All Answers 358087 Answers

40.5 x 16 =648 goats on the mountain.

6/5 x 5=30/5=6 or "D"

10^10=10,000,000,000 or 10 billion.

Volume of WHAT????

Yes,the equation has no real roots.When you factor out x to get a quadratic,the discriminant of this quadratic is 9-32 = -23. It's got 2 complex roots,but 

I'm assuming you haven't studied complex numbers yet.

~Guest

The answer is 5767.25

~Songoflight

Log10 = 1 because it is the power that you need to raise 10 ( the base ) to in order to get 10. (The problem is set in base 10  logs.)A logarithm is just an index.

For example Log 100 = 2 because it's the power you need to raise 10 to in order to get 100.

In base 2, log 8 would be 3 because it's the power you need to raise 2 to in order to get 8.

In base 5,log 25 would be 2 because it's the power you need to raise 5 to in order to get 25.

In base 3,log 9 would be 2 because it's the power you need to raise 3 to in order to get 9

and so on.

The idea of using logs is that we change big numbers into powers of some base,like 10, so that instead of multiplying huge numbers,we just add (or subtract) their powers  instead. 

Understand the idea of a base,and get a bit of practice with indices and you'll begin to understand it .

ok thanks

1/5= /30=3/   = /40

1/5=6/30=3/15=8/40

It has 3 roots:

x=0

x= -1/8 i (sqrt(23)-3 i)

x= 1/8 i (sqrt(23)+3 i)

Simplify sqrt(a^2-(a*sinx)^2)

\(\begin{array}{rcll} \sqrt{ a^2 - [a \cdot \sin(x) ]^2 } &=& \sqrt{ a^2 - a^2 \cdot \sin^2(x) } \\ \sqrt{ a^2 - [a \cdot \sin(x) ]^2 }&=& \sqrt{ a^2 \cdot [ 1 - \sin^2(x) ] } \\ && \sin^2(x) + \cos^2(x) = 1 \qquad \text{ or }\qquad \cos^2(x) = 1 - \sin^2(x)\\ \sqrt{ a^2 - [a \cdot \sin(x) ]^2 }&=& \sqrt{ a^2 \cdot \cos^2(x) } \\ \mathbf{\sqrt{ a^2 - [a \cdot \sin(x) ]^2 } } & \mathbf{=} & \mathbf{a \cdot \cos(x) } \end{array}\)

91562.4

DUH its 25

In the drawing, a triangle is formed by drawing a line segment of length a from (4,3) to the positive x-axis. For what value(s) of a can you form

a) one triangle?

b) two triangles?

c) no triangles?

\(\begin{array}{|c|c|c|c|c|c|} \hline & a<3 & a=3 & 3<a<5 & a=5 & a > 5 \\ \hline \text{triangles} &0 & 1 & 2 & 1 & 1 \\ \hline \end{array}\)

\(\begin{array}{|c|c|c|c|c|c|} \hline & a<3 & a=3 & 3<a<5 & a=5 & a > 5 \\ \hline \text{triangles} &0 & 1 & 2 & 1 & 1 \\ \hline \end{array}\)

See the answer posted under your first question.

[4 x10^9] x [300,000,000]^2 / [4.2 x 10^6]=8.57 x 10^19 kg of TNT needed to release the same amount of energy per second as 4 million tons per second(4 x 10^9 kg) of Hydrogen used by the Sun.

\(2.4z + 1.2z - 6.5 = 0.7 \\ 3.6z - 6.5 = 0.7 | + 6.5 \\ 3.6z = 7.2 | ÷ 3.6 \\ z = 2\)  

\(a = 4 \\ b = -12 \\ \frac{2ab - b}{a} = \frac{2 \times 4 \times -12 - \left (-12 \right )}{4} \\ = \frac{8 \times -12 - \left (-12 \right )}{4} \\ \frac{-96 - \left ( -12 \right )}{4} \\ = \frac{-84}{4} \\ = -21\)