All Answers 358087 Answers

The first question:

\(\sqrt[4]{4x^3}=\sqrt[4]{4}\times\sqrt[4]{x^3}=\sqrt{2}x^\frac{3}{4}\)

The second:

\(\sqrt[4]{x}=x^\frac{1}{4}\)

{ x = -10

{ x = 8

\((3\sqrt{5})^2= 3^2\times(\sqrt{5})^2=9\times5=45\)

What's q1, q2, and q3? What kind of question is it?

You can use your calculator to get

64+96 = 160

\(3n - 3 = 4n + 1 | + 3 \\ 3n = 4n + 4 | - 4 \\ 3n - 4 = 4n \\ n = -4 \)           

52.03 * 30

Two sides are the same as the triangle is an isosceles triangle.

By Pythagoras' theorem,

\(x^2+x^2=14^2\)

\(2x^2=196\)

\(x^2=98\)

\(x=\sqrt{98}=7\sqrt{2}\)

When the length of the other two sides is \(7\sqrt{2}\)

The length of the hypotenuse is 14

 \((3*\sqrt{5})^2=\)

\(3^2*(\sqrt{5})^2=\)

\(9*5=45\)

  19.5*14.152+78/2

=275.964+78/2

=275.964+39

=314.964

equation of a circle centre (a,b) with radius r has equation

(x-a)^2 +(y-b)^2=r^2

Your circle has equation (x-3)^2 + (y-5)^2 = r^2.

Now to find r for your circle.  Area of circle =(pi)r^2 = 36(pi)

                                                       so                r^2  = 36

radius of your circle is                                        r      = 6

full equation of your circle is (x-3)^2 = (y-5)^  = 36

2⁶ = 2*2 * 2*2 * 2*2 = 4*4 * 4 = 16 * 4 = 64 

64+96=

60+4+6+90=

60+10+90=

60+100=

160

343 = 7^3. No other factors apart from 7

lengths of other two sides are equal.If lengths are   x  and x again,then x^2 plus x^2 -14

so 2 x^2=14        

x^2       =7

x           =sqrt 7

Use right-angled triangle where

length of side opposite angle (t) = 1

length of side adjacent to angle (t)= 9

then hypotenuse length = sqrt(82)

so sin(t) =1/sqrt(82)

One triangle is formed when a = 3

Two triangles can be formed when   3 < a < 5

No triangle will be formed when a < 3

1/2(x+6)=2x and 5-2x=7x-h

Solving the first equationfor x, we have

(1/2)(x + 6)  = 2x      multiply both sides by 2

x + 6  = 4x       subtract x from both sides

6 = 3x      divide both sides by 3

2 = x

Subbing this into the second equation, we have

5 - 2(2) = 7(2)  - h      simplify

5 - 4  = 14 - h

1 = 14  - h      subtract 14 from both sides

-13   =  -h     multiply through by -1

13  = h

cot = x/y       sin  = y/r       r = sqrt ( x^2 + y^2)    ......so we have.....

cot(t)  = 9/1      r = sqrt[ 9^2 + 1^1]  = sqrt [ 82]

So.....sin(t)   =  1/ sqrt(82)  =  sqrt(82) / 82

n + 1 = 4n     subtract n from both sides

1 = 3n      divide both sides by 3

1/3  = n

f(x)=3x^2+6x-10

The x coordinate of the vertex is given by    -b/ [2a]   where b = 6 and a  = 3......so we have...

-6/ [2(3)]  =    -1

And we can put this value into the function to find the y coordinate of the vertex....so....

f(-1)  = 3(-1)^2 + 6(-1) - 10  =  3 - 6 - 10  =   -13

So the vertex is  (-1, -13)

If If a + b + c = -2 and x + y = -9, what is 9x + 4b + 9y + 4c + 4a? I don't understand how to solve this. I need to assign each variable a number that makes the equation true.and x + y = -9, what is 9x + 4b + 9y + 4c + 4a?

a + b + c = -2    →  4a + 4b + 4c   =  -8    

x + y = -9  →    9x + 9y  =  -81

Therefore............

9x + 4b + 9y + 4c + 4a   = 

[9x + 9y] + [ 4a + 4b + 4c]  =

[ -81]   +  [ -8 ]

-89

Alrighty systems of equations! These are simple enough.

**For reference, let the number of hours equal x**

So if Brad makes only 4 key chains an hour then his "equation" would be 4x.

Getting a head start with 6 key chains is Velma, who makes only 3 per hour, her "equation" is  3x+6.

So now you have your system set up, just find what x is using any of the methods you've learned so far. I don't feel like doing it so... good day.