\(\frac{3}{5}*100 = 60\)

1/5 times 5 plus 2

(1/5) * 5 + 2 = 1 + 2 = 3

1 / 5 * 5 + 2 = 1 / 25 + 2 = 2.04

 !

Let's let the function be x^2 + 1

Using the left hand rule to calculate the area.......we will have 5 rectangles with the following heights    1, 5, 17, 37, 65  ...  and the width of each is 2

So......the total area = 2[1 + 5 + 17 + 37 + 65]  = 250 sq units

Using the right hand rule and applying the same procedure we have rectangles with the following heights 5, 17, 37, 65, 101  .... and the width of each is 2

So.....the total area = 2 [ 5 + 17 + 37 + 65 + 101] = 450 sq units

The actual area =   [10]^3/3 + 10  = 343+ 1/3 sq units

So

L₅ < actual  area < R₅

8 x y+2 z (8 x-3 y)-12 z^2    expand

8xy + 16zx - 6yz - 12z^2   factor

8x(y + 2z) - 6z(y + 2z)

(y + 2z) (8x - 6z)

(y + 2z) * 2 (4x - 3z)  =

2(y + 2z)(4x - 3z)

Factor the following:
8 x y+2 z (8 x-3 y)-12 z^2

The factors of -96 x y that sum to 2 (8 x-3 y) are -6 y z and 16 x z.
So, -12 z^2+2 (8 x-3 y) z+8 x y = -12 z^2-6 y z+16 x z+8 x y:
-12 z^2-6 y z+16 x z+8 x y

-12 z^2-6 y z+16 x z+8 x y = 4 z (4 x-3 z)+2 y (4 x-3 z):
4 z (4 x-3 z)+2 y (4 x-3 z)

Factor 4 x-3 z out of 4 z (4 x-3 z)+2 y (4 x-3 z), resulting in (4 x-3 z) (4 z+2 y):
(4 x-3 z) (4 z+2 y)

Factor 2 out of 4 z+2 y:
Answer: |  2 (2 z+y) (4 x-3 z)

\(48T=48{T}^{2}\)

\(48T-48{T}^{2}=0\)

\(-48{T}^{2}+48T=0\)

\({T}^{2}-T=0\)

\({T}^{2}-T+\frac{1}{4}=\frac{1}{4}\)​

\({(T-\frac{1}{2})}^{2}=\frac{1}{4}\)

\(T-\frac{1}{2}=±\frac{1}{2}\)

\(T=\frac{1}{2}±\frac{1}{2}\)

\(T=\frac{1}{2}+\frac{1}{2}\)

\(T=\frac{2}{2}\)

\(T=1\)

\(T=\frac{1}{2}-\frac{1}{2}\)

\(T=\frac{0}{2}\)

\(T=0\)

We use the brackets for order of operations.

In this order

{ [ ( ) ] }

3√10 (root form)

9.487 (decimal form)

Why did you change your text color to white? This is not right. Yo do not need to be fancy here.

If she started with 5 feet, she then cuts off 3³/₄ feet to make a hair bow, being left with 5 - 3³/₄ = 1¹/₄ feet.

Then she cuts off ⁵/₆ feet to make a border on a scrapbook page, being left with

1¹/₄ - ⁵/₆ = ⁵/₄ - ⁵/₆

                = ¹⁵/₁₂ - ¹⁰/₁₂

                = ⁵/₁₂ feet.

If she needs to cut 2 ¹/₃-feet pieces, she will need 2(¹/₃) = ²/₃ feet

                                                                                           = ⁸/₁₂ feet.

She does not have enough ribbon since ²/₃ > ⁵/₁₂. 

Turn what into degrees and minutes??

