All Answers 358110 Answers

5 pounds

5 pounds

THANKS

hi cPhill,thanks for the help

I assume you have a cone with a volume of 168 cubic units and a diameter of 8 units.....and you want to find the height, h.....if so.....we have....

V_cone =  [ pi * r^2 * h  ] / 3       note that the diameter is 8 so the radius is  4    and we have

168  =  [ pi * (4)^2  * h ]  / 3     multiply both sides by 3

504  =  [ pi * 16 * h ]        divide both sides by 16pi

504 / [ 16 pi ]   =  h     =  about 10.027 units

How did you get \({5}^{-1}\)?

Someone know?

I took a trignometry class at Portland Community College in Portland, Oregon last year in September and my math book says that the genral formula for the area of a triangle is \(K=\frac{1}{2}bh\) where \(K=area;\) \(b=base;\) \(h=height\).  If you know the lengths of two sides and an angle but do not know the base or the height, you can use the formula \(K=\frac{1}{2}ab\times sin(C)\)where \(K=area;\) a = side a; b = side b; C = angle C.  You can also use the formula\(K=\frac{1}{2}bc\times sin(A)\)where \(K=area;\) b = side b; c = side c; A = angle A.  You can also use the formula \(K=\frac{1}{2}ac\times sin(B)\)where \(K=area;\) a = side a; c = side c; B = angle B.  If you know the lengths of all three sides but do not know any of the angles, the base or the height, you can use the formula \(K=\sqrt{s\times(s-a)\times(s-b)\times(s-c)}\)where \(s=\frac{1}{2}\times(a+b+c);\)a = side a; b = side b; c = side c.

I assume you have this :

2^(-log₂ 5)   if so.....we can write this as

2^(log₂ 5^-1)  =

2^[log₂ (1/5) ]  =

1/5

This goes back to the property that says  that  ...   b^(log_b a)  = a      where b is a positive base

Go for it CP, logs are not my thing.

can you help me in my last question? (Mathproblem)

PLEASE?!

yes you are

-3x > 21      divide both sides by -3 and reverse the inequality sign

x <  -7

[ I think you might have mistakenly multiplied both sides by -3   ???  ]

log2(8)+1/2log2(4)

\(log_2(8)+\frac{1}{2}log_2(4)\\ =log_2(2^3)+\frac{1}{2}log_2(2^2)\\ =3log_2(2)+2*\frac{1}{2}log_2(2)\\ =3*1+2*\frac{1}{2}*1\\ =3+1\\ =4\)

No problem! 

thank you

42.10 =x