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to get area you times 14 * 14and you get 196 then times 196 by 196 

 it is 4

x - y = 5

-2x + y = -1

Add the two equations together:

x - 2x - y + y = 5 - 1

Simplify:

-x = 4  so x = -4

Put this value back into one of the first two equations and rearrange it to find y.

See the following reasoning:

$$The curve: $f(x)=4x-x^2$ has gradient $4-2x$\\

At the point $x=k$ the gradient is $4-2k$\\

The straight line that is tangent to the curve at $x=k$ therefore has the form $y=(4-2k)x+c$ where $c$ is the y-intercept.\\

At the tangent point the values of $y$ and $f(x=k)$ must be the same so $$(4-2k)k+c=4k-k^2$$

Rearranging this we find that, $c$, the y-intercept of the straight line is $$c=k^2$$$$

Probably for the same reason that Sam is a moose.

3(x-1)(2x+1) - (x-2)²  Multiply the first set of bracketed terms to get

3(2x² + x - 2x -1) - (x-2)²  = 3(2x² - x -1) - (x-2)^{2 =}  6x² - 3x -3 - (x-2)² Expand the second set of brackets to get

6x² - 3x -3 - (x²-4x+4) = 6x² - 3x -3 - x² + 4x - 4  Collect like terms to get

5x² +x -7

There are two prime factors of 46, namely 2 and 23.

g(-5) = -4*(-5)+6 = 26

f(g(-5)) = f(26) = -2*26 - 7 = -59

If you are referring to the calculator on this site, you can now just enter your equation and press Enter to get the solution.

See also the answers given to the same question here:  

It is not that hard, just think about how long it took for you to learn to speak properly. The same with math, just give it time and ask for help and I promise everything will be understood

0.1538461538461538 in decimal form

It is simplified to the best it can go before becoming a decimal answer.

23, 23, and 2

$$3\times(5-1)\times(2\times5+1)-(5-2)^2\\

=3\times4\times(10+1)-(3)^2\\

=12\times11-9\\

=132-9\\

=123$$

-2*(-2)^2+6*(-2)-3=

$${\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\left(-{\mathtt{2}}\right)}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{6}}{\mathtt{\,\times\,}}\left(-{\mathtt{2}}\right){\mathtt{\,-\,}}{\mathtt{3}} = -{\mathtt{23}}$$

$${\mathtt{988\,346\,297\,575\,454\,298\,764\,985\,739\,875\,639\,287\,564\,949}}{\mathtt{\,\times\,}}{\mathtt{238\,479\,265\,652\,947\,259\,874\,629\,837\,469\,587\,345\,692\,387\,456\,923}} = {\mathtt{235\,700\,099\,256\,603\,630\,019\,692\,598\,651\,476\,175\,762\,623\,230\,808\,903\,859\,557\,877\,290\,077\,482\,396\,566\,367\,535\,302\,191\,927}}$$

$${{\mathtt{0.044\: \!7}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{0.325}}}} = {\mathtt{0.000\: \!050\: \!917\: \!169\: \!123\: \!3}}$$

@@ End of Day Wrap - Monday 28/4/14   Sydney, Australia Time 21:16

Hi All,

Another busy day! Lots of great answers by DavidQD, Alan, CPhill, Anonymousperson, Kitty<3, Fiyero, Creeperface2000 and Rom.  Thank you all.

I wrote a letter to Andre Massow and have received a reply - I put these together and they are posted in the forum.  Comments and suggestions are very welcome. This is the address.  I have also included it with the 'Sticky Topics'

http://web2.0calc.com/questions/communications-with-andre-massow-with-reply_1

Kitty pulled together a few replies to 'How do I put fractions into the calculator' and put the addresses into 1 post.  I thought this was good and included her reply in the Sticky Topic 'Information pages worth keeping or developing'  It is on a new last post because I cannot edit the old pages.  I presume this is because they were written in the old forum.  It really needs to be done a little more neatly.  I have suggested that Kitty does this but I don't know whether or not she will.   I'd really appreciate it Kitty!

A new member Creeperface2000 made a great post this afternoon.  Thank you.

I think that is it for this Sunday/Monday.

Thank you all,

Melody

melodymathforum@gmail.com

I don't know what you mean. Sorry.

Those graphics look pretty cool!!!! Particularly the second one !!!

0.04x=27

x=27/0.04

$${\frac{{\mathtt{27}}}{{\mathtt{0.04}}}} = {\mathtt{675}}$$

$${\frac{{\mathtt{0.07}}}{{\mathtt{100}}}}{\mathtt{\,\times\,}}{\mathtt{0.33}} = {\mathtt{0.000\: \!231}}$$