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there is no joke the real answer really is 8

Solve for J: 8 = (2 log(1.58489×10^-12 J))/(3 log(10)) (2 log(1.58489×10^-12 J))/(3 log(10)) = (2 log(1.58489×10^-12 J))/(3 log(10)): 8 = (2 log(1.58489×10^-12 J))/(3 log(10)) 8 = (2 log(1.58489×10^-12 J))/(3 log(10)) is equivalent to (2 log(1.58489×10^-12 J))/(3 log(10)) = 8: (2 log(1.58489×10^-12 J))/(3 log(10)) = 8 Divide both sides by 2/(3 log(10)): log(1.58489×10^-12 J) = 12 log(10) 12 log(10) = log(10^12) = log(1000000000000): log(1.58489×10^-12 J) = log(1000000000000) Cancel logarithms by taking exp of both sides: 1.58489×10^-12 J = 1000000000000 Divide both sides by 1.58489×10^-12: Answer: | | J= 630957344480194367324160/10,000,000=63,095,734,448,019,436.7324160=6.31 X 10^16 Joules released in 8M earthquake. Since 1 Megaton H-bomb realses: 4.2 X 10^15 Joules, then an 8M earhquake will release:63/4.2=~15 Megatons of TNT equivalent 

OH! I get the joke. But the answer is actually 0,

Sorry, misread it

LOL rarinstraw!

Sorry for these sporadic posts, I just keep remebering things at times

0+0=0/0=8 get it

What do you mean? I am in 8th place in the top 10 in the leaderboard.

Here's the Venn diagram:

The total number of consumers = [ 455 + 311 + 131 + 385 + 203 + 463 + 76 + 133]  = 2157

The percent of consumers that shopped at more than one store  =

[385 + 311 + 203 + 463] / 2157 = about 63.1%

The percent of consumers that shopped exclusively at Nordstrom =

76 / 2157  = about 3.5%

Guest #5 is wrong because if you divide 0 by another 0, it is undefined, and since you add 0 to the other 0, it equals nothing, and 8 ISN'T A POSSIBLE answer.

It is negative infinity, or undefined.

Are you using a table or a calculator?

If you are using a TI-84+ calculator, press (2nd) (DISTR) and 2:normalcdf(

To find P(z<0.52), you can used normalcdf(-100,0.52) to get . 0.698.

To find P(z>-0.63), you can use normalcdf(-0.63,100) to get 0.736.

To find P(-0.31<z<1.345), you can use normalcdf(-0.31,1.345) to get 0.529.

(The answers are rounded.)

You needn't use -100 for the left-hand limit or 100 for the right-hand limit, but you should use numbers <-6 or >+6 for the limits.

doesn t it need to be:

P(.775<z<.975)=infinity ?

If I were a spelling bee judge, I would ask the contestant to spell "their". 100% of the time they will ask for me to say it in a sentence. The sentence I'll say? "They're building their house over there." :P

i agree with #5 guest he/she has a point

8=(2log(E/10^11.8))/3

I'm going to assume that exponet is on 10

24=2log(E/10^11.8)

3 moved over

12=log(E/10^11.8)

Lets that the inverse of log which is B^E=L where B is the base, E is what is equal to the log, and L is the log

10^12=e/10^11.8

10^12*10^11.8 = 630957344480194300000000

e=6.3095*10^23 joules of energy

Guest #5, you are wrong.

i didn t understood can you explain me ? :D

Good job SpawnofAngel! +5 points for you!

it would be 8 because you put one zero on top and the other below it but the division make two more but those two cancel each other out so it would be 8

You do not need to solve for the variables to the equation to solve it

Since it is something being subtracted from itself, the anwser is 0

Lool!

thats what I think about Prince Charming:)

It is simply 3 and 5/6

But you can trun the 3 into 18/6 and combine like terms 

23/6

I made many smile, but they don't pay attention to me.

P(z<.975) - P(z<.775)