5*3=15

overall, you're stuck with 15 hours in school

In German  relationship is Verhältnis.

Do you mean this:

$${\frac{{\mathtt{9.6}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{6}}}}{\left({\mathtt{1.2}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{2}}}\right)}} = {\mathtt{80\,000}}$$

9,6*10^6 : 1,2*10^2 = 8*10^4 : 1

Gruß radix !

I agree MG. This was a good question, thanks Civonamzuk.

And Alan has given a great answer.  Thanks Alan

yea

your english is a whole lot better than my brother's horrible handwriting and sloppyness

i can barely read it

awwww thx guys. :)

it means a lot to me to be here and to know that not every one in the world is horrible

I like being beautiful and smart (as well as athletic)

Your English is just fine Dbg :)

We can all understand you perfectly and that is the whole point of any language!

hey don't worry so much time saying you have bad english

your english is amazing. i can totally understand and read

there's no reason to say sorry

  ROF  LOL     .....     ROF  LOL

That is hilarious Chris.  I've only just seen it, I have been out almost all day.  

You have outdone yourself - how are you going to top this one next time  ?  

Cool question, both Anon and Alan are right.

I would've answered it like anon because i don't know how to get that image up.

How do you? It would make the answer more clear.

Your goal is to get x all alone.

Even i had trouble and still do with these equations, but every time you get rid of something you have to think of the consequences that's why you should take away the small things so that the equations is closer to x and its less complicated.

In the coding, i have shown what i added or took away.

Look at that and speak to me after if you're still having trouble answering it.

When i added 9x if instead +2x i would have gotten a negative but it's still right and i still would have gotten an answer.

$$\begin{array}{rrl}
33-2x&=&5-9x\qquad(- 5)\\
28-2x&=&-9x\qquad(+2x)\\
28&=&-7x\qquad(28\div(-7)=-4)\\
x&=&-4\\
\end{array}$$

Also correct!

$$\begin{array}{rrlll}33-2x&=&5-9x\qquad&(- 5)\\
28-2x&=&-9x\qquad&(+9x)\\
28+7x&=&0\qquad&(which\;means)\\
28&=&-7x\qquad&(28\div-7=4)\\
x&=&-4\\
\end{array}$$

The Ancient Romans used to encourage their students to cheat.

There were big penalties if they were caught.  

The punishment was for getting caught - not for cheating.

That's what I heard anyway.  :/

Hi Heather, Happy Birthday!

It appears you are very intelligent and beautiful!

Hello Dbg like radix said your english is great!

Hallo Dbg4thebest,

your English is not bad !! I can understand you.

Gruß radix !

10 minutes : 2.4 miles

Multiply both sides by 6 to get the distance per hour.

60 minutes (1 hour) : 14.4 miles

14.4 miles/hour

Danke schon, radix!!!!!!!

Ich bin spiele die " GAME " du " said  me "

.

Use the constant acceleration, kinematic equation s = ut +(1/2)at² where u = initial velocity, t = time taken, s = distance and a = acceleration.

Rearrange to get:  a = 2(s  - ut)/t²

a = 2(850 - 54.5*4.22)/4.22² m/s²

$${\mathtt{a}} = {\frac{{\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{850}}{\mathtt{\,-\,}}{\mathtt{54.5}}{\mathtt{\,\times\,}}{\mathtt{4.22}}\right)}{{{\mathtt{4.22}}}^{{\mathtt{2}}}}} \Rightarrow {\mathtt{a}} = {\mathtt{69.631\: \!185\: \!283\: \!349\: \!430\: \!6}}$$

acceleration ≈ 69.63 m/s²

.

Yes. If you square, say, -3, you have (-3)^2 = 9

However, you need to be careful.  If you write -3^2 (without brackets around the -3), then the exponent takes priority and you have -(3^2) = -9

. 

Better with 3.Binom :

$$\left({\mathtt{7}}{\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{3}}}}\right){\mathtt{\,\times\,}}\left({\mathtt{7}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{3}}}}\right) = {\mathtt{49}}{\mathtt{\,-\,}}{\mathtt{16}}{\mathtt{\,\times\,}}{\mathtt{3}} = {\mathtt{1}}$$

$${\sqrt{{\mathtt{1}}}} = {\mathtt{1}}$$

radix !

$${\sqrt{{\mathtt{7}}{\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{3}}}}}} = {\mathtt{0.267\: \!949\: \!192\: \!431\: \!122\: \!7}}$$

$${\sqrt{{\mathtt{7}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{3}}}}}} = {\mathtt{3.732\: \!050\: \!807\: \!568\: \!877\: \!3}}$$

$${\mathtt{0.267\: \!949\: \!192\: \!431\: \!122\: \!7}}{\mathtt{\,\times\,}}{\mathtt{3.732\: \!050\: \!807\: \!568\: \!877\: \!3}} = {\mathtt{1}}$$

You are right !!

Yeah, Melody....I like the way you presented that answer, too........it makes a lot of sense........and this problem doesn't seem as daunting as presented......

Remember.....a watched pot never boils.....but an unwatched clock leads to math problems........!!!!!