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Here's another way just by directly factoring....

-3x^4 + 27x^2 + 1200 = 0   multiply through by -1

3x^4 - 27x^2  - 1200  = 0     divide everything by 3

x^4 - 9x^2 - 400  = 0

(x^2  - 25) (x^2 + 16)  = 0      

(x - 5) (x + 5) (x^2 + 16)  =  0        setting the first two factors to 0 we get the two "real" solutions of 5 and - 5

Setting  x^2  +  16  = 0

x^2   = -16        take the square root of both sdes

x  = plus/minus [4 i ]        and these are the two complex [non-real] solutions

Step by step!!

420 x 69 x 21

First, Do 420*69

28980..

Then do 28980 * 21..

You're answer will be...

608580

:)

16=-2/3(-12)+b

16-b=8

-b=-8

b=8

printed area = 50 = xy 
paper size, P(x) 
= (x + 2*2)(y + 2*4) 
=(x + 4)(y + 8) 
= xy + 4y + 8x + 32 
= 8x + 4(50/x) + (50 + 32) 
= 8x + 200/x + 82 

P'(x) = 8 - 200/x^2 = 0 
x = √(200/8) = 5 (for x > 0) 

answer : paper dimension = 9 x 18

:)

Have a wonderful day!!

Solve for x:
-(3 x^4)+27 x^2+1200 = 0

Substitute y = x^2:
-3 y^2+27 y+1200 = 0

The left hand side factors into a product with three terms:
-3 (y-25) (y+16) = 0

Divide both sides by -3:
(y-25) (y+16) = 0

Split into two equations:
y-25 = 0 or y+16 = 0

Add 25 to both sides:
y = 25 or y+16 = 0

Substitute back for y = x^2:
x^2 = 25 or y+16 = 0

Take the square root of both sides:
x = 5 or x = -5 or y+16 = 0

Subtract 16 from both sides:
x = 5 or x = -5 or y = -16

Substitute back for y = x^2:
x = 5 or x = -5 or x^2 = -16

Take the square root of both sides:
Answer: | x = 5    or x = -5    or x = 4i    or x = -4i
 

Let's expand upon Hayley's answer [it is correct  !!!]

[x - (4 - i)][x - (4 + i)] = 0

x^2 - x (4 - i) - x (4 + i) +  [4 - i] [ 4 + i]  =

x^2 - 4x + ix - 4x - ix  + 16 -4i + 4i - i^2  =

x^2 - 8x + 16  + 1  =

x^2 - 8x + 17

Its 19

(6x-5) its self is a polynomial

You would caterogize it as a quadratic binomial

Zero because you cannot divide anything by zero, even zero

This is because Zero will go into whatever specified number infinite and no times.

Example:

 0 will go into 12 infinite times, and also none because 0 x Infinity is still zero

1st RULE OF DODGEBALL......ALWAYS PROTECT YOUR FACE.......

2nd RULE OF DODGEBALL.....NEVER TURN TOWARDS ANYONE WHO CALLS YOUR NAME......!!!!!  THEY ARE USUALLY THE "ENEMY"

Is that right?

Indeed you did, you had answered before i had even clicked on the question

The quadratic expression x2 - 2x + 15 can be factored to give x2 - 2x - 15 = (x - 5)(x + 3). Thus the quadratic equation x2 - 2x + 15 = 0 has roots x = 5 and x = -3. You can perform this from the end to the beginning.

One quadratic equation with roots 5 and -3 is (x - 5)(x + 3) = 0. Expanding this gives x2 - 2x + 15 = 0.

What I am saying is a quadratic equation with roots a and b is (x - a)(x - b) = 0. This fact is true, even ifa and b are complex numbers. Hence one quadratic equation with roots 4 - i and 4 + i is

[x - (4 - i)][x - (4 + i)] = 0.

Expand the left side.

When you are finished you can use the quadratic formula to verify that 4 - i and 4 + 1i are roots.

Man, I typed fast!!

This is just the graph of a straight line.......here it is..... https://www.desmos.com/calculator/zuyn869bdc

You're not funny at all... I know what you're trying to do.

I hear it's for like.. Very advanced people!!

I haven't even gotten there yet

Phill!! :(

Dodgeball  in the face  =   S - P - L  - A  - T       !!!!!!!!

Nahh, it's 18, My friend!

That's some interesting math!

bahaha!

That's funny!

-_-

My school is super strict. Like, getting demerits for being in the halls.

L * W = 192

3W * W   = 192

3W^2   = 192

W^2  = 64

W = 8  cm

And the length  =  3(8)  = 24 cm

So.....the perimeter  =  2 [ L + W]   = 2 [ 24  + 8]   =  2 [32]   = 64  cm