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Two of the parallel sides of the plane will each equal NP  = 6

The  other two parallel sides will each equal PU  =  sqrt ( 6^2 + 15^2)  =  sqrt (36 + 225) =

sqrt ( 261)

So.....the perimeter  of NPUR  =  2 [ 6 + sqrt (261) ] ≈ 44.3 ft

This is it, thank you! =)

Forgot I was adding 5 instead of subtracting 5! 

5/(1+x) = 3 – 4/(x-1)

Answer is suppost to be

x1 = -0,21

x2 = 3,21

Where did I go wrong? :D

$\frac{5}{1+x}=3-\frac{4}{x-1}$

$\frac{5}{1+x}+\frac{4}{x-1}=3$

$\frac{5x-5+4+4x}{x^2-1}=3$

${9x-1}=3x^2-3$

$3x^2-9x-2=0$

$x^2-3x-\frac{2}{3}=0$

$x_1=1.5+\sqrt{2.25+\frac{2}{3}}$

$x=1.5\pm\sqrt{2.91\overline{66}}$

$x_1=3.2078\\x_2=-0.2078$

                !

Solve for x:
5/(x + 1) = 3 - 4/(x - 1)

Bring 3 - 4/(x - 1) together using the common denominator x - 1:
5/(x + 1) = (3 x - 7)/(x - 1)

Cross multiply:
5 (x - 1) = (x + 1) (3 x - 7)

Expand out terms of the left hand side:
5 x - 5 = (x + 1) (3 x - 7)

Expand out terms of the right hand side:
5 x - 5 = 3 x^2 - 4 x - 7

Subtract 3 x^2 - 4 x - 7 from both sides:
-3 x^2 + 9 x + 2 = 0

Divide both sides by -3:
x^2 - 3 x - 2/3 = 0

Add 2/3 to both sides:
x^2 - 3 x = 2/3

Add 9/4 to both sides:
x^2 - 3 x + 9/4 = 35/12

Write the left hand side as a square:
(x - 3/2)^2 = 35/12

Take the square root of both sides:
x - 3/2 = sqrt(35/3)/2 or x - 3/2 = -sqrt(35/3)/2

Add 3/2 to both sides:
x = 3/2 + sqrt(35/3)/2 or x - 3/2 = -sqrt(35/3)/2

Add 3/2 to both sides:
Answer: | x = 3/2 + sqrt(35/3)/2         or          x = 3/2 - sqrt(35/3)/2

thankyou so much this helped a lot 

Hey, Rosie! I'm doing great, what about you?  One thing I have planned for summer break is going to Utah to visit my mom's side of the family.

Now, here's a question for you. What do you like to do in your spare time and what are you planning to do this week or next week?

Stay Awesome!

-MagikalRedNiteTiger

Hey, Rosie, is that your favorite cat? And, thanks for spreading the positivity.

Stay Awesome!

-MagikalRedNiteTiger

Ah right!

Thank you once again!

It's an OYSTER Rosie!

Thanks!

Note that  1  = 3^0    ....so we have

3^(2 - 2x)  =  3^0      since the bases are the same, we can solve for the exponents

2 - 2x  = 0        add 2x to both sides

2  = 2x             divide both sides by 2

1  = x

I ma in 3rd grade and I can do this problem it's sqrt(2)*8 because 128 is 2^8. it is 8sqrt2

An

O - Y - S - T - E - R........!!!!!

OYSTER

Thanks for that, Rosy.......!!!!

Note  what happens when we expand   (x + 0.5) ( x - 6.5)

Distribute the terms in the first set of parentheses over the terms in the second set

x ( x - 6.5)  +  0.5 ( x - 6.5)   =

x^2  - 6.5x  + 0.5x - 3.25        combine like terms

x^2  - 6x  -  3.25

Now just apply the (-4/13)  over these to get the final function

Hope that helps and lemme know if you need anything else.

Press [MODE] and put the calculator in SEQ mode. To highlight an item in the Mode menu, use the arrow keys to place the cursor on the item, and then press [ENTER]. Highlight SEQ in the fifth line to put the calculator inSequence mode. 

To cite my source I used google 

Aight cool, thanks!

Just one last question, where does the 6x come from?

Isn't 2x*0,5 just 1? :o 

Note that   g(x)  =  - 2  / (-x - 3) +5    can be written as   g(x)  =  - 2  / - (x + 3) + 5 =  

2 / (x + 3)  + 5

The   (x + 3)  part  shifts the graph of   1/x   to the left by 3 units

The "2"   vertically stetches the parent graph by a factor of 2

Additionally, the "+5"  shifts the parent graph up 5 units 

So  putting all these together......the parent function is shited to the left by 3 untis, up by 5 units and vertically stretched by 2 units

See  the graphs of   1/x  , 2/x , 2/ (x + 3) and  2 /( x + 3) + 5  here : 

https://www.desmos.com/calculator/sxufnzobpv

I just want to know how to use the "sequence mode" in a regular calc.. :/

thanks