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You can these 3 numbers: 5 + 11 +13=29 or

2 + 3 + 5 +19=29, or, 5 + 7 +17=29 and so on.

\(a = 0.5 b h\)

divide both sides by \(0.5 h\)

\(\dfrac {a}{0.5 h} = b\\ b=\dfrac {2a}{h}\)

thanks man, I was wondering that but I didn't wanna look stupid if it was wrong xD

you just grind the numbers through and at the end you have a number that is in units km/hr.

\(\dfrac {22560000000 \times 0.00000012km}{ 24.5 hr}=110.498~ km/hr\)

to live it

That formula is the volume of a sphere: Just multiply,

4/3(3.14159)(4.7in)^3=

4/3(3.14159)*4.7*4.7*4.7

(4*3.14159)/3 *(103.823)

12.56636/3 * (103.823)

4.1888 * 103.823

=434.8937824 cubic units- which is your answer.

60- the answer is 60

+56

   30

+  -6

------------

3 turns to a 2 and 0 turns in to 10 

then 10 -6 = 4

and the 2 comes down

answer is 24

Can you explain sir cphil what happen to 60°?

144 ?

I'll do the first one for you:

x = t^2 + 5t + 2

v = Limit_dt→0 (x_t+dt - x_t)/dt             I'll use dt instead of writing out deltat all the time.

so

Put t+dt into the expression for x to get the x_t+dt part

v = Limit_dt→0  ([t+dt]^2 + 5[t+dt] + 2 - t^2 - 5t - 2])/dt 

Expand the terms in brackets

v = Limit_dt→0  (t^2 + 2tdt + dt^2 + 5t + 5dt + 2 - t^2 - 5t - 2])/dt 

Subtract terms where appropriate

v = Limit_dt→0  (2tdt + dt^2 + 5dt])/dt 

Divide numerator by dt

v = Limit_dt→0  (2t + dt + 5] 

Let dt go to zero and you are left with:

v = 2t + 5 

See if you can apply a similar approach with the others.

Because then I would have to find everyone and my memory is horrible.. 

-Matt

Sorry, Matt....I don't remember......why don't you just create a new account???

-3+-4+0+5+10+14+19+19+16+-1=75

75/12=6.25

1,001

Difficult.

(-1)3 – (|-5| + 23)   =

-3 - 5 + 23  =

15

lol no. he has 1 apple left

Just divide 35/28=1 1/4, so that we have:

28:35 = 1: 1 1/4

12t² - 4t² = 8t²   

Thank you, :-)

We can set this up as an exponential equation in this form :

y = ab^x   ......where y is  the attack strength, a is .7 , b is to be determined and x is the damage

And we're given :

2.5 = .7b¹⁹⁰    divide both sides by .7

2.5/.7 = b¹⁹⁰    take the log of both sides

log(2.5/.7) = log b¹⁹⁰   and we can write this as

log(2.5/.7)  = 190 logb   divide both sides by 190

log(2.5/.7)/ 190  = log b

And this says that  b = 10^[log(2.5/.7)/190]  = about 1.0067

And we can solve this :

3 = .7(1.0067)^x    where x is the damage we're looking for.......divide both sides by .7

3/.7  = 1.0067^x        take the log of both sides

log(3/.7)  = log 1.0067^x    and we can write

log (3/ .7)  = x log 1.0067      divide both sides by log1.0067

log (3 / .7)  / log( 1.0067) =  x  =  about  217.93  = 218  [rounded]