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Because you are already given the log of x as being 3 to base 10, it follows that x=10^3=1000. Therefore, the answer is "B".

We need the problem to help you, first. And i'm quite sure some of us can help you. So your answer is yes.

There is SOMEone here who can !

Well, there's  two different ways to answer it here, pick your preference.

The base 10 log of a number is the exponent of 10 that will result in that number

log x    =      3        means   10^3 = x

x = 1000              

Because you cannot divide anything by zero. It is phisically impossible to find a way to divide something by zero because zero goes into every numder infinite and no times.

Julie is driving to her mother's house and has already traveled 24.6 miles. if Julie has traveled 30% of the total distance, then what is the total distance Julie will travel to get to her mother's house?

Let the total distance=D, then

.30D=24.6 divide both sides by .30

D=24.6/.30

D=82 miles being the total distance.

24.6 miles = 30% of the trip

And you want 100% of the trip

So take 10/3 ( 100% divided by 30%) and multiply it by you current miles.

Answer is 82.

what is the answer to: There are two consecutive positive integers such that the square of the larger number is 73 more than 8 times the smaller number. and how do you solve.

Let the first number be=N, then we have,

N+1=the second number, but we have,

(N+1)^2=8N+73, therefore the two numbers are

N=12 and 12+1=13

Solve for N:
(N+1)^2 = 8 N+73

Subtract 8 N+73 from both sides:
-73-8 N+(N+1)^2 = 0

Expand out terms of the left hand side:
N^2-6 N-72 = 0

The left hand side factors into a product with two terms:
(N-12) (N+6) = 0

Split into two equations:
N-12 = 0 or N+6 = 0

Add 12 to both sides:
N = 12 or N+6 = 0

Subtract 6 from both sides:
Answer: | N = 12                      or N = -6 we discard this

I was always taught rise over run where rise is how far the graph goes up and run is how far it travels.

Now that im thinking about it, it may be wrong. CPhill will correct me.

Sorry for any errors

log10(x)=3

You can write this as 10^3=x

Because logarithms find exponets, you can interchange between these to forms

LOGe(x)=i is the same as e^i=x

Whole numbers?

1-239,2-238,3-237,4-236, etc

Decimal?

There are literally infinite possibilities

1- sin^2theta/ csc^2thea-1

This is the question that you asked. - it is probably not be the question that you intended.

Perhaps you should introduce some brackets.  

\(1- \frac{sin^2\theta}{csc^2\theta}-1= \frac{-sin^2\theta}{csc^2\theta}=-sin^4\theta \)

32 is the geometric mean of 16 and what other number?

Since the geometric mean is the nth root of the product of a geometric sequence of n terms, therefore:

32^2 / 16=64 the other term, because:

sqrt(64 X 16)=32

Simplify the following:
(3/2 x+1) ((3 x)/(2)-1)-((3 x)/(2)-1)^2

Put each term in (3 x)/(2)-1 over the common denominator 2: (3 x)/(2)-1  =  (3 x)/2-2/2:
(3 x)/2-2/2 (3/2 x+1)-((3 x)/(2)-1)^2

(3 x)/2-2/2 = (3 x-2)/2:
(3 x-2)/2 (3/2 x+1)-((3 x)/(2)-1)^2

Put each term in 3/2 x+1 over the common denominator 2: 3/2 x+1  =  (3 x)/2+2/2:
((3 x)/2+2/2 (3 x-2))/(2)-((3 x)/(2)-1)^2

(3 x)/2+2/2 = (3 x+2)/2:
((3 x+2)/2 (3 x-2))/(2)-((3 x)/(2)-1)^2

Put each term in (3 x)/(2)-1 over the common denominator 2: (3 x)/(2)-1  =  (3 x)/2-2/2:
((3 x+2) (3 x-2))/(2×2)-(3 x)/2-2/2^2

(3 x)/2-2/2 = (3 x-2)/2:
((3 x+2) (3 x-2))/(2×2)-(3 x-2)/2^2

Multiply each exponent in (3 x-2)/2 by 2:
((3 x+2) (3 x-2))/(2×2)-((3 x-2)^2)/(2^2)

2^2 = 4:
((3 x+2) (3 x-2))/(2×2)-(3 x-2)^2/4

Combine powers. ((3 x+2) (3 x-2))/(2×2) = 2^(-(1+1)) (3 x-2) (3 x+2):
((3 x-2) (3 x+2))/2^(1+1)-(3 x-2)^2/4

