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Suicide is the absolute worst problem solver by far. Why you ask? How many lives do you get? 1. How many times can you do suicide? 1. 1-1=0 After suicide, you have NO CONTROL on what happens from there on out. You may think that "It's gonna make everyone happy!" Guess what. IT'S NOT. EVERYONE WILL WEEP AND CRY AND FIGHT AND EVERYONE WILL BE MAD AT EACH OTHER. You don't want that, do you?

I feel the same way:/

BC, life is special, u r only given one, so, use it wisely:)

Hey make an account and text me.

y = 3 +2x + 3x^2   (1)     ..... at (1, 8)

The slope of the line at any point on the parabola is given by :

y '  =  2 + 6x

So....at (1,8)  the slope is

y'(1)  = 2 + 6(1)  = 8

And the line normal to this will have the slope  of -1/8   ....so......the equation of this line is

y = (-1/8)(x - 1) + 8

y = (-1/8)x + 65/8      (2)

So.....setting (1)  = (2)   we have

3 + 2x + 3x^2  = (-1/8)x + 65/8

24 + 16x + 24x^2  = -x + 65

24x^2 + 17x - 41 = 0       factor

(24x  + 41) (x -1) = 0

We already know that setting the second factor to 0  produces a correct answer

Setting the first factor to 0 produces

x = -41/24

And putting this into

y = (-1/8)x  + 65/8   produces  1601/192

So....the second point of intersection  is (-41/24, 1601/192)

Here's a graph :  https://www.desmos.com/calculator/sjnizqdyzq

Also, ur adopted doesn't make any difference..  U can still have a divorced parents...

That is amazing! I like that a lot...:)

Read

I'm sorry, I truly am...

And there r many possible reasons...

Solve for x: x^3-6 x^2-7 x+60 = 0                                                                                                          The left hand side factors into a product with three terms: (x-5) (x-4) (x+3) = 0 Split into three equations: x-5 = 0 or x-4 = 0 or x+3 = 0 Add 5 to both sides: x = 5 or x-4 = 0 or x+3 = 0 Add 4 to both sides: x = 5 or x = 4 or x+3 = 0 Subtract 3 from both sides: Answer: | | x = 5   or x = 4   or x = -3

your adopted

add them together

DID YOU CHECK THE FIRST TIME YOU POSTED THE SAME QUESTION? LOOK TOWARDS THE BOTTOM OF THIS PAGE.

Why don't try this fine graphing calculator and see if it will solve your problem:

https://www.desmos.com/calculator

what is 25 to the 1/2 power plus 25 to the -1/2 power

Simplify the following: sqrt(25)+1/sqrt(25):                                                                                            sqrt(25) = sqrt(5^2) = 5: 5+1/sqrt(25) 1/sqrt(25) = 1/sqrt(5^2) = 5^((-2)/2): 5+1/5 Put 5+1/5 over the common denominator 5. 5+1/5 = (5×5)/5+1/5: (5×5)/5+1/5 5×5 = 25: 25/5+1/5 25/5+1/5 = (25+1)/5: (25+1)/5 25+1 = 26: Answer: | | 26/5=5 1/5

Sin(27) / 11 = Sin(x) / 23 cross multiply

23*sin(27) =11*sin(x) take sin(27) on your calculator

23*.454 =11sin(x)

10.442 =11sin(x) divide both sides by 11

10.442/11 =sin(x)

0.94927 =sin(x)

Arcsin(.94927)=x

x=71.67 degrees

Thanks 

I think the first answer is what was wanted :)

Ur amazing Bree:) 

Maybe so.. But cuts and scars may hurt you but you are much more then just that.. Scars never go away but cuts can just need to stand strong !! 

That's nice Bree. I've had way too much happening lately. But some cuts are to deep to heal.

(ok jack spins a games spinner 6 times he hopes to get 3 two times is that teareticol or experimental) sorry bad at spelling lont words lol :) please help me and thank uo

What he hopes to get might be theoretical ..........

BUT what he does get is definitely experimental.

What is the value of k if x3 + kx2 + 7x + 5 is divided by x + 6 and gives a remainder of −1?

[ x^3 + kx^2 + 7x + 5] / [ x + 6] = -1

x=1   and   k= -20, or

x=2   and   k=-8.75, or

x=3   and   k= -6 8/9

Hi   Danielr_ddrp     

Welcome to the web2.0calc forum       

\(log_2(x+4)-\frac{1}{2}(log_2y)=2\\ log_2(x+4)-log_2(y)^{1/2}=2\\ log_2\frac{x+4}{(y)^{1/2}}=log_24\\ \frac{x+4}{(y)^{1/2}}=4\\ x+4=4(y)^{1/2}\\ x^2+8x+16=16y\\ 16y=x^2+8x+16\)

\(2log_2x-log_2(y-1)=1\\ log_2x^2-log_2(y-1)=log_22\\ log_2\frac{x^2}{y-1}=log_22\\ \frac{x^2}{y-1}=2\\ x^2=2(y-1)\\ x^2=2y-2\\ x^2+2=2y\\ 8(x^2+2)=8*2y\\ 16y=8x^2+16\\\)

SO

\(x^2+8x+16=8x^2+16\\ x^2+8x=8x^2\\ 7x^2-8x=0\\ x(7x-8)=0\\ x=0 \;\;or\;\; x=\frac{8}{7}\\ \)

Log 0 is undefined so x=0 is a nonsense answer.

\(If\;\;x=\frac{8}{7}\;\;\;then\\ 16y=8*\frac{64}{49}+16\\ y=\frac{81}{49}\;\;\;(or\;\;\;1\frac{32}{49})\\ so\;\;x=\frac{8}{7}\;\;\;and\;\; y=\frac{81}{49} \)

I have checked this answer by substituting the values into the original equation.

It is correct :)

Are they wired in parallel  ?    Series ?  Some othe combination???