All Answers 358154 Answers

(1/2)⁴  = 1/16

What are we solving for ???

Drop the decimals....we'll go back and add them at the end...so we have

   1886

x     87

----------

  13202

15088

----------

164082.  

We moved the decimals a total of 3  places to the right in the original problem....so....we need to move them back to the left  a total of 3 places in the answer  = 164.082

is you stupid

3/5 = .6     so   5 + 3/5 =  5 + .6  = 5.6

0.0008  =  8/10,000  = 1/1250   or 8 x 10^-4 in scientific notation

1200ft/3min = 400 ft / min

One equation, two unknowns.....we will have an  ifinite number of integer solutions [even though they may be difficult to identify......!!!!  ]

v= [df - di ] /  [ tf - ti ]   multiply both sides by  [tf - ti]

v[tf - ti]  = [df - di]    simplify the left side

vtf - vti = [ df - di]      add vti to both sides, subtract [df - di] from both sides

vtf - [df - di ]   = vti   

vtf - df + di  = vti     divide both sides by v

[ vtf - dfi + di] / v  = ti

6x-3

you have two coefficients, 6 and 3.

the greatest common factor of 6 and 3 is 3

so you can rewrite

(6x-3) as 3(2x-1)

\(boxers = 4\times cspaniels\\ boxers+cspaniels=30\\ 4\times cspaniels + cspaniels = 30\\ 5\times cspaniels = 30\\ cspaniels = \dfrac {30}{5}=6 \\ boxers = 4\times 6 = 24\)

18-r=42     add r to both sides and subtract 42 from both sides

-24 = r

1 1/7 to 1 1/2 yd^3

The day advances one day for each non-leap year  and two days for each leap year

There are 14 Valentine's Days that occur between 2006 and 2020

There are 3 leap years in this period 2008, 2012 and 2016, and 11 non-leap years

So the number of days that advance  = 3(2) + 11(1)  = 17 days

So....Valentine's Day will fall on Friday in 2020

You can check this here :   http://www.apples4theteacher.com/holidays/valentines-day/when-is-valentines-day.html

\(slope=\dfrac{y_1-y_0}{x_1-x_0}\\ slope=\dfrac{-8-5}{6-(-2))}=\dfrac{-13}{8}\)

\(midpt=\left(\dfrac{x_0+x_1}{2},\dfrac{y_0+y_1}{2}\right)\\ midpt=\left(\dfrac{-2+6}{2},\dfrac{5+-8}{2}\right)=(2,-3/2)\)

\(dist = \sqrt{(x_1-x_0)^2 + (y_1-y_0)^2}\\ dist= \sqrt{(6--2)^2 + (-8-5)^2}\\ dist=\sqrt{8^2+(-13)^2}=\sqrt{64+169}=\sqrt{233}\)

12 year olds be like...

to elaborate on CPhil's answer.  Consider the sum of the first N odd numbers

\(s=\displaystyle{\sum_{k=1}^N}(2k-1) \\ s = 2 \displaystyle{\sum_{k=1}^N}k -\displaystyle{\sum_{k=1}^N}1\\ s=2\dfrac{N(N+1)}{2}-N\\ s=N^2+N-N=N^2\)

A recipe for sabayon calls for 2 egg yolks, 3 tablespoons of sugar, and ¼ cup of white wine. After cracking the eggs, you start measuring the sugar, but accidentally put in 4 tablespoons of sugar. How can you compensate?

Note that we put  in 4/3 more sugar than we wanted, because 3(4/3) = 4

So we need to increase eveything else by 4/3

So 2(4/3)  = 8/3  = 2 +2/3 egg yolk    and      (1/4)(4/3) =4/12 = 1/3 cup of wine

gtfo

twennyone

hey you'r a modder, right? Just a suggestion, a lot of people prefer fractions, soeither add those or make it easier to access

there are two ways to do this

20% of 2400 is

\(r=\dfrac{20}{100} 2400 = \dfrac{2400}{5}=480\)

we are taking this off of 2400 so

\(remaining = 2400-r = 2400-480 = 1920\)

or we could do it by noting that if we remove 20% we are leaving (100-20)=80%

\(remaining = 2400 \dfrac {100-20}{100}=2400 \dfrac{80}{100}=24\times 80=1920\)

3n - 3  =

3(n -1)    so 3 is the GCF