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That is an excellent explanation HSC   

5 - (-8) = 13

Yes this is greater than zero. Because the minus and (-8) multiply to make positive 8. Basically you're adding 5 and 8.

yup.

hello.

x=-2.6

Don't let the length of the problem get to you!

Focus on one term at a time, to reduce the risk of mistakes.

Let's take... 

(8p+2a−4)

Nothing you can really do here in terms of simplifying the term. So let's leave it alone.

Now we move on to...

− 2(2p−a+3)

Here we can distribute (-2) to the rest of the term your result:

-4p+2a-6

Now that we have both terms situatuted by simplifying we can just put the "like terms" together

(8p+2a−4) + (-4p+2a-6)

Match the "p," "a," and constants (numbers w/o the variable next to it):

8p + (-4p) = 4p

2a + 2a = 4a 

-4 + (-6) = -10

ln the end you will get:

4p + 4a - 10

Any additional questions?! Just ask!

2 sets of ordered pairs for 7x-8y=0

x=0, y= 0  (0,0)

x=8, y=7   (8,7)

It is undefined.

You cannot divide any number by 0

'those'   are typically  NOT 'THESE'            are you trying to learn English on a MATH FORUM????

Say she scored  50 % on the first two exams    that would   50   and 50

she scored 13% lower on the next 5            that would be    37  and 37  and 37 and 37 and 37

Add all of her scores and divide by the number of scores to find her NEW average

(50+50 + 37 + 37 + 37 +37 + 37 ) / 7    = 40.71      

She HAD a 50% average, now it has gone DOWN  to 40.71 %    Down  9.28% points.

Just pick ANY two numbers for 'x' and see what 'y' equals for those x's

let's pick    x= 2      and x= 3

for x= 2    4(2) - 6y=0

8-6y=0

8=6y

8/6 = 1 1/3 = y      so our first ordered pair is   (x,y) =  ( 2, 1 1/3 )

For x = 3

4(3) - 6y = 0

12 = 6y

12/6 = 2 = y       so our second ordered pair (x,y)    would be    (3,2)

Just USE the calculator !   9 x pi = 28.27433388.......

Remember, when dealing with exponents      (a^b)^c   =  a ^(b*c)

(5^(1/5))^5  = 5^(1/5  * 5)   = 5^1 = 5

You'll need to look at a periodic table to get all of the molecular weights

Mg=24.305                =24.305

N =14.007           x 2  =28.014                     (there are TWO N's in each molecule)

O=15.999            x 6  =  95.994                  (there are SIX O's in each molecule)

Total =                         =148.313

The FRACTION of this total that is Oxygen   is  95.994/148.313   of the total

99.994/148.313  x 860  = 556.63 grams of oxygen

2/3  /    1/2        when DIVIDING fractions, flip the BOTTOM one over and MULTIPLY

2/3   x   2/1   =  (2x2) / (3 x1)  =  4/3  =  1 1/3

-2 = 2(x-3)    First expand the right side

-2 = 2x - 6      Add 6 to both sides

4 = 2x             divide by 2

2=x

F=ma    First of all.

If 20 N are applied to the block   5 N are 'used' to overcome friction for a 'net' force of 15N applied to the block

15 N = 10 kg  x  a

15 kg m/sec^2 = 10 kg x a

15/10 = a    =  1 1/3  m/sec^2

how about 

7*8 = 7*4*2 = 28 doubled = 56

--------------------

I was very stubborn when I was a kid and I never learned my tables properly.

To muliply by 8 I always doubled then doubled again (I still use this method)

7*8 = 7, 14, 56 bingo!    LOL

sin^4 2 theta - 2 sin^2 2 theta = -1

\(sin^4 2 \theta - 2 sin^2 2 \theta = -1\\ (sin^2 2\theta)^2 - 2 (sin^2 2\theta )= -1\\ (sin^2 2\theta)^2 - 2 (sin^2 2\theta )+1=0\\ \text{let }x=sin^22\theta\\ x^2 - 2x+1=0\\ (x-1)(x-1)=0\\ x=+1\\ so\\ sin^22\theta=1\\ sin2\theta=\pm1\\ 2\theta=\frac{\pi}{2},\;\;\frac{3\pi}{2},.......\\ 2\theta=\frac{\pi}{2}+n\pi \qquad n\in Z\;\;(n \;is\;an\; integer)\\ \theta=\frac{\pi}{4}+\frac{n\pi}{2} \qquad n\in Z\\ \theta=\frac{\pi(1+2n)}{4} \qquad n\in Z\\ \)

check:

\(sin^4 2 \theta - 2 sin^2 2 \theta = -1\\ LHS\\ =\left(sin \frac{\pi(1+2n)}{2}\right)^4 - 2 \left(sin \frac{\pi(1+2n)}{2}\right)^2\\ =\left(\pm1\right)^4 - 2 \left(\pm1\right)^2\\ =1 - 2 *1\\ =-1\\ =RHS\)

check:

hai

\(\frac{1/4}{7/10} = 1/4\times10/7 =10/28 =5/14\)

3.2/2.4= (3 1/5)/(2 2/5)= (16/5)/(14/5)= 4/3*

*I left out the simplifying steps

1/5x8/9= 8/45

60/(4/5)=75