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I see I sparked some discussion. So the difference is in paying close attention as to exactly how you formulate the problem.

Thanks all.

It is interesting when these types of contradictions spring up :)

Thanks Alan and Michael  :)

What is 20 multiply or 20 x?

I am with Melody too

The last of the above ignores a set of parentheses (implied in the way the original question is specified), hence does not comply with PEDMAS.  So I'm with Melody on the solution.

WolframAlpha, Matlab, Mathcad and Maple all give the following:

.

"A new scooter is valued at $15 000. At the end of each year its value is reduced by 15% of its value at the start of the year. What will it be worth after 3 years?"

At the end of the first year the value is $0.85*15000       (because 0.85 = 1 - 0.15)

at the end of the second year the value is $0.85*0.85*15000 → $0.85²*15000

at the end of the third year the value is $0.85*0.85²*15000 → $0.85³*15000

etc.

You do make a very interesting point answering guest.

\(\sqrt{(-8)^2}=\sqrt{64}=+8\\ BUT\\ \mbox{If you use index laws then}\\ \sqrt{(-8)^2}= ((-8)^2)^{0.5} =(-8)^{2*0.5}=(-8)^1=-8 \)

I still think the answer is +8 but I would like other mathematicians to comment on this.    

what is square root of (-8)^2 ?

\((-8)^2=64\\ \sqrt{64}=+8\)

+8 IS THE ONLY SOLUTION

\({({(-8)^2})^{1\over2}}={(-8)^{1}}=-8\)

I would say that since \({(-8)^2}={8^2}\)

8 is also a solution.

y=1(x-(-3))^3+0

\(y=1(x-(-3))^3+0\\ y=(x-(-3))^3\\ y=(x+3)^3\\ y=x^3+3*3x^2+3*3^2x+3^3\\ y=x^3+9x^2+27x+27\\\)

theres 16000 laps, a lap takes 30 seconds. How many minutes to complete the laps?

Needed time = 16000 * 30sec * (min/60sec) = 8000min

Needed time = 8000min

hi how do i solve y=1(x-(-3))^3+0

Expanded form:y = x^3+9x^2+27x+27= (x+3)^3

-1/4y-1=-3 solve for Y?

-1/4y-1=-3

-1/4y = -3+1 = -2 divide both sides by -1/4

y = -2 / -1/4=-2 x -4

y=8

In the bedroom 😉

You English so good man

If Uday goes to a Mexican taco truck and orders an unknown order of crunchy tacos at US$2.50 each and buys an unknown number of soft tacos at $3.00 each and pays with a US$50 bill and recives US$7.50 back as change, how many crunch tacos and how many soft tacos did Uday buy?  Please show how you got to your answer

Let the number of crunchy tacos=C

Let the number of soft tacos =S

2.50C + 3S =50.00 - 7.50=42.50

gibsonj338: You do NOT have enough information to solve it algebraically!. You must give either the total number of tacos sold, or the number of either "cruncy" or "soft" tacos sold!!.

However, because of the small numbers involved, you can easily "guess" that the answer is:

5 cruchy tacos and 10 soft tacos sold, brcause:

[5 x $2.5] + [10 x $3.00] =$42.50.

5.6?

If a=Opposite side, b=Adjacent side, and c=Hypotenuse, then we have:

Sin(theta)=a/c

Cos(theta)=b/c

Tan(theta)=a/b

15 + n < 25 subtract 15 from both sides

n < 10