All Answers 358524 Answers

buna

Very nice explanation Heureka :)

Omg thank you so much, you made life so much easier 

I am the monster that lives under your bed; the fleeting shadow that you catch out of the corner of your eye. I am the hand that writes the handwriting on the wall; the voice you hear in the distance:  The one who says “yes” when everyone else says “no.”

what are you doing 

Change a term or sign so that the equation has the solution x=2 

2(x-3) = 1-(2x-5)

This is really important i'd appreciate the help very much 

Change a term or sign so that the equation has the solution x=2 

2(x-3) = 1-(2x-5)

This is really important i'd appreciate the help very much 

if \(x = 2\) we have:

\(\begin{array}{rcll} 2(x-3) &\ne& 1-(2x-5) \\ 2(2-3) &\ne& 1-(2\cdot 2-5)\\ 2(-1) &\ne& 1-(4-5)\\ 2(-1) &\ne& 1-(-1)\\ -2 &\ne& 1+1\\ -2 &\ne& 2\\ \end{array}\)

We must change the sign:

\(\begin{array}{rcll} {\color{red}-}2(x-3) &=& 1-(2x-5) \\ -2(2-3) &=& 1-(2\cdot 2-5)\\ -2(-1) &=& 1-(4-5)\\ -2(-1) &=& 1-(-1)\\ 2 &=& 1+1\\ 2 &=& 2\\ \end{array}\)

let alone 10 minutes

but where are you going ? 

What method did you use for your solution?

What are the coords of the endpoints of the other diagonal \(G(x_G,y_G) \)and \(H(x_H,y_H)\).

\(\begin{array}{rcll} \vec{E} &=& \binom{2}{3} \\ \vec{F} &=& \binom{0}{-3} \\\\ \vec{G} &=& \vec{F} + \frac12 \cdot ( \vec{E}-\vec{F} ) + \frac12 \cdot ( \vec{E}-\vec{F} )_\perp\\ \vec{H} &=& \vec{F} + \frac12 \cdot ( \vec{E}-\vec{F} ) - \frac12 \cdot ( \vec{E}-\vec{F} )_\perp\\\\ \end{array}\)

\(\begin{array}{lcll} \text{please note, if }~ \vec{a} = \binom{x_a}{y_a} ~\text{ then }~ \vec{a}_\perp = \binom{-y_a}{x_a}~\text{ or }~ \vec{a}_\perp = \binom{y_a}{-x_a} \\ \text{because }~ \vec{a} \cdot \vec{a}_\perp ~\text{ must be null, if be perpendicular to one another.}\\ \binom{x_a}{y_a} \cdot \binom{-y_a}{x_a} = -x_a\cdot y_a + x_a\cdot y_a = 0\\ \binom{x_a}{y_a} \cdot \binom{y_a}{-x_a} = x_a\cdot y_a - x_a\cdot y_a = 0\\ \end{array}\)

our formula is:

y=mx+b

y=-2x+16

m=-2    (slope)

b=16    (y-intercept)

Find the equation of the line that passes through the point (4, 4) and is perpendicular 

to the line 

y = -2x + 16

so the formula of perpendicular line is -1/m your slope is -2 perpendicular line s slope will be:

(-1)/(-2)=1/2

and we have m=1/2  and (4, 4) let s put it into y=mx+b:

4=(1/2)*4+b

b=2

So our equation is:

\(y=\frac{1}{2}x+2\)

Isn't everyone like that?

And yes, I would like a better answer, though that one was a rather good answer...

Hi galeano,

I nearly missed this request for more help.  Next time you would be best to copy the address and paste it into a private message for me :)

Then I will know that you want more help and I will be able to go straight to the question.  :)

f(x)=x^2(x-3)

Ok, I didn't realize that you needed to graph it.  :)

First it will cross the x-axis when f(x)=0

this will happen when x=0 and when x-3=0  which is when x=3

now because it is x^2, that means the graph will only just touch the axis at x=0 and then it will turn around and go back where it came from.

f(x)=x^3-3x^2+0

because it is x^3 the graph will have 3 directions and because it is +x^3  it will start up in the top right hand corner .

So I know a lot about what the graph will look like just by having a quick look.

The y intercept is 0 

To know much more I would need to use calculus.

This is what the graph looks like.

Hello:)

Heii ;))))))))

Are you a boy, or a girl?

Im sorry, I have to go. Maybe I will be able to talk to you later:)

este violetta

l have 17 for years

\(\sqrt[1]{x}=x^\frac{1}{1}=x\)

Okay:) how old are you?

l do not know how to make an account bun l do when l have time

Aye TR , thee hath learned thine new trade well.

Thine bread be the best in all the land  !!

Here be a royal plaque for thine bakery :)

By Order of Queen Guinevere.

Soverign of the Magical World of Camelot

you re beautiful

Can you make an account? That way it is easier for us to talk to each other, and I will know who you are...

Well I am one type of person when you are watching and another when you are not.

Want a better answer?