All Answers 356066 Answers

it works just like equations

but if you multiply by -1 or negative number , it inverses

so you just need to subtract 15

15+n<25

n<10

so all solutions for this inequality are under 10 

the biggest integer who satisfy this equation is 9 

just solve it like equations rule

but don't forget when you are multiplying by negative number

or squaring negative numbers

You must make sure not to confuse the two:

Combinations[nCr]=n! / [(n-r)!.r!]. Example:75C5=75! / [(75-5)!.5!]=17,259,390.

Permutations[nPr] =n! / [n-r]!.       Example:75P5=75! / [75-5]! =2,071,126,800.

Math is if you have one potato and you are given an other potato you have enough potato to boil them and make dinner with two boiled potatoes.

Type 07734 into your calculator and turn it around and bada bing bada boom: 

One of the most common calculators seems to be the Ti-84 so i will explain it for that one, but also for all others too.  this is a Ti-84

on it you will want to press Alpha, Y= and then you will see the fractions button. Now i guess there is a high chance you dont have one of these, so here is how to do it on any calculator with a division button. All you have to do is to type the fraction in but replace the line thingy(i dont know its name) with a division sign. That is all there is too it and you have a fraction on any calculator.

Hello Guest!

How do I find the other angles in a right triagle ?

A right angle triangle

A         B                                    C

consists of the sides

a and b and the hypotenuse c

the sides opposite the angle

α        β                                     γ.

The angles α and β are calculated

by means of trigonometric functions.

α = arctan (a / b) = arcsin (a / c)

β = arctan (b / a) = arcsin (b / c)

Good night!

asinus :- )

   !

Well the brackets placed like that indicate that the operation here is multiplication. So the question is really 3x -5x 7. This has an answer -105. I hope this helps.

-G

Where ever you feel the delightful necessity to answer mathematical problems with the inclusion of fractions. Or in you math binder i guess.

That depends on the information you are given about different parts of the triangle. If you could supply me with the information or triangle you have been given i might be able to help you.

There are lots of fractions that are larger than one, but they are improper fractions. Examples of these are 3/2 and 4/3 which should be simplified to 1 1/2 and 1 1/3. Hope this was the answer(s) you were looking for.

-G

4+4+4+4=4*4=16

145x + 250y =25,000,000

This has an infinite number of solutions. One is:

x=50 and y=99,971. And ANY multiple of 50, such as 100, 150, 200, 250.......for x will give a solution.

Solve for x:
(x-80) (x-2) = x^2-10 x

Expand out terms of the left hand side:
x^2-82 x+160 = x^2-10 x

Subtract x^2-10 x from both sides:
160-72 x = 0

Factor constant terms from the left hand side:
-8 (9 x-20) = 0

Divide both sides by -8:
9 x-20 = 0

Add 20 to both sides:
9 x = 20

Divide both sides by 9:
Answer: | x = 20/9

Hello guest!

At what minimum speed will be the normal force become zero 

( causing occupants of the car to seem weightless ) if r = 23.5 m.

I understand your question so:
The radius of curvature of a threshold is r = 23.5 m.

The centrifugal force is equal to gravity.

mv² / r = mg

v²  = gr

v = √(gr)

v = √(9,81(m/s²) * 23.5m)

v = 15.183 (m/s) * (3600s/h) * (km/1000m)

v = 54.660 km/h

The vehicle takes off at a speed of v = 54.660 km/h.

Greeting asinus :- )

   !

Clear everything by using the letter "C" in the top right hand corner.

A quick graph shows pro35hp is clearly correct:

Solve for x:
2 (2 cos(x)-3 sin(x))+sin(2 x) = 12

2 (2 cos(x)-3 sin(x))+sin(2 x)  =  4 cos(x)-6 sin(x)+sin(2 x):
4 cos(x)-6 sin(x)+sin(2 x) = 12

Subtract 12 from both sides:
-12+4 cos(x)-6 sin(x)+sin(2 x) = 0

Simplify trigonometric functions:
2 (cos(x)-3) (2+sin(x)) = 0

Divide both sides by 2:
(cos(x)-3) (2+sin(x)) = 0

Split into two equations:
cos(x)-3 = 0 or 2+sin(x) = 0

Add 3 to both sides:
cos(x) = 3 or 2+sin(x) = 0

Take the inverse cosine of both sides:
x = cos^(-1)(3)+2 pi n_1  for  n_1  element Z or x = 2 pi n_2-cos^(-1)(3)  for  n_2  element Z
   or  2+sin(x) = 0

Subtract 2 from both sides:
x = cos^(-1)(3)+2 pi n_1  for  n_1  element Z
   or  x = 2 pi n_2-cos^(-1)(3)  for  n_2  element Z
   or  sin(x) = -2

Take the inverse sine of both sides:
Answer: |  x = cos^(-1)(3)+2 pi n_1  for  n_1  element Z
   or  x = 2 pi n_2-cos^(-1)(3)  for  n_2  element Z
   or  x = pi+sin^(-1)(2)+2 pi n_3  for  n_3  element Z                                                                           or x = 2 pi n_4- sin^(-1)(2)  for  n_4  element Z

Hi Chris,

Yes I could have miss a set of 10 easily enough.  I can't be bothered trying to find it though :)

I get  something a little different from Melody

Assuming that we have to start with a non-zero digit :

If we start with 1, we have 9 possibilites for the second digit  0-8   

Srarting with 2, we have 8 possibilities for the second digit, 0-7

Starting with 3, we have 7 possibilities for the second digit, 0-6

.

.

.

Starting with 9, we only have 1 possibility for the second digit, 0

So........the sum of all the possibilites for the second digit, with the beginning digit being 1-9,  is just the sum of the first 9 positive integers = (9)(10)/2  =  45

And since the 3rd digit can be 0-9, we have 10 possibilites.........so .......  45 * 10   = 450   4-digit numbers that have the last digit equal to the sum of the first two digits

\(( \frac{27}{64})^{- \frac{4}{3}} = ( \frac{27*27^{1/3}}{64*64^{1/3}})^{-1} = ( \frac{27*3}{64*4} )^{-1}= \frac{256}{81}\)

(27/64) ^(-4/3)  =

(64/27) ^ (4/3)   =

[(64/27)^(1/3)]^4   =

[ 4/3 ]^4  =

256 / 81

\(({27\over64})^{-{4\over3}}={256\over81}=3.1604938271604937\)