Compute the definite integral:
 integral_(-3)^3 sqrt(9-x^2) dx
For the integrand sqrt(9-x^2), substitute x = 3 sin(u) and  dx = 3 cos(u)  du.
Then sqrt(9-x^2)  =  sqrt(9-9 sin^2(u))  =  3 sqrt(cos^2(u)).
This substitution is invertible over -pi/2<u<pi/2 with inverse u = sin^(-1)(x/3).
This gives a new lower bound u = sin^(-1)(-3/3) = -pi/2 and upper bound u = sin^(-1)(3/3) = pi/2:
  =  3 integral_(-pi/2)^(pi/2) 3 cos(u) sqrt(cos^2(u)) du
Factor out constants:
  =  9 integral_(-pi/2)^(pi/2) cos(u) sqrt(cos^2(u)) du
Simplify cos(u) sqrt(cos^2(u)) assuming -pi/2<u<pi/2:
  =  9 integral_(-pi/2)^(pi/2) cos^2(u) du
Write cos^2(u) as 1/2 cos(2 u)+1/2:
  =  9 integral_(-pi/2)^(pi/2) (1/2 cos(2 u)+1/2) du
Integrate the sum term by term and factor out constants:
  =  9/2 integral_(-pi/2)^(pi/2) cos(2 u) du+9/2 integral_(-pi/2)^(pi/2) 1 du
For the integrand cos(2 u), substitute s = 2 u and  ds = 2  du.
This gives a new lower bound s = (2 (-pi))/2 = -pi and upper bound s = (2 pi)/2 = pi:
  =  9/4 integral_(-pi)^pi cos(s) ds+9/2 integral_(-pi/2)^(pi/2) 1 du
Apply the fundamental theorem of calculus.
The antiderivative of cos(s) is sin(s):
  =  (9 sin(s))/4|_(-pi)^pi+9/2 integral_(-pi/2)^(pi/2) 1 du
Evaluate the antiderivative at the limits and subtract.
 (9 sin(s))/4|_(-pi)^pi = (9 sin(pi))/4-(9 sin(-pi))/4 = 0:
  =  9/2 integral_(-pi/2)^(pi/2) 1 du
Apply the fundamental theorem of calculus.
The antiderivative of 1 is u:
  =  (9 u)/2|_(-pi/2)^(pi/2)
Evaluate the antiderivative at the limits and subtract.
 (9 u)/2|_(-pi/2)^(pi/2) = (9 pi)/(2 2)-((9 (-pi))/(2 2)) = (9 pi)/2:
Answer: |  =  (9 pi)/2

Assume each beautician has almost equal number of requests.

95 ÷ 4 = 23 R 3

Assume Kurt has more requests than Jim.

Let Jim be D.

Let Kurt be C.

24 - 23 = 1

She has 1 more.

and the dirrivatave of an intagral or an intagral of a dirrivatave cancel out, because an intagral is the oppiste of a

dirrivatave.

1. \(e^t\cos{(t^3)},t\in{[\infty,3]}\)

2. \(e^t\cos{(t^3)},t\in{[3,-\infty]}\)

.2957 Radians/Second

1/5 times 5 = 1

1+2=3

3 = answer

Since there are  possible combinations of the above properties, each possible type of car is represented exactly once. Once we choose the first car, the second car has  possibility for the doors to be different,  possibilities for the color to be different, and  possibilities for the brand to be different. Thus there are  cars that have no properties in common with the first car. We could have chosen this second car in 23 equally-likely ways, and hence our answer is 6/23.

So the answer is 6/23 :)

Because this calculator CANNOT handle very large numbers like that one, and so it says "infinity", which is a programming error of the calculator. It should say something like "overflow." This number is much, much larger that "googol", or 10^100.

3, 4, 7, 10, 16, 21, 30, 40,

F(n) = Fibonacci[n] + Prime [n]

i searched the internet and found the answer.

now sure about the first term. seems like the first term should be 2.

Luke

e is a mathematical constant, approximately 2.71828

👀👀

It is easier to write e than 2.71828 😜

👉 Your calculator probably has this number already stored in it, look for the e button. A scientific calculator has a button with the power function, e to-the-power x, and it's this button you can use to calculate y in your formula once you know a value for x.

Badinage

45*14n = 630n

something that you will know when you are about to die.

Now if you graph the function you will find that guest1 got the correct answers for where the function EQUALS zero.   The graph will show you that for 1  < = x  <= -5/2   the value will be GREATER than or EQUAL to  ZERO