All Answers 356085 Answers

what is b?

b=260cos41

\(rad\)

\(b=260\times cos \ 41 = -26.708\)

\(deg\)

\(b=260 \times cos 41°=196.224\)

  !  I have no idea why this is double here.

its fine :)

what is b?

b=260cos41

\(rad\)

\(b=260\times cos \ 41 = -26.708\)

\(deg\)

\(b=260 \times cos 41°=196.224\)

  !

what is 1,760,000/360,000?

\(\frac{1,760,000}{360,000}=4.\overline{88}\)

  !

The principal value is always between \(0^{\circ} - 90^{\circ}\)

So 84.3\(^{\circ}\) is definitely the correct answer.

The principal value is

arc cos 0.1 = 84.3°

but also

cos -635.7° ≈ 0.1

cos -275.7° ≈ 0.1

cos 84.3° ≈ 0.1

cos 444.3° ≈ 01

  !

I guess that's your version of geometric proofs.

In our country, for number 7, we have to write '\(\text{corr. }\angle \text{s, }\cong\triangle\text{s}\)'. It means 'corresponding angles of congruent triangles'.

2. \(\overline{SV}\parallel\overline{TU}\)

3. \(\overline{SV}=\overline{TU}\)

7. \(\text{CPCTC}\)

8. \(\text{def. of parallelogram}\)

You just type 6v into the calculator on this site.

Note that you can't do this on your own calculator. LOL

~The smartest cookie in the world.

Maybe we could name the 4th power.

How about 'tesseracted'? LOL

Hello 'student'.

\(7\div \dfrac{7}{3}\\ =7\times \dfrac{3}{7}\\ = 3\)

\(\boxed{\color{BurntOrange}{\dfrac{a}{b}\div\dfrac{d}{c}}\color{black}{=}\color{BurntOrange}\dfrac{a}{b}\color{red}{\times \dfrac{c}{d}}}\)

Inverse cos is the same as arc cos

Use   acos   etc

Pretty good :)

Thank you all of you (Chris, Alan, herueka, EP, and Guest #1)

1.

\({5^{-1}}\times {5^3}\div {5^0}\)

2.

\({5^{-3}}\div 1\)

3.

\(1\over {5^3}\)

4.

\(1\over 125\)

Alternative Form

\(0.008\)

Yes ...   What you going to do about it ??       

Yes....always.......

Hey...don't get smart with me, young lady......!!!!

Thanks for the points :))

Don't you play with Desmos?  It is not that hard and it is fun making these diagrams.

I think Geogebra is harder, it is less intuitive especially when you are new at it.   :/

P.S.  ......I'd never figure out how you did this...but...it should be worth more than 5 points....!!!

Thanks Chris,

Yes, took forever but I can use Desmos a little better now :))

It is fun drawing these pics and this one was a bit of a challenge.

I tried to come up with that distance without Wolfram|alpha but I couldn't get the numbers to fall out.  

I guess I was doing something wrong....... :(

Neat, Melody....that was a lot of work.....!!!!

Hi Chris,

Did you just know 

"2^2 + 3^2 + 5^2 + 7^2 + 11^2 + 13^2 + 17^2  =  666 =  sum of the squares of the 1st seven primes...!!!"

Or did you google it?       

I think you knew it your have always been fascinated with 666