All Answers 358150 Answers

$${\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{4}}}^{{\mathtt{2}}}\right)}^{\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)} = {{\mathtt{17}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)}$$

honestly you  know what...i dont even wnat a glance of that dark side...becoz if it comes,...and i have a super cool mind...this site will explode...yea..you see....heat cold...and BOOM.......we all have dark sides....some of us rarely show them....and thats good....i dont want to show any one my "bad" side either....becoz when i get anrgy....i really dont see to whom my words are sticking to.....so i kinda avoid it.....

okay, well thats cuz you havent gotten a taste of my dark side, but i guess of we subtract me minus my dark side, can still qualify as a good girl

yea, well thx about the supportive friend part.

I am sorry MG I know you tried really hard but you have messed up right from the beginning.  

I will start you off.

$$\\34\frac{1}{8}\times \frac{14}{51}\div 1\frac{15}{34}\\\\
$None of the fraction parts can be simplified so you firstly need to change all the mixed numerals to improper fractions.$\\\\
\frac{8*34+1}{8}\times \frac{14}{51}\div \frac{34*1+15}{34}\\\\
$now simplify what you have got$\\\\
*\\\\
$now invert the last fraction and change the divide to a time$\\\\
$Now you are up to cancelling BUT don't cancel yet$$$

Don't cancel yet.  Get it right up to here first!   Then tell me what you want to cancel.

Don't tell me in the LaTex.  Tell me underneath in normal text.

Good luck  

@@ End of Day Wrap   Sat 30/5/15   Sydney, Australia Time   11:36pm     ♪ ♫

Good evening/day/morning     

Today our great answers were supplied by DarkBlaze347, DragonLance, CPhill, Thejamesmachine, MathsGod1, Heureka, Alan, asinus, MathsGod1 Civonamzuk and Josh4444.  Thank you  

My "odd socks" could have made it to Australia......they've been known to "walk on water"

As Alan pointed out, you did not s***w it up!  If I was here I would not  have even attempted it.

I would have  been doing something more relevant to me like looking for your odd socks.  Do you think that they could have made it to Australia.  There have been some big tides lately :/

Yes you could have been designing the next genaration of Marsian rockets.  

OR

Cleaning out your sock drawer.     LOL

Melody......what are you gonna' title this one in the Puzzles Thread???....."Another One That Chris Screwed Up "   ????....... LOL!!!!!

Yep, Alan....it's just that ....if I had seen that up front.....I could have had 15 more minutes in my life devoted to some other pursuit.....LOL!!!!

$$\frac{y^2*9}{5}=\frac{9y^2}{5}$$

There is nothing else that you can do with it  

YES absolutely  !!

We should note that Chris's expansion is still correct.  It's just that the resulting grand sum evaluates to zero!

.

Great thinking anon, are you the same anon that posted the question ??

I love this trick question  !!!

I just added it into the puzzles sticky thread :))

hi Josh4444,

That is not quite right.  

it is not 9000 at all because the nine is not in the thousands column, it is in the tenths column.

The number is

One hundred and thirty point nine four seven one.

I shall give you 3 points for your genuine attempt  

Yes, "sum" was a very bad word to use there! 

I will use the cancelling technique, and I will give this question all I've got!

(PS: I enjoyed the popcorn, I will send you some Unpopped kernels from England - it probably won't be as tasty as the popcorn in Austrailian )

$$\\34\frac{1}{8}\times\frac{14}{51}\div1\frac{15}{34}\\\\
34\frac{1}{8}\times\frac{14}{51}\\\\
=\;34\frac{1}{8\div2}\times\frac{14\div2}{51}\\\\
=\;34\frac{1}{4}\times\frac{7}{51}\\\\
=\;\frac{34*4+1}{4}\times\frac{7}{51}\\\\
=\;\frac{137}{4}\times\frac{7}{51}\\\\
=\;\frac{137*7}{4*51}\\\\$$

