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Don't forget this one

Which points? 

ur welcome melody , it isnt nice of me but just the pain u take for all of us to write the day wrap ! 

ull do it like this ;

7 times means 7 x and negative 4 means (-4)

so ull solve it like this ;

7 x (-4)

= -28     

Thank you Rosala, that is really nice of you.   

read it ! its so nice melody that u take the initiative to write the day wrap everyday ! its so good ! i would like to give u a thumbs up for this , u r so nice u just take the pain to write it for all of us ! thank u melody ! thumbs up !

thumbs up from me !

oh i completey forgot about it !

Hi Rosala,

You can give reinout a thumbs up if you want to!

oh my god the second ones so funny ! 

@@ End of Day Wrap - Wednesday 28/5/14   Sydney, Australia   Time 20:10 am 

Hi everyone,

Another busy day with great answers from reinout-g, heureka, zegroes, Alan, admin, Caleb, chilledz3non, unknown GoldenLeaf, Kitty<3. Thank you everyone.

I thought that this comment by TreefAM was interestin.  TreefAM appears to have had a problem posting anonymously.  Maybe that is a part of the reason that so many new people are joining."Oh sorry it was 2^(x/2), had to make an acount because i wasn't able do to the spamm security thing."

I also want to remind everyone.  If you are happy with your answer post a thank you and give a thumbs up.  If you are not happy say so and ask for clarification.

--------------------------------------------------

I can't think of any other great pieces of news so I will go straight to the interesting posts.

A few of us had fun with this one. 

Take a look at this video

There is no question here.

cotx/(sinx.cosx)

$$\frac{cosx}{sinx}\div (sinxcosx)\\\\
=\frac{cosx}{sinx}\times \frac{1}{sinxcosx}\\\\
=\frac{1}{sin^2x}\\\\
=cosec^2x$$

7x-4 = -28

equals negative twenty-eight

Great one reinout!!!!!   ROF lol  

I've been laughing out loud for the last 5 minutes over this one!!!

You started in a very similar way like me and then someone came along with the

And now I'm totally lost by what you did next 

$$\begin{array}{rll}
4883.5&=&775(1+\frac{r}{12})^{12/4}\\\\
4883.5&=&775(1+\frac{r}{12})^3\\\\
\frac{4883.5}{775}&=&(1+\frac{r}{12})^3\\\\
\left(\frac{4883.5}{775}\right)^{1/3}&=&1+\frac{r}{12}\\\\
\left(\frac{4883.5}{775}\right)^{1/3}-1&=&\frac{r}{12}\\\\
12\times\left(\left(\frac{4883.5}{775}\right)^{1/3}-1\right)&=&r\\\\
r&=&12\times\left(\left(\frac{4883.5}{775}\right)^{1/3}-1\right)\\\\

\end{array}$$

$${\mathtt{12}}{\mathtt{\,\times\,}}\left({\left({\frac{{\mathtt{4\,883.5}}}{{\mathtt{775}}}}\right)}^{\left({\frac{{\mathtt{1}}}{{\mathtt{3}}}}\right)}{\mathtt{\,-\,}}{\mathtt{1}}\right) = {\mathtt{10.164\: \!489\: \!991\: \!486\: \!86}}$$

 If this is meant to be a compound interest answer then I think you made a mistake with how you used the formula!

All right so we have

$$3\frac{1}{3} = \frac{9}{3}+\frac{1}{3} = \frac{10}{3} = \frac{10*5}{3*5} = \frac{50}{15}$$

and

$$4\frac{4}{5} = \frac{20}{5}+\frac{4}{5} = \frac{24}{5} = \frac{24*3}{5*3} = \frac{72}{15}$$

Then

$$\frac{\frac{50}{15}}{\frac{72}{15}} = \frac{50}{72} = \frac{25}{36}$$

Reinout 

The answer is C=11, B=19 and L=70

1. 5C+2B+0.10L = 100    -> 50C+20B+L=1000
2. C+B+L=100

$$\boxed{(1) - (2) : 19B+49C=900 }$$

19B+49C=900

49C=900 mod 19

49C-2*19C=(900-47*19) mod 19

49C-38C=11C=7 mod 19

11C+19z=7

19z=7 mod 11

19z-1*11z=(7-0*11) mod 11

8z=7 mod 11

8z+11u=7

11u=7 mod 8

11u - 1*8u=(7-0*8) mod 8

3u=7 mod 8

3u+8v=7

8v=7 mod 3

8v-2*3v=(7-2*3) mod 3

2v=1 mod 3

2v+3w=1

3w=1 mod 2

3w - 1*2w=(1-0*2) mod 2

$$\boxed{w=1 \bmod 2 }$$

back:

w=1-2g    g is a integer

v:

2v+3w=1

2v+3(1-2g)=1

-> v=-1+3g

u:

3u+8v=7

3u+8(-1+3g)=7

-> u=5-8g

z:

8z+11u=7

8z+11(5-8g)=7

-> z=-6+11g

C:

11C+19z=7

11C+19(-6+11g)=7

-> C=11-19g

B:

19B+49C=900

19B+49(11-19g)=900

-> B=19+49g

L:

C+B+L=100

L=100-C-B

L=100-(11-19g)-(19+49g)

L=100-11+19g-19-49g

L=70-30g

The result is:

$$\boxed{C=11-19g\quad B=19+49g \quad L=70-30g}$$

C can't be negative so g must be 0:

g=0

C=11-19*0=11

B=19+49*0 =19

L=70-30*0 =70

$$\\\textcolor[rgb]{1,0,0}{C=11\quad
B=19\quad
L=70}$$

11*$5.00 + 19*$2.00 + 70*$0.10 = $55+$38+$7=$100

11+19+70=100

(3+4)w+(9+6)x+(3-12)y = 7w+15x-9y

whut?

I don't understand what you mean but let me give you some help on how you can write this down properly.

Click on the box 'LaTex Formula', write down \sqrt{} for the sq. root and put everything within the square root between the brackets. Wait for the thing to load and you'll have a brilliantly looking sq. root

(oh and use * for times)

Reinout

you need a value of t fo find y 

or a value of y to find t !