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How the h**l do yo solve that?

Huhhhhhh? I get why you've been confused lol😀😜😀😜😀😜

       -Victoria 

BTW it is 4

ROFL!!!!!!😜😀😜😀😜😀😜😀 that is awesome

     -Victoria 

LOL! I'm dying!

1+1=2

I would not take my word for it though off my years of education I would have to take a safe guess that the answer it 3... again, I'm in highschool and am not sure if  they taught us this yet so I might not be right.

Just google it under "Logs in Math".

3/12 + 1/12 - 11/12 = 4/12 - 11/12 = -7/12

We want to know where the sin = 1/2......

This occurs at   30°  +  n* 360°     and at   150° + n*360°    where n is  an integer

Here is a graph which confirms this........https://www.desmos.com/calculator/03z7sxndpl

Because it's a bananana :D

3/10 : 5 = 3/10 * 1/5 = 3/50

-5×2x = -5×2×x = -10x

thanks

Note that

13 / 6   =   2.16666666667

So   .....any  ratio  =   [13 * n ] / [ 6 * n]   will work   [where n is an integer  > 0 ]

For example, if n = 4

[52] / [24]  = 2.16666666667

How would you write the second half of this word problem on a calculator? "The new van was bought for $24000. It decreased in value by 20% in the first year. if its value at the end of the second year was $1612, by which percentage did its value decrease during the second year?" The first answer is $19200, thank you very much

$24,000 - 20%=$19,200 its value after the 1st.year, which is a 20% depreciation.

$19,200 - $1,612=$17,588-The amount it depreciated by at the end of 2nd year. It, therefore depreciated in the second year by: 1 - ($1,612/$19,200)=91.60%. The van, however, depreciated by a whopping:1 - ($1,612/$24,000)=93.28% over the 2-year period. The average,per year, compound depreciation over the two years is=74.08%.

I could very well be wrong, but my guess is

\(26*26*26*26*5*4*3 = 26^4*5!/2!\)

Please explain if I am wrong

Oops sorry Melody \(x=9y\)

Also can I have a proof?

THIS IS HOW YOU GET -2

Simplify the following:
2×(-3)^2+5 (-(-5)-3^2)

3^2 = 9:
2×(-3)^2+5 (-(-5)-9)

-(-5)  =  5:
2×(-3)^2+5 (5-9)

(-3)^2 = 9:
2×9+5 (5-9)

-9+5 = -4:
2×9+5×-4

2×9  =  18:
18+5 (-4)

5 (-4)  =  -20:
18+-20

18-20  =  -(20-18):
-(20-18)

| 1 | 10
| 2 | 0
- | 1 | 8
| 0 | 2:
Answer: | -2
 

 6. What is the equivalent value, twelve months from now, of the cash available to fund the expansion? Show your calculations.

    7. Twelve months from now, what is the total of the value of the required cash payments? Show your calculations.
   8. Twelve months from now, what is the difference between the value of the funds available from (6), and the total present value of the required payments determined in (7)?  Show your calculations.
   9.  What is the accumulated value of this difference at the end of the expansion period? Show your calculations

ANSWERS:

6. =$2,737,859.32- This is the FV of $2,600,000 one year from now. Use this formula to get this:

FV=PV[1 + R]^N=FV OF $1 TODAY.

7.Since the PV of all the cash payments inculding the 10% increase in the last payment is=$2,579,689.61. Twelve months from now, it will be worth=$2,697,081.61. Use the exact same formula above.

8. $2,737,859.32 - $2,697,081.61=$40,777.71

9. The accumulated value of this difference will be=$52,797.30. Use the exact same formula above.

Using the secant inverse, we have

asec (3)  = x = about 70.53°

This angle could also lie in the 4th quadrant, i.e., about 289.47°

Sorry, Haley......I couldn't find anything online........you might try your local library???

-12x-3= -51      add 3 to both sides

-12x  = -48       divide both sides by -12

x = 4

Here's the function

C(h)   =  90h + 200   where C is the total cost for h hours of work

For 4 hours, we have

C(4)  = 90(4) + 220   =   360 + 220   =   $580