All Answers 358089 Answers

ALMOST ALWAYS!!!,

Your question doesn't make sense!!!!!.

Can't have an = sign on the right hand side. Please correct your equation.

X=10

yep

Melody-ROME, STAY OUT OF MY WRAP POST OR YOULL END IN THE SAME FATE AS ZEGEOES!!!!!

Me-I just had to be the first one to play around

Besides, where's the Lantern Thread? MELODY, GO TO YOUR ROOM UNTIL YOUVE LEARNED THE BENEFITS OF HAVING A LANTERN THREAD!!!

Hi Heureka,

It seems you are back with us again.

I am so pleased.    

Thanks Andre   

You've gone astray by putting an explicit negative sign in for 'a'.  Simpler to do the following:

. 

-3r = 9     divide both sides by -3

r = -3

I think you might want to know the number of rolls the photographer needs...so we have

438 / 24 = 18.25 rolls    ....but....since we can't purchase partial rolls, we need 19

This is known as "The Twin Prime Conjecture"......it is believed to be true, but hasn't been proved conclusively.......!!!

Here's more : https://en.wikipedia.org/wiki/Twin_prime

@@ End of Whatever Wrap   Thurs  3/9/15 Sydney, Australia Time 10:15pm   ♪ ♫

Hi everyone,

As many of you are aware the forum has had a very big overhaul.     

Let's see what is better:

* The Top User's list includes almost everyone, which is much liked by many people, I like it too. :)

* The table is better because it now has borders.  I think I was the only one who occasionally used it before.  I hope that it is better used now :)

* Security is better but this is causing some teething problems.  Some people are looked out.  I believe Radix and CPhill have expereinced this problem and Heureka is still locked out.  I expect Admin is working on this as I write.   

* There are a lot more features in the private message centre.

   I think they are the same features as available in the forum posts.

       * The stranger danger warning is well placed and I am pleased it has been added.

       * Pictures can now be uploaded into private messages which has bought smiles of approval.

There are also some other problems but Admin is working hard to overcome these. Thanks Mr. Massow. 

Please be patient and understanding    

----------------------------

Now for some personal news.

I will not be around much for the next month.  I am going to be overseas.  Nearly 3 weeks in Turkey, then 10 days in England.  I leave at around 8am in the morning :)

CPhill has told me he will do all he can to hold the fort while I am away. Thanks Chris, that is very much appreciated. 

I am sure Alan will work hard by your side.  Not to mention all our other wonderful regular answerers :)

I am sure I will make lots of cameo appearances.  I won't be able to stay way from this place for a whole month.

Anyway, learn lots, have fun and I will be back     

                            ♫♪  ♪ ♫                                ♬ ♬ MELODY ♬ ♬                       ♫♪  ♪ ♫ 

Look at the following, matsunnymat  :

To prove that AC divides the parallelogram into two equal parts.......note that, by the defintion of  parallelogram,  angle (ABC)  = angle (CDA) ......   and AD = BC and AB = DC

Therefore, by SAS, triangle CDA = triangle ABC.....and if two triangles are equal [congruent, in this case ], their areas are also equal

In general......the diagonals of a parallelogram are not equal [except for squares and rectangles ]

For example.....the diagonal drawn from D to B above has a length of about 8.25....but the diagonal drawn from A  to C   has a length of only about 2.82

(5/3)m / 1s   =  1.66 m/s

100m/55s = 1.818 m/s

It appears that he doesn't quite swim fast enough......

sqrt(72) + sqrt(800)  -  sqrt(18) =

sqrt (36 * 2)  + sqrt (16 * 25 * 2)  - sqrt(9 * 2)  =

6 sqrt (2) +  sqrt (16) * sqrt(25) * sqrt(2)  - 3 sqrt(2) =

6 sqrt(2)  +  (4 * 5 )sqrt (2)  -  3 sqrt (2)  =

8 sqrt (2) + 20 sqrt (2) - 3 sqrt (2) =

25 sqrt (2)

The onsite calculator gives cot(200) * cot(-70)   as 1

This isn't a quadratic equation unless you meant :

y=4x^2-7x+3

Also......what do you want us to do with this......graph it???  find the roots???

A. Let L be the skirt length.......then we have

L = abs (x + 20)

B.  The range of "x" is from  -2 to 2, inclusive

C. Assuming the same leg length, the designer will not use a 6 ft. model.....the skirt will be "short" by one inch  !!!!

Heureka....I have the same trouble with the computer at my local library...I tried everything I know to  let that computer accept "cookies"...still, no dice  !!!......my home computer works fine......this definitely needs to be fixed!!!

CPhill.......

Well if the trig problem has got an angle with 'pi' in it then it is fair to assume that the angle is in radians.

However, if the problem has a pie in it then it just means that someone in hungry.  

That is probably me, I'd love to have some apple pie with cream and ice cream right now.  

Nice answer Dragonlance  

(3.33 10-4 m) ✕ (3.25 10-5 m)

I expect that you mean

\((3.33* 10^{-4 }m) \times (3.25 *10^{-5} m)\\ 3.33*3.25*10^{-4 }*10^{-5} m*m\\ 3.33*3.25*10^{-4 }*10^{-5} m*m\\ 10.8225*10^{-4 -5}\;m^2\\ 1.08225*10^1*10^{-9}\;m^2\\ 1.08225*10^{-8}\;m^2\\ \)

Mmm, Not quite guest   

Remember that with order of operation you have to do powers before you multiply   :)

It is not (3rs)^4

it is 3rs^4  which means 3r(s^4)

it cannot be simplified.

It is not anything except an expression :)

10t^2+5t=5t^2+11t+8

\(10t^2+5t=5t^2+11t+8\\ 10t^2-5t^2+5t-11t-8=0\\ 5t^2-6t-8=0\\ \)

Now you could use the quadratic formula but I am going to factorise it.

I need 2 numbers that multiply to give 5*-8=-40   and add to give -6

-10 and +4 work

change -6t into  -10t+4t

\(5t^2-10t+4t-8=0\\ 5t(t-2)+4(t-2)=0\\ (5t+4)(t-2)=0\\ 5t+4=0 \qquad or \qquad t-2=0\\ 5t=-4 \qquad or \qquad t=2\\ t=-\frac{4}{5} \qquad or \qquad t=2\\ \)