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2^x*3^x=(2*3)^x=6^x

Please refrain from putting down other people. Just because a problem can be put into the calculator provided does not mean the concept is grasped. Sometimes people want to actually learn, can you blame them?

You sir, are a god. Congrats on finding a means to getting the magic number.

My brain hurts. You've had me here an hour Melody l'll get some sleep and figure it out then since it's been apparently proven through science we slove our problems best in our sleep. Also, l like to sleep. Gosh this is hard.

OK Melody, here is one way:

[100 - 9] x [ 4 - 1] =

    91      x      3    = 273

Here is my answer. I have also tried to give you some insight into how I went about it.

273

=300-27

=3*(100-9)

=(4-1)*(100-9)

hilo

No to the first question - yes to the second question.

Gee that was tricky!

No, it is a joke!!. The calculator has a limit of about 10^372 display. Your number of e^1,000,000 is a far, far bigger number and it says "infinity". Most calculators have limited display built into them. Your e^1,000,000 is a very large number=3.033215396802087... × 10^434,294. As you can see, it has 434,295 digits!!!.

\({e}^{-0.0246}≠-0.9757\)

\({e}^{-0.0246}≈0.9757001140283413\)

So true.

Yes 

What - you think a calculator cannot have a sense of humour?

obviosuly 50

(-1/4) * (-4) =

-1/4 * (-4/1) =

4/4 = 1

Take LOG of both sides:

LOG (e^(-.0246)) = LOG( .9757)

-.0246  LOG(e) = -.0106836              Divide both sides by -.0246

LOG(e)=.43429                                  Anti-log both sides :  10^(LOG(e)) = e    

e=2.71829

something you have too much of

Thanks guests

I don't remember where it came from. I asked it once before, a very long time ago. I got no responses.

I saw it in my watchlist and I just thought I'd ask again. :)

Ok I'll try

Thanks Tiggsy :/

864 n***a

You'll have to have the same denomintor to add or SUBTRACT fractions...

1 2/7 = 36/28

36/28  -  15/28 = 21/28 = 3/4

sqrt((sqrt(10)-3)^2)-sqrt((sqrt(10)-4)^2)

\({\color{red}\sqrt{(\sqrt{10}-3)^2 } -\sqrt{(\sqrt{10}-4)^2 } }\)

= \((\sqrt{10}-3) -(\sqrt{10}-4)\)

= \(\sqrt{10}-3 -\sqrt{10}+4 \)

\({\color{blue}=1}\)     !

the answer is .75 or 3/4 or 75%

KYS