All Answers 358387 Answers

Replace Melody's 150 by 300 and see if that gives the same result as the answer sheet.  Personally, I like Melody's answer!

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Thank you melody! You know it was so hard to make this post! As I have made it with my phone! So hard to get the pics arranged!

Using f for Fred and j for Joe:

Fred initially had 240 boxes.

Edited to correct error!

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Um hi melody, but my mum checked the answer sheet and said its wrong..

Happy Independance Day Rosala :))

Melody beat me to it, and made a better assumption on pages!

The thickness of each page of a 300-page novel is 3/20 cm. If the 2 covers are each 7/8 cm thick, find the total thickness of the book.

Well it seems to me that a 300 page novel only realy has 150 peices of paper to it. 

odd pages on the front side and even pages on the back side.

So

$${\mathtt{150}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{3}}}{{\mathtt{20}}}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{7}}}{{\mathtt{8}}}}\right) = {\frac{{\mathtt{97}}}{{\mathtt{4}}}} = {\mathtt{24.25}}$$

24.25 cm   :   My goodness those pages are very think!

Just use the calculator on the Home page

Sólo tiene que utilizar la calculadora en la página de inicio 

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Is this meant to be

2^(x+1) + 5x^(x-2) = 104 or

2^(x+1) + 5(x^x) -2 = 104 or

(2^x) + 1 + 5(x^x) - 2 = 104 or what?

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Reply To Nauseated: I dont really give a **** if i lost anyways.

Reply To Rosala's First Comment: oh ****. The cavalry arrived, at least I can turn invisible and get out of here.

Reply To CPhill: That is not a new math identity, if there was, then David would seriously say triangles are sins, for they represent illuminati, which David hates

Reply To Rosala's 2nd Comment: Great idea, except just like pretty much almost every other girl, Heather also will break her teeth if she did that.

Besides, I've got my eyes on another girl, one who unlike the others, is not vulnerable to metal, and that's cuz she too is metal

Also, I would be excellent at Cinema Sins

It is not actually like that! Well it maybe! I don't hate jokes ! But when they hurt me or make me think about the useless past it makes me angry! Becoz I've already turned the page and deleted bad things! Another thing was , if dragon had taken the punch on himself and made a joke , I wouldn't mind but he took someone else so I mind, and I also don't mid when people turn my serious questions I to jokes, but the joke they make up is what I may be stuck up on! You can see my first reply was good , I took it lightly but do yoh know this got on me like a bacteria the whole day and my mood was spoiled , I don't know but it was the only poor joke DL has made since the day I met him ! 

And a a point to note , I don't have a boyfriend I never had a boyfriend and I will never have a boyfriend and that should be clear with everyone including me! Which I will somehow make it!

Nauseated how many times have you graduated ? Your English and knowledge is so good ! I feel so jealous of you! ( a bit) 

Tin you must eat almond or else you'll get into serious trouble ! At first you became so peaceful and acted like your a Buddhist followed and now you want to k**l 7up! Well you will never be able to k**l him! Be coz I've just decided to be a lawyer and also a medical science doctor and also a writer! WOoh! So much! So overall Ill protect him! 

And anyone you try your kiddy tricks on! When I think of you I think of a small kid who is having a finger gun and is shooting people! I mostly do that! And then I think of another cute mannered graceful girl wearing a . Rose gown and handing  you a rose and your mood changes into a nice one with a dropped jaw!

and btw where are you taking this! If a vampire tastes someone blood that down at mean it something kind of dating! I just wonder how "7up" being a human would Taste!well you have titanium in you and I can't eat metals so sorry I cant allow my teeth to break! Maybe heather can ! 

Hehe

The asymptotes will go through the center of the hyperbola, which is (-2,5).

The square roots of the denominators of the x-term and the y-term give the slope of the lines. Since slope is y-value over x-value, the slopes will be 9/11 and -9/11. 

The equations will be y - 5  =  ± (9/11)(x + 2).

When graphing, you draw the box; the asymptotes are the lines created by the opposite corners of the box.

The "set of all sets" would have to contain itself, along with all the other possible sets. 

For ease of writing, let's pretend that there are only three sets: X, Y, and Z.

Now the set of all sets is this set: {X, Y, Z}. Let's call this set S so that S = {X, Y, Z}.

But, S doesn't contain set S. Now the set of all sets is {S, X, Y, Z}.

Let's call this set T so that T = {S, X, Y, Z}.

But T doesn't contain set T. Etc. Etc. Etc. Do you see the problem? 

By graphing, I get an answer that is approximately 2.8.

I don't have an algebraic way of solving this problem.

The minimum amount of the loan could be $0.00; so, let's find the maximum amount of the loan.

Let  L  be the amount of the loan. We need to borrow L and 2% of L and $600.00; so, we need a total of  L + 0.02L + 600,  or  1.02L + 600.

1.02L + 600  ≤  120 000

          1.02L  ≤  119 400

                L  ≤  119 400 / 1.02

                L  ≤  117 058.82

I believe that you need more information; just knowing that the water content depends upon the width of the leaf is not sufficient; you need to know how (the mathematical amount) it depends.

You never know

We hate to see you go, jillybean....

Please visit when you can!!!!!

Sincerely, CPhill

The square footage that he needs to paint is given by:

2 [14 + 16] * 8 + (16* 14) - (7 * 6) =  662  sq ft

So 662/350  = about 1.9 gallons......but we can't buy "partial" cans.....so....we need 2 gallons = "A"

l x^2 - 4x - 5 l   = 7    we have two equations here......

The first is :

x^2 - 4x - 5  = 7    subtract 7 from both sides

x^2 - 4x - 12 = 0    factor

(x - 6) ( x + 2)  = 0      and, setting each linear factor  to  0   means that  x= 6 or x = -2

The second equation is :

-(x^2 - 4x  - 5)  = 7       multiply both sides by -1

x^2 - 4x - 5  = -7      add 7 to both sides

x^2 - 4x + 2  = 0     the solution to this is:

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{2}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{2}}}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{2}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{0.585\: \!786\: \!437\: \!626\: \!905}}\\
{\mathtt{x}} = {\mathtt{3.414\: \!213\: \!562\: \!373\: \!095}}\\
\end{array} \right\}$$

Thus...we have 4 values that make this true....

Let R be Sean's speed   and let R + 4 be Ian's speed  (both in km/hr)

Note that, when Ian meets Sean, he has run 6km and Sean has run 4km. And they each have run the same amount of time.......so we have

D/R = T   and

Ian's Time = Sean's Time....so...

6/(R + 4) =   4/R    cross-multiply

6R = 4(R + 4)

6R  = 4R + 16   

2R = 16

R = 8 km per hour...and this is Sean's rate

So, Sean runs the 10km in:   ..... 10km/(8km/hr)  = 5/4 hrs = 5/4(60m min)  =  75 min 

5/2^x-1=4/25

5/2^x-1= 5/2 ^-2

x-1=-2

x=1

Solve    | x²– 4x – 5 | = 7