Hi galeano,
I nearly missed this request for more help. Next time you would be best to copy the address and paste it into a private message for me :)
Then I will know that you want more help and I will be able to go straight to the question. :)
f(x)=x^2(x-3)
Ok, I didn't realize that you needed to graph it. :)
First it will cross the x-axis when f(x)=0
this will happen when x=0 and when x-3=0 which is when x=3
now because it is x^2, that means the graph will only just touch the axis at x=0 and then it will turn around and go back where it came from.
f(x)=x^3-3x^2+0
because it is x^3 the graph will have 3 directions and because it is +x^3 it will start up in the top right hand corner .
So I know a lot about what the graph will look like just by having a quick look.
The y intercept is 0
To know much more I would need to use calculus.
This is what the graph looks like.
https://www.desmos.com/calculator/despxw3pos