$$\\=\;\frac{959}{204}\\\\
=\;\frac{959}{204}\div1\frac{15}{34}\\\\
=\;\frac{959}{204}\times1\frac{34}{15}\\\\
=\;\frac{959}{204\div34}\times1\frac{34\div34}{15}\\\\
=\;\frac{959}{6}\times1\frac{1}{15}\\\\
=\;\frac{959}{6\div3}\times1\frac{1}{15\div3}\\\\
=\;\frac{959}{2}\times1\frac{1}{5}\\\\$$

$$\\=\;\frac{959}{2}\times\frac{1*5+1}{5}\\\\
=\;\frac{959}{2}\times\frac{6}{5}\\\\
=\;\frac{959}{2\div2}\times\frac{6\div2}{5}\\\\
=\;\frac{959}{1}\times\frac{3}{5}\\\\
=\;959\times\frac{3}{5}\\\\
=\;\frac{2877}{5}$$

I gave it everything.

I got an answer in the end.

I'm not sure if I made any mistakes.

But, again with the code i messed up, i wrote this before but when I copied and pasted (just to be quicker with fractions) but I forgot that I copied the code before, then the code doubled, and everything went in between and I had to start again.

CALC.

Umm...How do I do it on the calc again?

I've been using Latex so much I almost forgot how to do a fraction and it was just /.

When you're doing mixed numbers, how do you do it wihout mixing the number with the fraction.

\\34\frac{1}{8}\times\frac{14}{51}\div1\frac{15}{34}\\\\
34\frac{1}{8}\times\frac{14}{51}\\\\
=\;34\frac{1}{8\div2}\times\frac{14\div2}{51}\\\\
=\;34\frac{1}{4}\times\frac{7}{51}\\\\
=\;\frac{34*4+1}{4}\times\frac{7}{51}\\\\
=\;\frac{137}{4}\times\frac{7}{51}\\\\
=\;\frac{137*7}{4*51}\\\\
=\;\frac{959}{204}\\\\
=\;\frac{959}{204}\div1\frac{15}{34}\\\\
=\;\frac{959}{204}\times1\frac{34}{15}\\\\
=\;\frac{959}{204\div34}\times1\frac{34\div34}{15}\\\\
=\;\frac{959}{6}\times1\frac{1}{15}\\\\
=\;\frac{959}{6\div3}\times1\frac{1}{15\div3}\\\\
=\;\frac{959}{2}\times1\frac{1}{5}\\\\
=\;\frac{959}{2}\times1\frac{1*5+1}{5}\\\\
=\;\frac{959}{2}\times\frac{6}{5}\\\\
=\;\frac{959}{2\div2}\times\frac{6\div2}{5}\\\\
=\;\frac{959}{1}\times\frac{3}{5}\\\\
=\;959\times\frac{3}{5}\\\\
=\;\frac{2877}{5}

Thanks for that proof, Alan.....

Sun 31/5/15

If you would like to comment on other site issues please do so on the Lantern Thread.  Thank you.    

Interest Posts: 

FTJ means 'For the juniors' 

Excellent answer MG  :D

Yep, Anonymous.....I'm afraid you are correct....I had forgotten about that small detail!!!

NO    MathsGod1

$$\\2x=2\times x\\
$ and this is the same as$\\
x+x\\\\\\
$This is just like$\\
2\times 7=7+7$$

weight = mass * gravity and it is measured in Newtons.

When you get your 'weight' from the bathroom scales you are not really getting your weight at all, you are gettting an estimate of your mass!

Here this mathsis fun unit looks quite good :)

arc tan is the same as inverse tan.

It is labelled atan       

Mellie, you have asked quite a few of these now.  

Maybe this video will help you understand   

$$\\xy-7+9=12\\
xy+2=12\\
xy=10\\$$

This is the formula for a hyperbola.  It will be in the 1st and 3rd quadrants.