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Similar to the question below this one....see it there

Example:

7/8      Look at the space ABOVE the calculator and enter  '7'  then the division symbol then '8'....it should display as a fraction above the calculator  

18 /  pi/6   =   18  x  6/pi  = 108/pi  = 34.37747

OK., so that doesn't work.

Back to the drawing board.

-Bertie

0.1882845188284519

9/5  /  1/5   =  9/5  x  5/1  =  9/5  x 5 = 9

Pie is usually found in the bakery department.

Pi is in the top row of keys just to the right of the ' 2nd' key

Can you restate the question?.....it makes no sense the way it is currently written.

Guest #1 assumed the time was for ONE year, but the problem does not state the time period !   HOW MANY YEARS??

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Alpha + beta = 270 , cos alpha + sin beta = 0

\(\small{ \begin{array}{rcll} \alpha + \beta &=& 270 \\ \beta &=& 270 - \alpha \\\\ \cos{(\alpha)} + \sin{(\beta)} &=& \cos{(\alpha)} +\sin{(270 - \alpha)} \\ && \sin{(270 - \alpha)} = \sin{(270 )}\cos{(\alpha)} + \cos{(270 )}\sin{(\alpha)} \\ &=& \cos{(\alpha)} +\sin{(270 )}\cos{(\alpha)} + \cos{(270 )}\sin{(\alpha)} \quad & | \quad \sin{(270 )} = -1 \qquad \cos{(270 )} = 0 \\ &=& \cos{(\alpha)} +(-1)\cdot \cos{(\alpha)} + 0\cdot \sin{(\alpha)}\\ &=& \cos{(\alpha)} -\cdot \cos{(\alpha)} \\ &=& 0 \\ \cos{(\alpha)} + \sin{(\beta)} &=& 0 \end{array} }\)

Hmm?

write the next term in this sequence

-1 2 7 14 23...

\(\begin{array}{lrrrrrrrrrr} & {\color{red}d_0 = -1} && 2 && 7 && 14 && 23 && \cdots \\ \text{1. Difference } && {\color{red}d_1 = 3} && 5 && 7 && 9 && 11 && \cdots \\ \text{2. Difference } &&& {\color{red}d_2 = 2} && 2 && 2 && 2 && 2 && \cdots \\ \end{array}\)

\(\begin{array}{rcl} a_n &=& \binom{n-1}{0}\cdot {\color{red}d_0 } + \binom{n-1}{1}\cdot {\color{red}d_1 } + \binom{n-1}{2}\cdot {\color{red}d_2 }\\ a_n &=& \binom{n-1}{0}\cdot ({\color{red}-1 }) + \binom{n-1}{1}\cdot {\color{red}3} + \binom{n-1}{2}\cdot {\color{red}2}\\ \\ \hline \binom{n-1}{0} &=& 1 \\ \binom{n-1}{1} &=& n-1 \\ \binom{n-1}{2} &=& ( \frac{n-1}{2} ) \cdot ( \frac{n-2}{1} ) \\ \hline \\ a_n &=& ({\color{red}-1 }) + (n-1)\cdot {\color{red}3} + ( \frac{n-1}{2} ) \cdot ( \frac{n-2}{1} )\cdot {\color{red}2}\\ a_n &=& -1 + 3n - 3 + (n-1)(n-2) \\ a_n &=& -1 + 3n - 3 + n^2-2n-n+2 \\ \mathbf{a_n} &=& \mathbf{n^2-2} \\\\ a_6 &=& 6^2-2 = 34\\ a_7 &=& 7^2-2 = 47\\ a_8 &=& 8^2-2 = 62\\ \cdots \end{array}\)

Hayley who is on the photo is it you ?

:D :D

Good Evening! ( dracula's voice ) :)

i mixed not afternoon i mean evening :)

thanks heureka ! :)

in our country afternoon now

Good Good

Sine, Cosine and Tangent are the three main functions in trigonometry.

They are often shortened to sin, cos and tan.

To calculate them:

Divide the length of one side by another side 
... but which sides?

For a triangle with an angle θ, they are calculated this way:

Sine Function:

sin(θ) = Opposite / Hypotenuse

Cosine Function:

cos(θ) = Adjacent / Hypotenuse

Tangent Function:

tan(θ) = Opposite / Adjacent

Would you like me to give you more information? (:

haha, Nauseated got you. :)

Good Morning!! :)

we both wrong the answer is 3/5 because he asking from female i find it now :P

Outstanding, MathsGod!

 You are in an exclusive category, sometimes known as the nines. 

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Well, ColdPlay, that’s why he makes perfect scores –he double-checks his work.

If you did that then your comment would be written as:

Good for you. Did you really have to edit “yay” twice?

Or

Good for you; did you really have to edit “yay” twice?

Often, 90% of the energy is used for the last 10% of perfection.