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You can literally punch this into a calculator but...

2^6 = 2 * 2 * 2 * 2 * 2 * 2 = 64 

=10^(10^3196.338559265405)

=2.180515938024003×10^3196 decimal digits

Please do not throw out the "R" word without knowing what it means. You used it in derogatory manner though a "retard" is actually a person who is mentally disabled. People can take this to extreme offense (such as myself) and it won't end in your favor. Besides, nobody won't not like you because you're mentally disabled, unless they're sadstic and ignorant people. If people don't like you then try to avoid them, find something you're interested in eventually people with that common interest will either ridicule you or become your friend. It's a gamble but isn't that what life is about?

If you're trying to get the equation into the exponent form then here are your answers:

\(\sqrt[4]{4x^3} \)=          \({4x}^{3/4}\)

\(\sqrt[4]{x}\)=          \(x^{1/4}\)

The pattern is pretty simple so no need to explain it.

One   -   David.

After quickly seeing this, I think I have the answer to A and C.

a.) You can form a triangle if the line segment a was connected to a positive real number on the x axis EXCEPT for 0.

c.) You can form no triangle if the line segment a was connected to 0.

I have no idea how you could get 2 triangles.

1/4 or .25 multiplied by 4.9289 would be 1.232225

The answer is 15

1/4*4.9289 = 1.232225

No matter what numbers you assign to each variable, the final result should always=-89

Example:{9 x+4 b+9 y+4 c+4 a, a = 1, b = 2, c = -5, x = -4, y = -5}

4 a+4 b+4 c+9 x+9 y = -89

Here is one easy answer:

a=0

b=0

c=-2

x=0

y=-9

9(0)+4(0)+9(-9)+4(-2)+4(0)

-81-8

-89

The answer is in the question.

Mister, you are the one that is retarted.

69¹⁷³⁸ is equal to infinity.

₄₂₀69¹⁷³⁸ is basically infinity.

infinity=3.

3=triangle

triangle = illuminati

Illuminati conferemed

Illuminati is infinity.

You would put it next to 11 and 12, as the square root of 130 is 11.4017542509913798...

A: 98 B: 0 C: 1 D: 0 E: 1 It might be expected intuitively that Pirate A will have to allocate little if any to himself for fear of being thrown overboard so that there are fewer pirates to share between. However, this is as far from the theoretical result as is possible. This is apparent if we work backwards: if all except D and E have been thrown overboard, D proposes 100 for himself and 0 for E. He has the casting vote, and so this is the allocation. If there are three left (C, D and E) C knows that D will offer E 0 in the next round; therefore, C has to offer E 1 coin in this round to make E vote with him, and get his allocation through. Therefore, when only three are left the allocation is C:99, D:0, E:1. If B, C, D and E remain, B knows this when he makes his decision. To avoid being thrown overboard, he can simply offer 1 to D. Because he has the casting vote, the support only by D is sufficient. Thus he proposes B:99, C:0, D:1, E:0. One might consider proposing B:99, C:0, D:0, E:1, as E knows he won't get more, if any, if he throws B overboard. But, as each pirate is eager to throw each other overboard, E would prefer to k**l B, to get the same amount of gold from C. Assuming A knows all these things, he can count on C and E's support for the following allocation, which is the final solution

And that, my friends, is how you answer a riddle...

You do it my looking it up

_w²   

just add a 2 to the top

Expand the following:
pi (3-x)^2

(3-x) (3-x) = (3) (3) + (3) (-x) + (-x) (3) + (-x) (-x) = 9-3 x-3 x+x^2 = x^2-6 x+9:
pi x^2-6 x+9

pi (x^2-6 x+9) = pi×9+pi (-6 x)+pi x^2:
Answer: |  pi×9 - 6 pi x + pi x^2

m=y₂-y₁/x₂-x₁:

m=-1-10/-7+9

m=-11/2

m is equal to:

 -11

  2

Distribute the -3 into both terms:

Distribute -3 to the constant term 3, therefore multiplying it.

-3(3)=-9

Distribute the -3 to -8j

-3(-8j)=24j

Final Solution:

-9+24j

It repeats, so therefore, it is not an irrational number.

Something like:

1.010010001...

Would be irrational. It has a pattern, but it goes on and on and on.

Repeating numbers are not seen as irrational, on the other hand.

What is the question?

The square root of 130 is irrational, as it goes on and on forever.

Oh, wait a second....

The last time I checked, there is no perfect squares in 130.

sqrt(130) = 11.4017542509913798

It would be located around 11.

I am sorry if this did not help you, its been a long time since I did square roots like this.

Male Total: 625

Female Total: 575

Bus Total: 650

Car Total: 375

Other Total: 175

P(M|C)(Male people who travel by car)=200

I belive they are independent, as a depended event would be something such as the total amounts of males,etc.

10.990*85.9304 = 944.375096.

Tada! Calculators.