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Good one Rom    hahaha        

https://www.youtube.com/watch?v=XVSRm80WzZk

\(\mbox{If }x=2 \mbox{ is a root of }x^3-7x+6 \mbox{ then } (x-2) \mbox{ divides } x^3-7x+6\)

\(x^3-7x+6 = x^2(x-2) + (2x^2-7x+6) \\ (2x^2-7x+6)=2x(x-2) +(-3x + 6) \\ (-3x+6) = -3(x-2) \\ x^3-7x+6 = (x-2)(x^2+2x-3)\)

\(\mbox{To find the rest of the zeros we have to factor }x^2+2x-3 \\ \mbox{and this is easily done resulting in } \\ x^2+2x-3 = (x+3)(x-1) \\ \mbox{and thus the other zeros are } x=-3, x=1\)

decrease 6000 by 7%

1- 7% means 7/100=.07 X 6,000=420 This is 7% of 6,000. Now we subtract it from 6,000

6,000 - 420=5,580

2- Since 7%=.07, that means 1 - .07=.93 of the number is left. So we multiply this number by 6,000

.93 X 6,000=5,580.

If something is decreased by 7%, it must just be 93% of what it was....so....

93% of 6000  =

.93 x 6000 =

5580

9t^2 x 3t x 2t^4

Simplify the following:
9×3×2 t^2 t t^4

9 t^2×3 t×2 t^4 = 9 t^(2+1+4)×3×2:
9×3×2 t^(2+1+4)

2+1+4 = 7:
9×3×2 t^7

9×3  =  27:
27×2 t^7

27×2  =  54:
Answer: | 
| 54 t^7

sin59x19=0.8571 X 19=16.2849. I assumed that your x meant "Times".

Well, obviously it is rational, why? Because it is expressed as a RATIO of two numbers. Whether it is + or - doesn't matter. That is where the words "rational" and "irrational" come from. From the word "RATIO".
 

derivative of y = (3x)^2

=y'(x) = 18x

derivative of y = 3x^2?

y'(x) = 6x

(3x)^2  =9x^2    and the derivative of this = 18x

3x^2   .....and the derivative of this = 6x

Rom has given the slope of the radial line in the first quadrant.......if, however, you wanted the slope of the tangent line to the circle when y = 3.144, we have :

  -sqrt(7^2 - 3.144^2) / 3.144 =  -1.9892 

Why do people keep asking this question? Knock it off already.

\(x^2 + y^2 = r^2 \\ x = \sqrt{r^2 - y^2} \\ m = \dfrac y x \\ m = \dfrac y{ \sqrt{r^2 - y^2} } \\ m = \dfrac {3.144}{\sqrt{7^2 - (3.144)^2}} =0.503\)

2.75=2 3/4

How about subtracting 97 from both sides? Try it and see what you get.

TWENTY ONE!!!

you would subtract 97 from both sides

You cannot add (or subtract) matrices of different dimensions.....!!!

We can multiply different dimensions when the number of columns of the first matrix = the  number of rows of the second.......  the resulting matrix dimensions  = [ the number of rows of the  first matrix by the number of columns of the second.....]

For instance

[3 x 2]  [ 2 x 3 ]     .....the resulting matrix will be 3 x 3

You don't.  You can only add matrices that have the same dimensions.