There is no equal sign in your original question - it was a divide!
log2(n4)+5n=(n*log2(n))
\(log_2(n^4)+5n=(n*log_2(n))\\ log_2(n^4)+5n=log_2(n^n)\\ 5n=log_2(n^n)-log_2(n^4)\\ 5n=log_2(\frac{n^n}{ n^4 })\\ 5n=log_2(n^{n-4})\\ 2^{5n}=2^{log_2(n^{n-4})}\\ 2^{5n}=n^{n-4}\\ 32^n=n^{n-4}\\\)
Again, I suggest you have written the question down wrongly!