There is no general analytical solution for quintic algebraic equations, but a Newton-Raphson numerical method can be used:

So s ≈ -1.253462

There are four other solutions as well, but these are all complex.

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If you mean in scientific notation this will be 10^9  (because 10^2/10^-7 = 10^(2- -7) = 10^(2+7) = 10^9)

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kilo = 1000, so divide by 1000

nano = 10^-9, so divide by 10^-9, or, equivalently, multiply by 10⁹.

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peta = 10¹⁵

femto = 10^-15

atto = 10^-18

so 10^-16 grams = 10^-31 petagrams = 0.1 femtograms = 100 attograms

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There is no single answer to this.  It depends on the expressions themselves, what type of numbers (e.g. rational, irrational), what tools you are using (e.g. by hand, using computer software, calculator) etc.

Do you have an example or two in mind?

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Yes, that's the right approach.  I got a slightly different numerical answer (13.37m), but that's primarily because I used more decimal places for t (3.4641 s).

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What a great answer Dragonlance.  ROFLOL

One lightyear is

9.4542549555E27 picometers

or

9,454,254,955.5 megameters

Distance to Alpha Centauri is

4.1126009056e+28 picometers

or

41,126,009,056 megameters

BTW Proxima Centauri is the cloest star to our sun. It is 4.2 light years.

1+1=x 

So, x=2

I never been bored. Mayby once when I was stuck in a closet. I know I never been bored on this site.

CPhill have you ever been bored?

hahaha

I know I keep forgeting. That is what happens when I do it wrong for 14 years.

Monday is my last day of summer school I get my scores for my writing. I sure I do ok even though I still need a lot of practice.

I am a lot better because of your help.

Eloise and 7UP help me too.

then your probably just bored....you thought that this forum wouldve been fun but after seeing the quiet atmosphere youve just backed off right?

all the grammar that i taught you...looks like it was useless -_-

thanks i know it...........btw,....i didnt like the joke!

The slope of the first line = 8 = the slope of the desired line....so we have

y-5 = 8(x - 0)

y = 8x + 5     and in Standard Form, we have

8x - 1y = -5

Ah.....thanks, Dragonlance.....I'll make the correction!!!!!

CPhill don’t you need to add the 1m above ground into the answer?

combin(31,7)=?

$$\small{
\begin{array}{rcl}
\dbinom{31}{7} &=&
\dfrac{31}{7}
\cdot \left( \dfrac{30}{6} \right)
\cdot \left( \dfrac{29}{5} \right)
\cdot \left( \dfrac{28}{4} \right)
\cdot \left( \dfrac{27}{3} \right)
\cdot \left( \dfrac{26}{2} \right)
\cdot \left( \dfrac{25}{1} \right)\\\\
\dbinom{31}{7} &=&
\dfrac{31}{7}
\cdot 5
\cdot \left( \dfrac{29}{5} \right)
\cdot 7
\cdot 9
\cdot 13
\cdot 25 \\\\
\dbinom{31}{7} &=&
31
\cdot 29
\cdot 9
\cdot 13
\cdot 25 \\\\
\mathbf{\dbinom{31}{7}} & \mathbf{=} & \mathbf{2~629~575}
\end{array}
}$$

23.8   = 23 + 8/10   = 23 + 4/5   =  119/5

I assume this is......  (1/8)w = 14

Multiply both sides by 8

w = 112

What is one one half as a decimal to the thousandths place?

                                it's   1.500                               

4√2 * 2√6   =

8√12  =

8*√4 *√3  =

8 *2 * √3 =

16√3

√[72 x^3)  =

√[36 *2] * √x^3  =

6√2  *  x√x  =

(6x) * √[2x]

Plot the point (0, 0) on the graph

Since the slope is -1/45, this means that when y changes by - 1, then x changes by 45...so.....

Plot the point (45, -1)  .......draw a line through both of these plotted points......voila !!!  ....there's the graph!!!