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yes melody ur right , i am having the same feeling because one question can have different right answers ! isnt it !

Thanks for the help guys!! i see where i went wrong now. 

thanl u very much melody ! im happy so idont know why but i want to give a thumbs up ! thank u !

OR the asker could mean;

$$3\sqrt{27}\times6\\\\
=3\times 3\sqrt3\times6\\\\
=54\sqrt3\\\\
\approx 93.53$$

$${\frac{{\mathtt{0.09}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{9}}} = {\mathtt{0.000\: \!000\: \!6}}$$

OR

$${\frac{{\mathtt{0.09}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{9}}}$$

$${\frac{{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{0.09}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{4}}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{9}}}$$

$${\mathtt{0.06}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{5}}}$$

$$6\times 10^{-2} \times 10^{-5}\\

6\times 10^{-7}\\

0.0000006$$

Matrix A:
( 1,  1,  1,  1,  1,

  0,  1,  3,  2,  0, 

  1,  1,  0,  5,  1,

  0,  0,  1, -4,  2)

Matix A: toReducedRowEchelonForm
( 1,  0,  0,  -9,  0,

  0,  1,  0, 14,  0,

  0,  0,  1,  -4,  0,

  0,  0,  0,   0,  1)

Thanks Alan,

This is a present value of an ordinary annuity problem.

This is another way that you  can do it.

A=$10791

R=207

i=0.129/12=0.01075

find n (number of months)

$$\begin{array}{rll}
10791&=&R\times \left[\frac{1-(1+i)^{-n}}{i}\right]\\\\
10791&=&207\times \left[\frac{1-(1+0.01075)^{-n}}{0.01075}\right]\\\\
10791&=&207\times \left[\frac{1-(1.01075)^{-n}}{0.01075}\right]\\\\
(10791*0.01075/207)-1&=&-(1.01075)^{-n}\right]\\\\
1-(10791*0.01075/207)&=&(1.01075)^{-n}\right]\\\\
2.274806518&=&1.01076^n\\\\
ln2.274806518&=&ln1.01076^n\\\\
ln2.274806518&=&n\times ln1.01076\\\\
\frac{ln2.274806518}{ln1.01076}&=&n\\\\
n&=&\frac{ln2.274806518}{ln1.01076}\\\\
n&=&76.79\\\\
&=&\mbox{77 months}\\\\
&=&\mbox{6 years and 5 months}\\\\
\end{array}$$

$$\vec{v} = \begin{pmatrix}-5\\7 \end{pmatrix}

\| v\| = \sqrt{(-5)^2+7^2}= \sqrt{25+49}= \sqrt{74} \approx 8.60$$

A very nice offer from NinjaDevo

Do you want to know know how to put a fraction into the calculator?

look at this thread

$$2x^2+9x+5=0$$

or if you need to do it by hand you use the quadratic formula

It is just

2nd then atan

arc tan is the same as inverse tan

That is very sweet Rosala.  I am sure that Andre will be pleased.

That is the cutest picture ever!

It depends what is meant by the question Rosala.

2x1 doesn't make make a lot of sense.  It can be interpreted as 2 multiplied by 1 like I did 

or

it can be interpreted as 2x*1 which is 2x as our anonymous friend did.

I really think that something was left out of the question.

Hi,

welcome to the forum!

with  $${\sqrt{\left({\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right){\mathtt{\,\times\,}}{\mathtt{x}}}} = \left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\sqrt{{\mathtt{x}}}}$$ your input is equal to:

$${\sqrt{{\mathtt{x}}}}{\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\sqrt{{\mathtt{x}}}} = {\mathtt{30}}$$

$${\sqrt{{\mathtt{x}}}}{\mathtt{\,\times\,}}\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right) = {\mathtt{30}}$$

$${\sqrt{{\mathtt{x}}}} = {\frac{{\mathtt{30}}}{{\mathtt{1.5}}}}$$

$${\sqrt{{\mathtt{x}}}} = {\mathtt{20}}$$

x = 20^2 = 400

Rom, I think that you have made an error.

Dominic paid $18.90 plus some more.

They each have to pay 1/3 each.  It is easier to think of this as 3/9 each.

But Bob pays 4/9  and Clement pays 5/9

bob pays 3/9 for himself and 1/9 for Dominic.  Clement pays 3/9 for himself and 2/9 for Dominic.

This means that Dominic owes Bob 1/9 of the total and Clement 2/9 of the total

Dominic repays $18.90 to Clement.  This represents 2/9 of the total.

So 1/9 of the total must be 18.90/2 = $9.45

So the whole cost must have been $9.45*9=$85.05

Hi Melody,

(log(sqrt(10)+1))^2=

log(sqrt(10)+1)^2

These are different questions and the second one is incorrect.

What result would you expect?

Rom , could u just tell me that how did u know that Clement paid 1/3 of the cost of gift!and what use of the ratio 4:5 did u make ! i cant makeout how did u solve this question !

oh thats not good zegroes , uve chastised Lady Guinevere , thats really bad and now ur calling her a thief ! hoooaaaa ! ha ha !i hope she doesnt punishes u ! lol!

Clement paid $18.90 which was 1/3 of the cost of the gift.

The gift costs 3x$18.90=$56.70

Sorry 6,6,12,35,38,66,104.

What about 6,12,35,38,66,104 to make -912?

melody , i think anonymous is right because as there is 5x so 2x can also be the same ! but anonymous i think ur way wasnt a bit correct !

(5x+4)+(2x1)

so i assume this will be done like this ,

5x-4+2x

=5x+2x-4

=7x-4

so thats the answer but if that 2"x" is really multiplication sign or a variable , then pls let me know !

(5x+4) + (2x1) = 

*5x + 2x = 7x*

* 7x + 4 x 1 = *

ANSWER:

7x + 4

$$5x+4+2*1=5x+4+2=5x+6$$

Was this your intended question or should there be a + or a - in the second bracket?