All Answers 358087 Answers

Its next to the the 2ND buttom, looks like this \(\Pi \)

Present Population =8,484

Future Population =?

FP =PP x (1 + i)^N

FP =8,484 x 1.025^12

FP =8,484 x 1.344889.......

FP =11,410 Projected population of the town in 12 years.

Notice the pattern in the following sums:

1*1!+ 2*2!,+3*3! =23

1*1!+ 2*2!,+3*3! + 4*4! =119

1*1!+ 2*2!,+3*3! + 4*4! + 5*5! =719

Notice that the answer in each case is next number factorial - 1. In other words, the 23 is 4! - 1, and the 119 is 5! - 1, and the 719 is 6! - 1. And this pattern holds true for any sequence of such numbers.

Therefore, the sum of your sequence up to 99*99! = 100! - 1. This is the exact answer to your problem.

Use the net to find the surface of the cylinder Length 7 cm Width 9 cm

I do not use a net and use this formula:

\(A=\frac{1}{2}\pi w^2+\pi w l=\pi w(\frac{w}{2}+l)\)

\(A=\pi\cdot 9cm(\frac{9cm}{2}+7cm)=\pi \cdot103.5\ cm^2\)

\(A=325.155\ cm^2\)

\( The \ surface \ of \ the \ cylinder \ is \ 325.155\ cm^2.\)

  !

\(-6 = -\frac1{w+5}\)

Multiply both sides of the equation by (w + 5) .

-6(w + 5) = -1

Divide both sides of the equation by -6 .

w + 5 = 1/6

Subtract 5 from both sides of the equation.

w = 1/6 - 5

Get a common denominator and combine the fractions.

w = 1/6 - 30/6 = -29/6

We want the equation of a line that has a slope of 6.1 and passes through the point (45, 2274.5) ......here, the fuel = x, and the weight of the plane = y

That will be:

y - 2274.5 = 6.1(x - 45)

We could put this into slope intercept form, but it isn't necessary. We just want to know what y is when x = 72. Plug in 72 for x and solve for y.

y - 2274.5 = 6.1(72 - 45)

y = 6.1(72 - 45) + 2274.5 = 2439.2 pounds

3 over 25

what does square root do?

The square root of a number is a number which, multiplied by itself, returns the original number.

\(\large \sqrt{324}=18\\\large \ 18\times 18=324\)

  !

original price = p

p - 0.27p = $ 219

0.73p = $ 219

p = $ 219 / 0.73

p = $ 300

the number that is more is -29

2 is the amswer

How do you calculate arc length given radius and central angle measure?

\(\large arc=\pi\cdot r\cdot\frac{\alpha}{180°}\)

\(\pi=3.1415926535897932\)

  !

80,080= 8.008 * 10 to the power of 4

                                       or

                                 4   

                             10

What information do you have to work with?

Are you given the area or circumference or something like that? 

\(\frac{117}{x}=\frac{144}{100}\)

Now just solve for x.

\(117=x\cdot\frac{144}{100} \\~\\ 117\cdot\frac{100}{144}=x \\~\\ \frac{11700}{144}=x \\~\\ 81.25=x\)

117 is 144% of 81.25

Thx  @hectictar this assignment is practice for my STARR so I appreciate the help.

(I may keep asking other questions so stay alert brp)

We want to solve this equation for x.

x² + x - 6 = -4

Add 4 to both sides.

x² + x - 2 = 0

Factor.

(x + 2)(x - 1) = 0

Set each factor = 0 and solve for x.

x + 2 = 0       and       x - 1 = 0

x = -2            and       x = 1

Which is b) 

\((\frac47)^{-2}=\frac{4^{-2}}{7^{-2}}=\frac{7^2}{4^2}=\frac{7*7}{4*4}\)

And...   \(\frac{7*7}{4*4}=\frac{49}{16}\)  :)

The mean of this list of numbers = \(\frac{60+31+24+50+44+88}{6}=\frac{297}{6}=49.5\)