(-2x^2/x^7)^4 =
[ -2 ]^4 * [ x^2 / x^7] ^4 =
16 * [ 1 / x^5] ^4 =
16 * [ 1 / x^20] =
16 / x^20 just as rarinstraw found.....!!! [ I just wanted to show how he got the answer ]
162/1 is in simplest form. If that is not what you asked, what are you asking?
Multiply the numerators by each other and the denominators by each other.
6 * 5 = 30
-- -- ---
20* 19= 380
So, 6/20*5/19=30/380, but now we simplify it.
3/38=30/380, so 3/38 is the final, simplified answer because you cannot simplify it any more.
You really think so Spawn? Lol
21!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Click here.
CASE SHE LIEKS MEH MOR. STAHP STELLING MEH TIEME.
You're unblocked.
3,300,000*100 is 330,000,000%
(To find percents, multiply by 100)
Why'd you block me tho?
Oh, lol :D
r + 3 = 2
(Solve for r.)
Subtract 3 from both sides.
r=-1
(-2x^2/x^7)^4 = (16/x^20)
The equation is incorrect, by the way. 12.5cm does NOT equal 75cm
h equals any real number because h is not in this problem.
Lol, my bad! You can delete my answer, thx!
okay thank you Alan that helps alot
Use the Pythagorean Theorem.
\(\sqrt{a^2+b^2}=c\)
REMEMBER that the radical symbol is like a pair of brackets: [ ] or parentheses: ( )
See http://web2.0calc.com/questions/3sqrt-2-4sqrt-12-6sqrt-54
.
Like I have said before, I think it is best to ignore him because he seems to be cheating and rude to theres.
As follows:
Note that 12 = 2*6 and 54 = 9*6 so:
\(3\sqrt{2}\times 4\sqrt{12}-6\sqrt{54}\rightarrow 3\sqrt2\times 4\sqrt{2}\sqrt6 - 6\sqrt9\sqrt6\)
This simplifies to \(12\times2\sqrt6-6\times3\sqrt6 \rightarrow 24\sqrt6 - 18\sqrt6 \rightarrow 6\sqrt6\)
So the end result is 6sqrt(6)
log4(16) = 2 because 42 = 16
So -(1/2)log4(16) → -(1/2)*2 → -1
TBH, I'm thinking about it.
Use the Newton-Raphson numerical technique:
