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how did you figure that out?

500=L((0.0239/12)/(1-(1+(0.0239/12)^-60

L=$28,250.34

The calculaor is not including the first x in the quation for "x(x+4)=(x-5)(x-1)". Therefore your answer will be much different as you leave out a whole variable.

tan (58) =  50/x      multiply both sides by x, divide both sides by tan(58)

x = 50 / tan(58)  = about 31.24      [assuming "58"  is degrees ]

x y  = 11       

x - y = 5  

So 

x²y - xy²  =   [factor]

xy ( x - y)  =

11 (5)   =

55

Use a common denominator of 150

-8/3 becomes -400/150  (multiply the numerator and denominator by 50)

3/50 becomes 9/150 (multiply the numerator and denominator by 3)

Now that they both have a common denominator (150) they can be added together

-400/150 + 9/150 = -391/150

Sidenote: If this problem is challenging for you, please get extra help from a peer or teacher. Try your best not to use the internet to get answers, since these can be done wrong no purpose, so you would get an incorrect answer. Thank you.

Divide them as you normally would. If there is a negative number and positive number the answer is negative, if there is a negative number and another negative number than the answer is positive.

ratio 7:3,

add the ratio numbers: 7+3=10,

divide total by ratio total: 60/10=6 per unit of ratio 

multiply ratio number and the number per unit of ratio

 7*6=42 cars, and 3*6=18 trucks

5^x  =  4^{x + 1}

Since 4^{x + 1}  =  4^x·4:

5^x  =  4^{x + 1}     --->     5^x  =  4·4^x

                       --->     5^x / 4^x  =  4

                       --->     (5/4)^x  =  4

Now, take the log of both sides:

                       --->     log(5/4)^x  =  log(4)

                       --->     x · log(5/4)  =  log(4)

Divide both sides by log(5/4):

                       --->     x  =  log(4) / log(5/4)

Now, use yourcalculator:

                       --->     x  =  6.21...  (approx)

One way to look at this problem:

Since the ratio of cars to trucks is 7:3, for every 10 (7 + 3 = 10) vehicles, 7 are cars and 3 are trucks.

How many groups of 10 are there?

Since there are 60 vehicles, 60 / 10 = 6   --->  there are 6 groups of 10.

Since there are 7 cars in each of the 6 groups:  6 x 7  =  42  cars

Since there are 3 cars in each of the 6 groups:  6 x 3  =  18  trucks

what is 0.196 divided by 100???

0.196 / 100 =0.00196

express 165 as a product of prime factors

165=3 X 5 X 11

Solve the following system:
{3 y-3 x = -3 |     (equation 1)
9 x-12 y = -18 |     (equation 2)
Swap equation 1 with equation 2:
{9 x-12 y = -18 |     (equation 1)
-(3 x)+3 y = -3 |     (equation 2)
Add 1/3 × (equation 1) to equation 2:
{9 x-12 y = -18 |     (equation 1)
0 x-y = -9 |     (equation 2)
Divide equation 1 by 3:
{3 x-4 y = -6 |     (equation 1)
0 x-y = -9 |     (equation 2)
Multiply equation 2 by -1:
{3 x-4 y = -6 |     (equation 1)
0 x+y = 9 |     (equation 2)
Add 4 × (equation 2) to equation 1:
{3 x+0 y = 30 |     (equation 1)
0 x+y = 9 |     (equation 2)
Divide equation 1 by 3:
{x+0 y = 10 |     (equation 1)
0 x+y = 9 |     (equation 2)
Collect results:
Answer: |  x = 10             and               y=9

 

Expand the following:
(6 x-4 y)^2

(6 x-4 y) (6 x-4 y) = (6 x) (6 x) + (6 x) (-4 y) + (-4 y) (6 x) + (-4 y) (-4 y):
6×6 x x-4×6 x y-4×6 y x-4 (-4) y y

6 x×6 x = 6×6 x^2:
6×6 x^2-4×6 x y-4×6 y x-4 (-4) y y

6×6  =  36:
36 x^2-4×6 x y-4×6 y x-4 (-4) y y

6 (-4)  =  -24:
36 x^2+-24 x y-4×6 y x-4 (-4) y y

-4×6  =  -24:
36 x^2-24 x y+-24 y x-4 (-4) y y

-4 y (-4) y = -4 (-4) y^2:
36 x^2-24 x y-24 y x+-4 (-4) y^2

-4 (-4)  =  16:
Answer: |  36x^2 - 24xy - 24yx + 16y^2

yes it is glitch because it is not writing the multiply symbol if you will write multiply symbol before x it will give you the same answer:

\(1.25=b^5\\ \sqrt[5]{1.25}=\sqrt[5]{b^5} \\ \sqrt[5]{1.0456395525912732^5}=\sqrt[5]{b^5} \\ 1.0456395525912732^{\frac55}=b^{\frac55}\\ 1.0456395525912732=b \\ \)

Hmmm... I tested them both, and it is a glitch... Hm... I don't know!

There are infinite solutions to this...for instance :

Razli                 Stanley           Theo

6                        12                   15        →    and Theo was 13, two years ago

10                      20                   23        →    and Theo was 21, two years ago

etc.

We don't need to worry about 18

36 = 2^2 x 3^2

45 = 5 x 3^2

Take each unique factor with the highest power and multiply them together...if two or more of the same unique factors have the same highest power, just take one of these .....this gives us

2^2 x 3^2 x 5  =

4 x 9 x 5  =

36 x 5  =

180    = LCM of 18, 36 and 45

You guys do realize this is a calculator website you could literally put in 1.25=b^5 and it would give you an answer in seconds