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If your triangle is a right-angle triangle, then if one angle is 45 degrees, that MEANS that the unknown angle must be 45 degrees. And if your given base is 8, it also MEANS that the unknown side must be 8!!. If it is non-right angle triangle, then you must have one of the following conditions:

1-Two sides and an angle opposite one of the known sides

2-Two angles and any side

3-Two sides and their included angle

4-All three sides

A=r^2*pi=21^2*pi=1385,44

-5/12 - (-9/3)=-5/12+9/3=-5/12+36/12=31/12=2 7/12

Yes, any number divided by 1 stays the same.

Also guest you have your permutation and combinations muddled up.

If the letters all must be different then

If order doesn't matter then the answer will be smaller and you use C  (for combinations)      

If order does matter then the answer will be bigger and you use P  (for permutations)

If you swap your answers around then they will be correct.   :)

Hallo guest

There are 26 choices for each of the 5 positions so it will be

26*26*26*26*26   = 26^5       = 11 881 376        = 1.1881376 * 10^7

This isn't quite what you're after but I suspect it can be simply modified to look for the max weight path vs. the longest path.

http://www.geeksforgeeks.org/find-longest-path-directed-acyclic-graph/

\(m = \dfrac{y_1-y_0}{x_1-x_0}=\dfrac{-6 - (-4)}{7-4}=\dfrac{-2}{3}=-\dfrac 2 3\)

\(\dfrac {a}{b} = a \times \dfrac {1}{b}\)

\(\dfrac {2}{9} \div \dfrac {3}{8} = \dfrac {2}{9} \times \dfrac {8}{3} =\dfrac{16}{27}\)

\(\mbox{The maximum volume of the box that is underwater is }11^3 cm^3 = 1331 cm^3\)

\(\mbox{Water weighs }1 \dfrac {g}{{cc}^3}\mbox{ so the maximum weight the box can displace is } 1331 g\)

\(\mbox{The sand has density }3.5 \dfrac {g}{{cc}^3}\)

\(\mbox{and thus a volume of }\dfrac {1331g}{3.5g/cc^3}=380.3 cc^3 \mbox{ of sand will sink the box.}\)

Solve for x:
x^2-18 x+80 = 0

The left hand side factors into a product with two terms:
(x-10) (x-8) = 0

Split into two equations:
x-10 = 0 or x-8 = 0

Add 10 to both sides:
x = 10 or x-8 = 0

Add 8 to both sides:
Answer: | 
| x = 10 or x = 8

Hallo Justin

If repeats are allowed then you have 5^26=1.49 X 10^18

If the order of the letters doesn't matter, then nPr(26,5)=7,893,600

If the order of the letters matter, then, nCr(26,5)=65,780

1234567890*infinity

The volume of a cube is 15.625cm3 what is the length of its edge

(15.625)^1/3=2.5cm

It's 247 dumbass. You're on a calculator website.

40=-4(10+x)

40=-40-4x  |+40

80=-4x   |:(-4)

  x=-20

carefully

Your question doesn't make sense! If you mean to say "How big is a 1,000 compared to 10^-6", the answer would be 1 billion(10^9).

Let x be one side, then x + 2 and x + 4 are the other 2 sides:

x + x + 2 + x + 4=24

3x=18

x=6 the shortest side, 6+2=8 and 6+4=10

So the sides of the triangle are: 6,8,10

What is 3 billion divided by 43 thousands

(3 X 10^9) / 43,000=69,767.44

    f–143< - 73=f<70