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Fair enough! In that case Landry's reply is correct.

Lynn has two bank accounts with balances of $1100 and $843. Lynn also has three credit cards with balances of $250, $782, and $1360. What is the total value of the five accounts?

$1,100 + $843 =$1,943 Credit balance of her two bank accounts.

$250 + $782 +$1,360 =$2,392 Debit balance of her three credit cards.

$1,943 - $2,392 = - $449 Net debit balace that Lynn has- or net amount she owes.

Yes, CPhill could you please explaing how you go it?

10000*5.3%*4 = 2120

Are the credit card balances what she owes or the $ she has loaded/prepayed on to the credit cards GAMEMASTERX40 ?

Hmm!  I'm inclined to think that the credit card balances should be subtracted from the bank balances as, presumably,  Lynn will have to pay the former to the credit card companies.

1100+843+250+782+1360 = 4335

$4335

This graph should help

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.12*1500 = 180

Use the fact that tan(68°) = height/14.3,  so:

height = 14.3*tan(68°) m

870/6 = 145

145*5 = 725

725 bottles

353-45 = 308

-$308

35.3937420038488 meters

This is the number of distinct ways.  Distinct means if you interchange the positions of two of the A's (for example) the result doesn't count as a new arrangement.

11 letters in all.

3 A's;  2 L's;  2 S's;  2 E's

Number of ways =  11!/(3!*2!*2!*2!)  =  831600

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Well, I really didn't understand what they were talking about.. Confused me 

I dont know what you mean with 'distinct' but: there's 11 letters, which basically means It's 11! (11 factorial).

11!=11*10*9*8*7*6*5*3*2*1=39916800. This is including the word Tallahassee.

And this is not probability, It's combinatorics.

This graph should help you to answer:

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I honestly put this in the calculator and mine came up with 25.4.. So I really don't know if it's right or wrong

First multiply all terms by 4/3:

x^2 + 2x = 16/3

Add 1 to both sides

x^2 + 2x + 1 = 1 + 16/3

This becomes

(x + 1)^2 = 19/3

There are two solutions:

A.   x + 1 = sqrt(19/3)   so  x = -1 + sqrt(19/3)

B. x + 1 = -sqrt(19/3)  so   x = -1 - sqrt(19/3)

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I've been working on probability problems because of final exams this week so to be honest I don't really know how many times you could re-arrange this..