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because pi is pi.

how do you graph (x-16)^2=(1/2)(y-8)?? Obviously this is a parabola and the vertex is (16,8) but where do I go from there?? What is the focus etc? How do I know what the rest of the points are on the graph? 

This is of the form

\((x-h)^2=4a(y-k)\\ h=16,k=8,a=1/8\\ (x-16)^2=4*\frac{1}{8}(y-8)\\ Vertex\;\;(16,8)\\ focal\; length =\frac{1}{8} \text { so focus is }(16,8.125)\\ Latus\;r****m\;is\; 4a=0.5\; units \;long\;\\\ \text{so the ends of the latus r****m are }(16-0.25,8.125)\;\;and\;\;(16+0.25,8.125)\\ \text{i.e. two more points on the graph are }(15.75,8.125)\;\;and\;\;(16.25,8.125)\\ \)

Here is the graph :)

Any questions?  Just ask. :)

70000 N/m^3 µɛ 

N= ‎kg ⋅ m ⋅ s^-2

\(70000  ‎kg ⋅ m ⋅ s^{-2}m^{-2} \times 132\;µɛ\; \times 24.66/56.5mm \times 3.14/2\\ 70000  ‎kg ⋅ s^{-2}m^{-1} \times 132\;µɛ\; \times \frac{24.66}{56.5mm} \times \frac{3.14}{2}\\ \frac{70000  ‎kg }{ s^{2}m} \times 132\;µɛ\; \times \frac{24.66}{0.0565m} \times 1.57\\ \frac{70000*1.57 *24.66*132\;µɛ\ ‎kg }{ 0.0565s^{2}m^2} \\ \frac{6331640496\;µɛ\ ‎kg }{ s^{2}m^2} \\ 6331640496\;µɛ\; ‎kg \;s^{-2}m^{-2}\\ 6331640496 ‎Nm^{-3}\;µɛ\;\\ 6.331640496\times 10^9 ‎Nm^{-3}\;µɛ\;\\ \text{I do not know what }\;µɛ\; \text{ symbol means but you probably do. }\)

70000*132*24.66/0.0565*3.14/2 = 6331640495.5752212389380531

its random or at the brotherhood of steel compund

its random or at the brotherhood of steel compund

Go consult the Steam forums, they will be able to give you better answers. 

Idk why are you asking that kind of question on a site meant for maths questions?

Im gunna agree with SomeoneSomewhere because that would just be plain bs if 0 had a value.

how you doin

You can't divide by zero, it has no value.

2, if you by 1/5 mean one fifth. 

Though upper and lower case, I suspect that probably the two v's are intended to be the same, in which case, separating the variables,

\(\displaystyle \frac{dv}{dt}=9.8-2v\),

\(\displaystyle \frac{dv}{9.8-2v}=dt\),

\(\displaystyle \int\frac{1}{9.8-2v}dv=\int dt\),

etc..

Alternatively, you could write the equation as

\(\displaystyle \frac{dv}{dt}+2v=9.8\)

and use the integrating factor technique,

(multiply throughout by exp(2t)).

Tiggsy.

Here is another magic number puzzle :)

1, 4, 8, 9, 75 and  100              Magic number is   273

Answers here:

"if a^9b^5-a^5b^9=505440 what is the value of a^2b?"

How about:

.

WOW

Heureka has found 10 more.   I am VERY impressed!

So that is 11 answers altogether !    

I doubt anyone can better that :)

Heureka, maybe you would like to post another puzzle for us ?

1, 4, 8, 9, 75 and  100              Magic number is   273

\(\begin{array}{|rcll|} \hline 273 &=& 100+\dfrac{8+9\cdot(1+75)}{4} \\\\ 273 &=& 75 + \dfrac{100\cdot (9-1) - 8 }{4} \\\\ 273 &=& 75 + \dfrac{1+8\cdot 100 -9 }{4} \\\\ 273 &=& 75 + 9\cdot \left ( \dfrac{100-8 }{4} - 1\right ) \\\\ 273 &=& 1+8\cdot ( 100-75+9) \\\\ 273 &=& 1+8+4\cdot (75-9) \\\\ 273 &=& 9 + 4\cdot(75-8-1) \\\\ 273 &=& 75 +\dfrac{8\cdot (100-1)}{4} \\\\ 273 &=& 1+ 8\cdot( 9 +\dfrac{100}{4}) \\\\ 273 &=& 4\cdot 75 \cdot \left( 1-\dfrac{9}{100} \right) \\\\ \hline \end{array}\)

(4+3x)(2-x)-2x^2=-5(x^2-4)

5 stars for your bruised brain  HSC.    

Just a little trivia :)

You know, where I live  HSC stands for Higher School Certificate which is a bit silly becasue there is no other school certificate :)

That is excellent guest :)

I did it exactly the same way.

I will now uncover my answer which may help people understand my thought processes.   

Number 5 doesn't even ADD UP!!!!! Sorry, friend!

I don't know if you will accept this:

[100 + 75] + 89 =237!

(30x^2-38x)(5x^2+2x-3)