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Mass of 12 Golf b***s=12 X .046=.552 Kg. Therefore,

1 - .552=.448 Kg. the mass of soccer ball

Thank you so much Melody, I was having trouble with it because I wasn't sure how to find the value of c.

18ab2 – 4ac2 – 10ac  If a= 3 and b=1

\(18ab^2 – 4ac^2 – 10ac\qquad If \qquad a= 3 \;\;and \;\;b=1\\ 18*3*1^2 – 4*3c^2 – 10*3c\\ 54 – 12c^2 – 30c\\ – 12c^2 – 30c+54\\\)

That is all you can do unless you know the value of c      

the correct answer is .514

(14.08-2.003) x 1.2 / 6.3-2.01

I'm using the forum calc to check the answer :)

(14.08-2.003) x 1.2 / 6.3-2.01 = 0.2903809523809523809523809523809523809523809523809524

Or......15/5, or 18/6, or 24/8, or  l 3 l, or......eh, nevermind.......

.

Doesn't matter....I apparently can't multiply correctly, anyway.....LOL!!!!!

Huh?  Why don't you change it back to a mixed numeral Chris ?

maybe t=6/2

21 1/3 times 11 1/3 times 3 5/8..........let's convert these to improper fractions, first

21 + 1/3  =  64/3

11 + 1/3  =  32/3

3 + 5/8   =   29/8   ....and we have....

(64 / 3) * (34 / 3)  * ( 29/8)     multiply the numerators together and the denominators together

63,104 / 72      divide by 2

31,552 / 36     again

15,776 / 18     again

7888 / 9

And that's all we can do.....

Simplify the following:
(21+1/3) (11+1/3) (3+5/8)

Put 3+5/8 over the common denominator 8. 3+5/8  =  (8×3)/8+5/8:
(21+1/3) (11+1/3) (8×3)/8+5/8

8×3  =  24:
(21+1/3) (11+1/3) (24/8+5/8)

24/8+5/8  =  (24+5)/8:
(21+1/3) (11+1/3) (24+5)/8

24+5 = 29:
(21+1/3) (11+1/3)×29/8

Put 11+1/3 over the common denominator 3. 11+1/3  =  (3×11)/3+1/3:
((21+1/3) (3×11)/3+1/3 29)/(8)

3×11  =  33:
((21+1/3) (33/3+1/3)×29)/(8)

33/3+1/3  =  (33+1)/3:
((21+1/3) (33+1)/3×29)/(8)

33+1 = 34:
((21+1/3)×34/3×29)/(8)

Put 21+1/3 over the common denominator 3. 21+1/3  =  (3×21)/3+1/3:
((3×21)/3+1/3 34×29)/(3×8)

3×21  =  63:
((63/3+1/3)×34×29)/(3×8)

63/3+1/3  =  (63+1)/3:
((63+1)/3×34×29)/(3×8)

63+1 = 64:
64/3×34/3×29/8

64/3×34/3×29/8 = (64×34×29)/(3×3×8):
(64×34×29)/(3×3×8)

64/8 = (8×8)/8 = 8:
(8×34×29)/(3×3)

3×3  =  9:
(8×34×29)/9

8×34  =  272:
(272×29)/9

| 2 | 7 | 2
× |  | 2 | 9
2 | 4 | 4 | 8
5 | 4 | 4 | 0
7 | 8 | 8 | 8:
Answer: | 
| 7888/9=876 4/9

What is the value  of  "c".....????

No :)

I am Australian,

CPhill (Chris) is from the US

Alan is from the United Kingdom

and

Radix is from Germany.

There are actually 5 seperate sites here, English, German, French, Spanish and Russian.

There is a gateway into the other forums at the bottom of most pages.  You will be automaticallly logged out but you can log back in again.  Why don't you take a look :))

The message system, and the Top Users board  is the same in each forum so it is not unusual for me to get messasges in other languages and they do not necessarily realize that I only speak English.     

 g(x)=-5- (7/2)x and f(x)= (-2/7)x-10/7

If f(g) = g(f)  = x.....they are inverses....so

f(g)  = (-2/7) [-5 - 7/2)x] - 10/7  =   10/7 + x - 10/7 = x

And

g(f)  = -5 - (7/2) [ (-2/7)x - 10/7]  = -5 + x + 5  = x

They are inverse functions.........!!!

That is excellent forensic maths Chris :))  5 points from me :))

-5 (6+-5)-2   simplify inside the parentheses, first

-5( 1)  - 2    perform the multiplication

-5  - 2  =

-7

Snce we have one equation and two unknowns, there isn't a single solution.......G and S could take on many values.......

Solve for a:
a^2 = 4 a+117

Subtract 4 a+117 from both sides:
a^2-4 a-117 = 0

The left hand side factors into a product with two terms:
(a-13) (a+9) = 0

Split into two equations:
a-13 = 0 or a+9 = 0

Add 13 to both sides:
a = 13 or a+9 = 0

Subtract 9 from both sides:
Answer: | 
| a = 13                or a = -9

You can only simplify this, this is the equation of a line and doesnt have 1 single answer

(-64)^2/3

Simplify the following:
(-64)^2/3

|  | 6 | 4
× |  | 6 | 4
| 2 | 5 | 6
3 | 8 | 4 | 0
4 | 0 | 9 | 6:
Answer: | 
| 4096/3

Look at the gradients(\(M\)) for both lines

Line 1 gradient = -4 = \(M_1\)

Line 2 gradient = 1 / 4 = \(M_2\)

Definition for a perpendicular line is when the gradient(\(M\)) satisfies:

\(\frac{-1}{M_1}\) is perpendicular to \(M_2\)

Solve for x:
x^2/4+(5 x)/4+1 = 0

The left hand side factors into a product with three terms:
1/4 (x+1) (x+4) = 0

Multiply both sides by 4:
(x+1) (x+4) = 0

Split into two equations:
x+1 = 0 or x+4 = 0

Subtract 1 from both sides:
x = -1 or x+4 = 0

Subtract 4 from both sides:
Answer: | 
| x = -1                  or x = -4

remember that \(e^{ln(x)}=x\)

Therefore just raise e by each side of the equation to get rid of the log terms

Edit:

Also a rule that will help you simplify -> \(e^{a+b}=e^ae^b\)

To: The questioner;

Is this the "Hildebrand solubility parameter"?