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a camera cost 115 Canadian dollars. If each Canadian dollar is worth 0.952 U.S. dollars, how much will the camera cost in US dollars? please help me with this problem is it dividing addition subtraction or multiplying

\(\begin{array}{|rcll|} \hline && 115 ~\text{Canadian dollars} \times \frac{0.952 ~\text{U.S. dollars} }{1 ~\text{Canadian dollar} } \\ &=& 115 \times 0.952 ~\text{U.S. dollars} \\ &=& 109.48 ~\text{U.S. dollars} \\ \hline \end{array} \)

     0.0256 = e^(.46t)

   e^(0.46)t=0.0256

lne^(0.46)t=ln0.0256

   0.46t*lne=ln0.0256         lne=1

         0.46t=ln0.0256          |:0.46

                t=ln0.0256/0.46

                t=-7,967745495...

0.0256 = e^(.46t) how to solve this equation ?? steps please

\(\begin{array}{|rcll|} \hline 0.0256 &=& e^{(0.46\cdot t)} \qquad & | \qquad ln() \\ \ln(0.0256) &=& 0.46\cdot t \qquad & | \qquad : 0.46 \\ \frac{ln(0.0256)}{0.46 } &=& t \\ t &=& \frac{ln(0.0256)}{0.46 } \\ t &=& \frac{-3.66516292750}{0.46 } \\ t &=& -7.96774549456 \\ \hline \end{array} \)

(3x-5)^2=9x^2-30x+25

-2-2=-4

15000*1.35^8 = 165486.1 correct to 7 significant digits.

used this website

http://www.thecalculatorsite.com/finance/calculators/compoundinterestcalculator.php

based on your words

answer is $16,698.65 

There are no real solutions. The two curves y = 3sqrt(3x+1) and y = 2sqrt(x-8) do not intersect.

Substituting x = -41/23 as  suggested by the previous answer gets you the square root of a negative quantity.

the answer is actuallty 25. Next time use the calculator.

No they are wrong.It is actually 25. Use the calculator to see if I'm right.

i found the answer dont w0rry it is 50

i found the answer dont w0rry it is 50

Greetings GingerAle,

Thank you very much.

Viele Grüße Heureka

Greetings GingerAle,

Thank you very much.

Viele Grüße Heureka

Greetings GingerAle,

Thank you very much.

Viele Grüße Heureka

30C5

\(\begin{array}{|rcll|} \hline && 30C5 \\ &=& \binom{30}{5} \\\\ &=& \dfrac{30!}{(30-5)!\cdot 5! } \\\\ &=& \dfrac{30!}{ 25! \cdot 5! } \\\\ &=& \dfrac{25!\cdot 26 \cdot27 \cdot 28 \cdot 29 \cdot 30}{25!\cdot 5! } \\\\ &=& \dfrac{ 26 \cdot27 \cdot 28 \cdot 29 \cdot 30}{ 5! } \\\\ &=& \dfrac{30}{5} \cdot \dfrac{29}{4} \cdot \dfrac{28}{3} \cdot \dfrac{27}{2} \cdot \dfrac{26}{1} \\\\ &=& \dfrac{30}{5} \cdot \dfrac{29}{1} \cdot \dfrac{28}{4} \cdot \dfrac{27}{3} \cdot \dfrac{26}{2} \\\\ &=& 6 \cdot 29 \cdot 7 \cdot 9 \cdot 13 \\\\ &=& \mathbf{142506} \\ \hline \end{array} \)

Press "2nd" in the top left hand corner. Then you will see "asin", which is the same as "inverse sin".

Press "2nd" in the top left hand corner. Then you will see "asin", which is the same as "inverse sin".

3a+2b a=-4 b=2

3*(-4)+2*2=-12+4=-8

x= -3 -x^2+6x-4 

\(x= -3 -x^2+6x-4 \\ 0= -3 -x^2+5x-4 \\ 0= -x^2+5x-7 \\ 0= x^2-5x+7 \\ \triangle=b^2-4ac=25-28=-3\\ since\;\;\triangle<0\;\;\text{there are no real solutions}\\~\\ \text{Note that the triangle is called the discriminant} \)

tan(4/5pi) =-0.7265425

tan^-1(=-0.7265425) =-pi/5

Learn to use the calculator here. If you have any problems, then ask for help.

294 / 210 x 10 =14 gallons of gas.

Area=Pi. r^2, r=radius

A=52^2 . 3.141592=8,494.86 sq.units- the area of the entire circle.

8,494.86 x 3/4 =6,371.15 sq. units - the area of 3/4 circle.

(1/4)^3 =1/64