1+1 = 2:
((3 x-2) (3 x+2))/2^2-(3 x-2)^2/4

((3 x-2) (3 x+2))/2^2-(3 x-2)^2/4 = ((3 x-2) (3 x+2)-(3 x-2)^2)/4:
((3 x-2) (3 x+2)-(3 x-2)^2)/4

(3 x-2) (3 x+2) = (3 x) (3 x) + (3 x) (2) + (-2) (3 x) + (-2) (2) = 9 x^2+6 x-6 x-4 = 9 x^2-4:
(9 x^2-4-(3 x-2)^2)/4

(3 x-2) (3 x-2) = (3 x) (3 x) + (3 x) (-2) + (-2) (3 x) + (-2) (-2) = 9 x^2-6 x-6 x+4 = 9 x^2-12 x+4:
(-9 x^2-12 x+4+9 x^2-4)/4

-(9 x^2-12 x+4) = -9 x^2+12 x-4:
(-9 x^2+12 x-4+9 x^2-4)/4

Grouping like terms, 9 x^2-9 x^2+12 x-4-4 = 12 x+(-4-4)+(9 x^2-9 x^2):
(12 x+(-4-4)+(9 x^2-9 x^2))/4

9 x^2-9 x^2 = 0:
(12 x+(-4-4))/4

-4-4 = -8:
(12 x+-8)/4

Factor 4 out of 12 x-8:
4 (3 x-2)/4

(4 (3 x-2))/4 = 4/4×(3 x-2) = 3 x-2:
Answer: | 3x - 2
 

In 5 minutes, the plane travels 450/12 = 37.5 miles

And we can use the sine to calculate this

sin13 = a / 37.5      where a is the gain in altitude.........rearrange

37.5(sin13) =  a  = about 8.4  miles

im confsed & i thnk its wrong :( sigh.

A contract valued at $27,500 requires payments of $6000 every six months. The first payment is due in four years and interest is at 11% compounded semi-annually.

(a)How many payments are required?

(b)What is the size of the last payment?

(c) How much will be paid in total?

(d) how much of what is paid is interest?

Any help with steps would be greatly appreciated. Thanks

Since the 1st.payment is not due for 4 years, then we have to find the FV of the $27,500 at the given rate of 11% S.A., which comes to=$42,203.88. Now this loan has to be paid in $6,000 S.A. payments.

a-9.14 payments are required.

b-The size of the last payment will be =$6,440.29P + $354.22 Int.=$6,794.51.

c-$6,000 X 8 + $6,794.51=$54,794.51 Total payments.

d-54,794.51 - $42,203.88=$12,590.63 Total interest paid.

The formulae used here are:FV=PV[1 + R]^N=FV OF $27,500 TODAY. and,

PMT=PV. R.{[1 + R]^N/ [1 + R]^N - 1}=PMT NEEDED TO PAY OFF A LOAN OF $42,203.88,

Where R=Interest rate per period, N=number of periods, P=periodic payment. PV=Present value, FV=Future value.

We can use a proportion to solve this

196ft  x (1/3)in / 1ft   =  about 65.3333   inches

12 / .90  = 

12 / [90 / 100]  =

12 *  100  / 90

1200/90  =   13.3333......girls   ?????

Ther are infinite possibilities......200  +  40  is one

a-The size of periodic payment=$177.96

b-Interest for 1st, period=$80.00

c-Principal repaid for 2st.period=$97.96

d-Balance for the 1st.period=$7,902.04

Here is the formula you use to calculate this, if you wish to check it:

PMT=PV. R.{[1 + R]^N/ [1 + R]^N - 1}=PMT NEEDED TO PAY OFF A LOAN OF $8,000

Where R=Interest rate per period, N=number of periods, P=periodic payment. PV=Present value, FV=Future value.

AMORTIZATION: Since the interest rate is 1% per month, then you just multiply: 1% or .01 x $8,000=$80.00, which is the interest for the 1st. month. Then subtract it from the monthly payment of $177.96 - $80=$97.96 which is principal to be subtracted from the loan of $8,000 - $97.96=$7,902.04.

-4.5114690885881435x10⁶⁵

96cars / 24 trucks       =   4/1      or  4:1