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109 is the correct number for the sum.

\(109 \bmod{10} = 9\\ 10-9 = 1\\ D[13] = 7 \neq 1\\ \mbox{So this is not a valid ISBN}\)

16+x-11=18-5  simplify

x + 5  = 13     subtract 5 from both sides

x = 8

I haven't got a lot of experience in trigonometry but...

Cosine=Cos

Cos = The adjacent side / hypotenuse

Well , the GDP per capita of Sweden is  435/9.5       = 45.79 billion/million people

                                               China         5739/1347 = 4.26 billion/million people

The ratio of the two is

Sweden/China   =   45.79/4.26  =  10.75    the GDP per capita is 10.75 times the GDP of China

E_p = mgh   divide both sides by gh

E_p / gh = m

Note something:

1 = 1

1 + 3 = 4

1 + 3 + 5 = 9

1 + 3 + 4 + 9 = 16

So.....the sum of the first N odd numbers = N^2

So   57^2 = 3249

yep

1/2 cup = 8 TBSP

2 lemons yield 4 TBSP

So, 4 lemons yield 8 TBSP

And 4 lemons cost $2

help him pls

(1 +1/2)x + (1 + 1/2)x +  6y =

3x + 6y

No, it's an Internet meme.

9 + 10 = 19

5/699 * 34 =      170/699

Find a unit rate: Joel ran 1500 meters in 4 minutes, 45 seconds

4min 45sec =  285 sec....so

1500m / 285sec = about 5.25m/s

if you didnt know why comment shes not asking for your opinion shes asking for an answer ...and the answer is 48 teaspoons in 1 cup so multiply 15 to 48 and that should be the answer

sqrt(81) = 9

How are we supposed to know without knowing how big/how many teaspoons of sugar a cup can contain?

6912

9+10=19 

you need to subtract 3 from both sides and then divde by 5x

solving for x

it equals -1.75

\(2x-5y=-12\\ x-3y=-7\)

using the 2nd equation

\(x = 3y - 7\)

plugging this into the first equation

\(2(3y-7) - 5y = -12\\ 6y - 14 -5y = -12 \\ y -14 = -12 \\ y=2\)

plugging this into our equation for x we get

\(x = 3(2)-7=6-7=-1\)

As a check

 \(2(-1)-5(2)=-2-10 = -12 \\ (-1)-3(2) = -1 - 6 = -7\)

no

9+10=19

\(12.08 = 12 + \dfrac {8}{100} \\ \mbox{so } 12.08 \Rightarrow 12\dfrac {8}{100}= 12\dfrac {2}{25}\)

density = mass/volume

\(Density = \dfrac{454 g}{2270 cm^3}=0.2 \dfrac {g}{cm^3}\)