All Answers 358154 Answers

this is simple it is $${\frac{{\mathtt{9}}}{{\mathtt{100}}}}$$.

Thanks CPhill

If it's on sale with a 15% discount off the original price, then the sale price must just be 85% of the original price.

So 85% x 210 = $178.50

$$\left({\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{0.15}}\right){\mathtt{\,\times\,}}{\mathtt{210}} = {\frac{{\mathtt{357}}}{{\mathtt{2}}}} = {\mathtt{178.5}}$$

$178.5

Here you go......

The x intercept is (-6,0) and the y intercept is (0,6)

First, let's simplify the 3*√20

We have

3*√[(4)(5)]  = 3*√4*√5 = 3*2*√5 = 6*√5

So we have

6*√5 * 6*√5

And since we can multiply in any order, we have

6 * 6 * √5 * √5 =  36 * √25 = 36 * 5  = 180

So, we have

-3 - (1/4)(1/8)

Remember, we must carry out any multiplications before we carry out any subtractions. So, multiplying the two fractions together, we have

-3 - (1/32)   

Note that this is the same thing as

- (3 + 1/32)   

And converting the mixed number to an improper fraction, we have

- (97/32) = -97/32

And that's it.....

So we have

∫x³ √(x⁴ + 9) dx

Let u = x⁴ + 9      du = 4x³ dx   ⇒   du/4 = x³ dx

I'll just continue in terms of "u" instead of "x," so that we don't have to "back-substitute."

So when x = 0, u = 9        And when x = 2, u = 25

So this gives us

(1/4)∫ u^1/2 du = (1/4)(2/3) u^3/2  = (1/6) u^3/2

And evaluating this from u = 9 to u = 25  gives us

(1/6)(25^(3/2)-9^(3/2))  =  49/3

And to get the average value, we divide this by the interval width, i.e., 2. 

This gives us......... 49/6

Note how the "average value" turns a "non-rectangular" area into a "rectangular area!!"

The "width" of the rectangle (2)  times the "height" (49/6) = 49/3 !!

And I think that's it.....

Functions that make use of angles (like sin and cos, for example) have to know if the angles they are working with are in degrees or radians.  If the calculator is in degree mode the functions automatically assume that numbers they are given are in degrees; if it is in radian mode the functions automatically assume that numbers they are given are in radians.

eg degree mode:   cos(5) = 0.9962   the 5 is assumed to be degrees

radian mode:  cos(5) = 0.2837  the 5 is assumed to be radians

You can't!  There are an infinite number of different sized right triangles with a given base.

I assume that by "row" you mean "in series" and by "beside" you mean "in parallel".  If that is the case then the following diagram illustrates your circuit:

Resistances in series simply add:  R24 = R2+R4 and R35 = R3 + R5

For resistances in parallel: 1/R2345 = (1/R24) + (1/R35)

Then R1 and R2345 are in series so Rtotal = R1 + R2345

The total current is then given by I = U/Rtotal

Can you take it from there?

(You should find that I ≈ 0.0224 A)

$${{\mathtt{e}}}^{-{\mathtt{13}}} = {\mathtt{0.000\: \!002\: \!260\: \!329\: \!407}}$$

thanks a lot guys i get it now

20*tan(70) 

Should work fine.

I am on an android and I dont think I can actually enter it from here.

I see that you are back on the forum.

I have sent a message to thr site developer with a link to this thread.

Regards

Melody.

Hi, yep I'm new in this forum. Thanks for your welcome :).

I get this error just embedding the suggested code in this webpage to put the calculator in my website.

<iframe width="590" height="390" src="http://web2.0calc.com/widgets/horizontal/" scrolling="no" style="border: 1px solid #silver; ">
</iframe>
<br />
<a href="http://web2.0calc.com/">Web 2.0 scientific calculator</a>

So I really don't know what to do if the source html code is not working, because there's no advanced functions to think that I was doing something wrong :S.

Firstly, I see that you are very new - as a member anyway.

Welcome to Web2.0calc forum.  We hope that you enjoy this site.

The forum has recently been revamped and there are a lot of bugs that still have to be eradicated.  Many of the errors are intermittant, so just because it doesn't work this time doesn't mean it won't work next time.  I often open a new page when I have problems and suddenly the feature is working again.  The error you are getting is a very generic error message.  In itself it does not help much.

NOW

Did you just want to embed a "Math(Input=Result)" into your post?  Was that where your problem lay?

I am not a computing person but I will pass this thread address onto the site developer.

if we assume there are 365 days in a year then there are 86500/(15*365) orbits per day, so the astronaut did approximately 330*86500/(15*365) orbits.

$${\frac{{\mathtt{330}}{\mathtt{\,\times\,}}{\mathtt{86\,500}}}{\left({\mathtt{15}}{\mathtt{\,\times\,}}{\mathtt{365}}\right)}} = {\mathtt{5\,213.698\: \!630\: \!136\: \!986\: \!301\: \!4}}$$

approximately 5200 orbits (or 5210 orbits or 5214 orbits, depending on how approximate you want to be!)

@@ End of Day Wrap - Sun 11/5/14   Sydney, Australia Time 20:10 

Hi everyone,

Great answers today were written by Alan, CPhill, admin, DavidQD and GoldenLeaf .  Thank you all.

There were also some nice shows of appreciation from some anonymous people as well as by Anana.  we all thank you for this evidence of gratitude.

Also, Morgan Tud and Lady Guinevere both has something to say and Sisyphus showed us a holiday snap!

BIG NEWS TODAY.

CPhill is now a MODERATOR - He has the POWER OF THE TICK!   CONGRATULATIONS CHRIS!

The WORD was out very quickly!   This is a quote from Morgan Tud: (I will include the thread below.)

"Yea, Sir CPhill, whom His Majesty hath just Knighted, stood as a guard to the chambers of the Knights and did witness the circular pun and the leads to a circular paradox by Sir Cumference."    

A couple of interesting questions/answers

$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{98}} = {\mathtt{196}}$$

196cm or 1.96metres.

That is very tall!

Thanks Melody :)

$${\frac{{\mathtt{72\,000}}}{{\mathtt{48}}}}{\mathtt{\,\times\,}}{\mathtt{1.15}} = {\mathtt{1\,725}}$$   So that is $1725

They are expensive radios!

The radios actually cost $72000/48 each

the original cost is 100%, if you add 15% you get 115% which is 1.15.  That is where the 1.15 came from.

If this is too confusing I can break it down better for you.

I am glad you like this site.  We try hard to help people.  Why don't you join up and then we can get to know you.  It is free and easy to do.   

Thanks Alan

To make a 15% profit he must sell the lot for 1.15*$72000

$${\mathtt{total}} = {\mathtt{1.15}}{\mathtt{\,\times\,}}{\mathtt{72\,000}} \Rightarrow {\mathtt{total}} = {\mathtt{82\,800}}$$

The price per radio is therefore $82800/48

$${\mathtt{radioprice}} = {\frac{{\mathtt{82\,800}}}{{\mathtt{48}}}} \Rightarrow {\mathtt{radioprice}} = {\mathtt{1\,725}}$$ 

price per radio = $1725

Pricey radios!

Thank you for making it easier to understand :P