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the answer is 4.

Here: New link: https://discord.gg/N9HFZnG

This one doesnt expire :)

Its not working. help :(

No, Its the class you should take after you finish watching breaking bad.

Yes, I'll set it to never expire, does that sound good? :)

The invite expired. is there another way to join?

Hey Cheyenne!! I'm good!! And yourself??🙃

Click the "login" button on the top right corner, then click "forgot your password?". Its below the "Password" field. You can return to your old account.

Here's the balanced equation:

2Fe₂O₃ + 6CO → 4Fe + 6CO₂

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\(y = a8^{x} \\ \frac{y}{a} = 8^{x} \\ (\frac{y}{a})^{\frac{1}{x}} = (8^{x})^{\frac{1}{x}} \\ (\frac{y}{a})^{\frac{1}{x}} = 8 \\ \frac{1}{x}ln(\frac{y}{a}) = ln(8) \\ \frac{1}{x}= \frac{ln(8)}{ln(\frac{y}{a})} \\ x = \frac{ln(\frac{y}{a})}{ln(8)}\)

Hey! Are you really just in 8th grade?

You're really really smart !!  I had no clue about trig in the 8th grade...

I wanted to add to your explanation about sine.

To find the sin of the angle that a line from the origin to a specific point makes with the x-axis...a point like this (4, 7) :

1. Find the distance from the point to the origin. This is the radius.

2. Divide the y coordinate, in this case 7, by that distance.

Dividing by the radius scales the length down to unit circle measures.

For this one, use the Pythagorean theorem or distance formula (same thing really) to find that the radius = \(\sqrt{65}\)

And the sine of the angle that a line from the origin to this point makes with the x-axis = \(\frac{7}{\sqrt{65}}\)

If the radius is already = 1, then just get the y-coordinate of the point! :)

Also... to find the sin if an angle is given, exactly what you said works but I think you want to start at the right-most point on the circle. On a clock, that's 3:00. In a unit circle, that is the point (1, 0). Then go counter-clockwise. 

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I assume that we have this ??

y  = a(b)^x

y = a(8)^x       divide both sides by a

(y / a)  =  (8)^x         take the log of both sides

log( y /a )  = log 8^x      and we can write

log ( y / a)   =  x * log 8     divide both sides by log 8

log ( y / a)  / log 8   = x       swap x and y

log ( x / a) / log 8  =  y        and for y,  write f^-1 ( x)

f^-1(x)  =   log ( x / a) / log 8

D.  a < 0

e^x  is always positive  ....so.....  (negative)(positive)  =  negative

5^(2)  /  5^(-3)        remember that   a^(-b)  =  1 / a^b     so we have

5^2  /  ( 1 / 5^3)    invert the second fraction and multiply

5^2  *  (5^3)  / 1          using  a^m * a^n  =    a^(m + n)

5^5  /  1   =

5^5

SA = 2πr²  + 2πrh

Subtract 2πr² from both sides of the equation.

SA - 2πr² = 2πrh

Divide through by 2πr .

SA/(2πr) - r = h

Great.

1580*(1+.0008)^36  ≈  1626.15

Yeah you right you right 

but it dont say for 23 hours straight

Using the identity  :   C(m, n) + C(m, n + 1)   = C(m + 1, n + 1), we have

C(5,0) + C(5,1) + C(6,2)  + C(7,1) + C(8,3) + C(9,2) + C(10,4) + C(11,3)

C(6,1)  + C(6,2)  + C(7,1) + C(8,3) + C(9,2) + C(10,4) + C(11,3)

C(7,2)  +  C(7,1) + C(8,3) + C(9,2) + C(10,4) + C(11,3)

C(7,1)  +  C(7,2) + C(8,3) + C(9,2) + C(10,4) + C(11,3)

C(8,2) + C(8,3)  + C(9,2) + C(10,4)  + C(11,3)

C(9,3)  + C(9,2)  + C(10,4)  + C(11,3)

C(9,2) +C(9,3) + C(10,4) + C(11,3)

C(10,3) + C(10,4)  + C(11,3)

C(11,4) + C(11,3)

C(11,3) + C(11,4)

C(12,4)  =  

495 

Lol...If he hit golfballs for 23 hours straight, that leaves him only 1 hour to sleep!