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2/3(m+17) = -41

m = -157/2

PUT YOUR QUESTION IN A FORM OF EQUATION EXACTLY AS IT IS WRITTEN,

2x-8=-10   add 8 to both sides

2x = -2     divide both sides by 2

x = -1

So

3x + 9 =

3(-1) + 9  =

-3 + 9  =

6

 -22+-8z=-78

-78 + 22=8z

-56=8z

z=-56/8

z=-7

-22+-8z=-78     add 22 to each side

-8z  = -56     divide both sides by -8

z  = 7

Absolute value bars

YOUR QUESTION IS INCOMPLETE!.

4[-2(4-t)+3t]   simplify

4[-8 + 2t + 3t ]  =

4[-8 + 5t ]  =

-32 + 20t

Solve for t:
4 (5 t-8) = 0
Divide both sides by a constant to simplify the equation.
Divide both sides of 4 (5 t-8) = 0 by 4:
(4 (5 t-8))/4 = 0/4
Any nonzero number divided by itself is one.
4/4 = 1:
5 t-8 = 0/4
Any number times zero is zero.
0/4 = 0:
5 t-8 = 0
Isolate terms with t to the left hand side.
Add 8 to both sides:
5 t+(8-8) = 8
Look for two terms that sum to zero.
8-8 = 0:
5 t = 8
Divide both sides by a constant to simplify the equation.
Divide both sides of 5 t = 8 by 5:
(5 t)/5 = 8/5
Any nonzero number divided by itself is one.
5/5 = 1:
Answer: | 
| t = 8/5

It can be re-written like this:

b+2 x^2 Q(x)+5 x Q(x)-12 Q(x)

Derivative:(d)/(dx)(b+(x+4) (2 x-3) Q(x)) = (2 x^2+5 x-12) Q'(x)+(4 x+5) Q(x)

lim(n->∞) ((n^2)+n)^(1/2) - n

THERE IS A MISMATCH IN YOUR BRACKETS. PLEASE WRITE IT DOWN CORRECTLY.

What figures???

0.6105Exp1.687

Your answer is:.434962406..........etc.

3^(3/5)  = 3^(.6)  = about 1.933

who r u talking 2

-0.6x^2+3x+4  = 8      subtract 8 from both sides

-0.6x^2+3x-4 = 0     multiply both sides by -10/6

x^2 - 5x + 20/3 = 0    multiply both sides by 3

3x^2 - 15x + 20 = 0     this has no real solutions

[ The solutions are  [ 15 plus/minus(sqrt 15) i ]  / 6

what grade are you in?

wow nice 

5-38/6.3463+68 = about 67.01

The equation of the plane containing the line y = 2 - x and the point (1, 0, 1) is

z = 2 - x - y, and this will be the equation of the upper boundary surface, (the top limit for z).

The bottom limit for z is the plane z = 0.

For the area in the xy plane, the upper boundary is the line y = 2 - x, and the lower boundary y = 0.

The limits on x are x = 1 and x = 2.

Assuming there is no air drag then distance = (1/2)*9.8*4^2 m = 78.4 m  where acceleration of gravity is taken to be 9.8 m/s^2).

Mr. CPhill, I have a proposition for you. If you are interested, please email me at jo7bello@yahoo.it <-- yahoo.it, not yahoo.com. Thanks. 

8 /(2/5)  =

8 x (5/2)  =  40/2  = 20

If sin(theta)  = - .7

Then csc(theta)  = -1/.7