Mean is another word for average

Somebody "nasty"!!!!!!

Let the the trail=T km

.875 X 3/7 X 2/3T=8

.25T=8 divide both sides by .25

T=8/.25=32 Km-the length of the trail.

The enrgy , e, in a given mass, m, is eqaual to the mass times the speed of light , c, squared.

You can see how a nuclear bomb, with only a little mass conversion to energy can make such a big BOOM!

Tourists were on a hiking trip for three days. On the first day, they hiked 1/8 of the trail. On the second day they hiked 4/7 of the remaining trail. On the third day they hiked 1/3 of the remaining trail and the last 8 km. How many km is the whole trail? 

Let x be the trail length

The first day they hiked (1/8)x

The second day they hiked :

(4/7) [ x - 1/8x]  =   (4/7) (7/8)x = (1/2)x

The third day they hiked :

(1/3) [ x - (1/8)x - (1/2)x] + 8  =  (1/3) (3/8)x + 8 =   (1/8)x + 8

So

(1/8)x + (1/2)x + (1/8)x + 8  = x     simplify

(3/4)x + 8 = x      subtract (3/4)x fro both sides

8  = (1/4)x      multiply both sides by 4

32  = x  =  32km  is the trail length

The little  x^y button right next to the '7' button

4*10^(5x)=200

10^(5x)=50

5x=log(50)

x=log(50)/5

The perimeter of the rhombus is 4*5  = 20 units

I'm assuming that the x in the triangle refers to the measure of one of the equal sides

So the perimeter of the triangle = x + x + x + 1  =   3x + 1

And we have this:

20  = 2[ 3x + 1]      divide both sides by 2

10  = 3x + 1            subtract 1 from both sides

9  = 3x            divide by 3 on both sides

3  = x

Proof  :  

20  =  2[3*3 + 1]

20  = 2[10]

20  = 20

2200/2 = 1100

4(10)^5x=200    divide both sides by 4

10^(5x)  = 50     take the log of each side

log 10^(5x)  = log50    and we can write

5x log10  = log 50          and log 10   = 1   so we can ignore ths.....and we have...

5x  = log50                  divide both sides by 5

x  = log 50/5 

And you are correct !!!

2^-14=2^-2x take the logs of both sides

-14=-2x

x=7

I think 1 of your 4 actually got answered.  And out of coutesy to the answerer I will not touch it BUT if I had seen these 4 identical questions almost in a row beforehand I would have deleted ALL of them.

Behave yourself and do not multiple post again !!@

Remember, Solveit.....it we're given the value of some trig function, we have to take the inverse to find what angle that function is referring to.

In this case, we know that the cosx = 0.788

So....to find out what x is, we need to take the cosine inverse to find the angle where the cosine is equal to 0.788.

Solve for x: e^5 x-11 = 17 Add 11 to both sides: e^5 x = 28 Divide both sides by e^5: Answer: | | x = 28/e^5=~0.1886625.........etc.

Add 11 to both sides to get    I assume you meant   e^(5x)   and NOT    e^5   *   x

e^5x = 28    Now take the ln of both sides

5x= 3.332

x=.66644

2.4 * 10^-9

Multiply both sides by sinx to get

1.33 sin x = sin 30       sin 30 = .5

sinx = .5/1.33     Inverse sine both sides

Arcsin x = x  = 22.08 degrees

(1.0/4.2)*(10^-15/10^-7)

= 1.0/4.2 * (10^-15)/10^-7 = 0.2380952380952381 * 10^-8 = 2.380952380952381 * 10^-9

 M = 0.15e^0.3t + 0.78

 3 = 0.15e^0.3t + 0.78

Solving for t using "natural logarithm", the answer is:

=8.982, which means the answer is closer to "A" NOT "B"

3.1415926535792►

I get a DIFFERENT answer

3 = .15e^(.3t) + .78   subtract .78 from both sides

2.22 = .15e^(.3t)       Divide both sides by .15

14.8= e^(.3t)             Take natural ln of both sides (ln....NOT LOG)

2.694627 = .3t          Divide both sides by  .3

8.982 = t

I am!!!!!!! Halftime, I can't wait!

3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679