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To make a small vase, Elisa uses no more than 4.5 ounces a clay. Which compound inequality represents the number of ounces of clay, C, that Elisa uses to make on vase of either size? show work

A. 4.5<c<12

B. 4.5< c < 12

C. c<4.5 or c>12

D. c< 4.5 or c>12

Part your question appears to be missing but even it can only be one of these answers.

she uses 4.5 ounces or LESS to make the little vase

So it has to be     \(c\le 4.5 \quad or\;\: whatever\)

Work out the value of n.

1/32÷^3√2=2^n

Give your answer as an improper fraction.

Mmmm do you mean

1/32÷(cube root of 2)=2^n

\(\frac{1}{32}\div \sqrt[3]{2}=2^n\\ \frac{1}{2^5}\div 2^{1/3}=2^n\\ 2^{-5}\div 2^{1/3}=2^n\\ 2^{(-5-\frac{1}{3})}=2^n\\ 2^{(-5\frac{1}{3})}=2^n\\ n=-5\frac{1}{3}\)

\(n=\frac{-16}{3}\)

2*x - 9 = 15   | +9

2*x = 24    | /2

x = 12

Like this

YES of course, thanks guest :)

aah jea makes sense. Well, I guess i need to take another look into some basics :d 

Yes you can amnesia BUT

\([x^{1/3} + (x-16)^{1/3}]^{3}\ne x+(x-16)\)

think about this

\(8^{1/3}+125^{1/3}=2+5=7\\ so\\ [8^{1/3}+125^{1/3}]^3=7^3=343\\ but\\ [8^{1/3}]^3+[125^{1/3}]^3 = 8+125=133\\~\\ \)

343 not equal 133    ​

Cant I take every side ^3? I know the answer looked really simple but who knows ^^

err,sorry again...bad hair day   , b is indeed zero. More coffee needed.

typo error,apologies,    b does NOT equal 0,   -- co-efficient of b is zero.

If one root is 5i,then since complex roots occur in conjugate pairs, we have

quadratic  = (x-5i)(x+5i)  which is identical to ax^2 +bx +c

expanding left hand side and comparing co-efficients

x^2 +x(5i -5i) -25i^2    = ax^2 +bx +c

x^2 +x(0) +25               = ax^2 +bx =c

so a = 1    b=0  and c= 25

It is not that simple amnesia :)

The Pythagorean numbers are: 3, 4 and 5

The hypotenuse is 14

14 divided by 5 is 2.8

3 times 2.8 is 8.4
4 times 2.8 is 11.2

8,4² + 11,2² = 196

70,56 + 125,44 = 196

Good question AnimeLover :)

! sign in mathematics is called factorial.

Amnesia has explained very nicely how it is use :)  Thanks Amnesia :)

If you meant the web2 calculator, yes you can but I think that this is a better calc for graphing purposes. :)

It is the one that we all use here :)

Eq 1 (An identity has infinitely many solutions.)

start by taking the log on both sides of the equation.

lg5(5^x) = lg5(sqr(5))

x = 1/2

Let one solution of a quadratic function be x=5i. Find the quadratic function. What is the "C" value of the quadratic.

\(0=k(ax^2+bx+c)\\ \)

\(x = {-b + \sqrt{b^2-4ac} \over 2a}=5i\\ so\;\;b=0\\ { + \sqrt{-4ac} \over 2a}=5i\\ { +2 \sqrt{-ac} \over 2a}=5i\\ \sqrt{-ac}=5ai\\ -ac=-25a^2\\ c=25a\\ \)

I can effectively ignore the k because it will not change the relationship between a and c

There is probably a much quicker way to to this. :/

More interesting

Look here:

your asking a simple question that can be answered through the CALCULATOR on the site that your on bruh

Well since u only said its a triangle i will think its a right triangle: (otherwise i got no idea)

Since you only have one side given a and b will always variety.

To get a fixed size we can use the pythagoras:

a^2 + b^2 = c^2

a^2 + b^2 = 14^2.     I -a^2

b^2 = 196 - a^2

and

a^2 = 196 - b^2

Example:

U want the size for b when a is 4:

b^2 = 196 - 4^2

b = 13.42

! is like sigma just for multiplication.

example:

3! = 3*2*1