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there is 3 methods they are

-b+(or)-sqrt of b^2-4ac/2a

              or

fatrization method

              or 

elimination method

choose ur method which u feel gud

Given a 15% world wide web usage in 2005 , a 30 % world wide web usage in 2010 and a 40 % world wide web usage in 2014.., during what year would the entirety of earth become connected to the world wide web?

I am confused  

I don't think that it  will ever really get there.

The model would be logatithmic i guess with an asymptote at y=100%

What kind of model are you expected to use?

$$\\log x=y\\
then\\
x=10^y\\\\
eg\\
logx={17}\\
x=10^{17}$$

100-15=85

$${\mathtt{0.85}}{\mathtt{\,\times\,}}{\mathtt{84}} = {\frac{{\mathtt{357}}}{{\mathtt{5}}}} = {\mathtt{71.4}}$$

100+7=107

$${\mathtt{1.07}}{\mathtt{\,\times\,}}{\mathtt{71.4}} = {\mathtt{76.398}}$$

$76.40

Good answer, thanks 

OR

-4-3*7 = -4-21 = -25 degrees

no - But there is a divide by symbol which does the same job.  (Yes I know, it is a little more clumsy)     :)

This is not a grraphing question but you can just put the two coloured in dots on a number line.

I assume you gave that thumbs up which is really good but it is nice to say thank you to you answerers as well.  

Especially if you write a new post like you did.  

This is almost identical to the one I just did for you.

Just do the same thing and LEARN from it :))

need help x(x-3)=0

The letters stand for numbers.

The only way that 2 numbers can multiply together to give zero is if one or the other (or both) is zero.

Think about it - this is very important!

so

If     x*(x-3)=0

then either

x=0   or  x-3=0  

x=0   or     x=3  

how to graph the answer?

I finally found the formula to my question   Here it is 

(3+1/3)*(1+3/4)=

how to solve this (2x+3)(3x-7)=0

Multiply 2x *(3x - 7)=6x^2 -14x...........(1)

Do the same for 3* (3x -7)=9x -21........(2)

so you have: 6x^2 -14x +9x - 21..........(3)

So, 6x^2 -5x -21=0, so now you to factor this equation, which works out to be:

(2x + 3) * (3x - 7)=0

So x=-3/2 and  x=7/3

And there you have it. Good luck!.

What do I do when log x is equal to a number?

Well, it means you got the answer that you wanted!!!!.

"Log" is just another name for "exponent"

10^2. In this case 2 is the Log or Exponent of 10;

So, if we had 10^x=100. To find x, we take the log of both sides;

so, Log(10^x)=Log(100)

We isolate x Log 10=Log(100)

x * 1=2,  or x=2/1=2

I mean how to build the formula for (3 1/3)(1 3/4) on calcuator for the answer?

How do you type the formula on (3 1/3)(1 3/4)?

YOUR QUESTION IS NOT CLEAR. STATE IT CLEARLY SO WE CAN HELP YOU.

15% of a 84.00 dollar jacket plus 7% sales tax

From what I understand, you mean you will get 15% off the price of the Jacket plus 7% sales tax.

So $84 - 15%(or .15 x 84)=$71.40 + 7%=$76.40 the final price you pay.

50$ can get 500 coins. How much can 1000$ get you?

Well, for $50 you got 500 coins, so

500/50=10 coins per dollar;

Therefore $1000 would get you

1000 x 10=10,000 coins

Thank you very much for your help!  It is most appreciated and the equation finally made sense!

how would you solve 1= -1+a/16

put the numbers on one side. Remember that when you a number from one side to the other, the sign(+,-) changes. So,

1+1=a/16

2=a/16 remember this means: 2/1=a/16. Then you cross multiply

1 x a=2 x 16

a=32

What is 19 billion divided by 10.5 trillion?

19 billion=1.9 x 10^10

10.5 trillion=1.05 x 10^13

Divide the 1st. by the 2nd.

1.9 x10^10/1.05 x 10^13

=1.80952380952 x 10^-3

$${\frac{\left({\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{4}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{4.6}}\right)}{\left({\mathtt{8}}{\mathtt{\,-\,}}{\mathtt{4}}\right)}}{\mathtt{\,\times\,}}{\mathtt{67}} = {\frac{{\mathtt{4\,221}}}{{\mathtt{20}}}} = {\mathtt{211.05}}$$ or $${\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{4}}\right){\mathtt{\,\small\textbf+\,}}{\frac{\left({\mathtt{4.6}}\right)}{\left({\mathtt{8}}{\mathtt{\,-\,}}{\mathtt{4}}\right)}}{\mathtt{\,\times\,}}{\mathtt{67}} = {\frac{{\mathtt{1\,701}}}{{\mathtt{20}}}} = {\mathtt{85.05}}$$, possibly $${\frac{\left({\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{4}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{4.6}}\right)}{\left({\mathtt{8}}{\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{67}}\right)}} = {\mathtt{\,-\,}}{\frac{{\mathtt{63}}}{{\mathtt{1\,300}}}} = -{\mathtt{0.048\: \!461\: \!538\: \!461\: \!538\: \!5}}$$ or $${\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{4}}\right){\mathtt{\,\small\textbf+\,}}{\frac{\left({\mathtt{4.6}}\right)}{\left({\mathtt{8}}{\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{67}}\right)}} = {\mathtt{7.982\: \!307\: \!692\: \!307\: \!692\: \!3}}$$

$${\mathtt{123}}{\mathtt{\,\times\,}}{\mathtt{798}}{\mathtt{\,\small\textbf+\,}}{\mathtt{7}}{\mathtt{\,\times\,}}\left({\mathtt{9}}\right){\mathtt{\,-\,}}{\mathtt{8}}{\mathtt{\,\times\,}}\left({\mathtt{4}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{900}} = {\mathtt{99\,085}}$$

$${\mathtt{1.01}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{9}}}{\mathtt{\,\times\,}}{\mathtt{1.17}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{4}}} = {\mathtt{1.181\: \!7}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{10}}}$$