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29.17mm

Well no one knows exactly. Just try live life in the moment and not think to much a bout the past and future.😊

Juan pedro=life

Assuming that 'lg' means 'log' (either base 10 or base 2):

3 lg( x )  =  lg( x³ )

So, the equation becomes  3 lg( x )  =  lg( 10 )     --->     lg( x³ )  =  lg( 10 )     --->     x³  =  10

                                                                                                                         --->       x  =  cuberoot( 10 )

You randomly select the first person and then choose every nth person after that.

For example, if you want to randomly choose a group of sophomores in a high school: get a list of the names of all the sophomores, randomly choose a number from 1 to 10 (choose that person) and then choose every 10^th name after the first person. (Modify how many are chosen by how many you want in your random group.

I don't believe that you can get more work out than what you put in; so, in an ideal situation, you might get the output work to be as large as the input work (answer B).

You can lift more output weight by increasing the distance of the input weight (the lighter person on a teeter-totter sits farther away from the center (the fulcrum) than the heavier person) and you can increase the distance the lighter weight moves by using a heavier weight at a shorter distance; but, in both cases, the output work is no greater than the input work.

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Thank you!

Permutation: A set of objects in which position (or order) is 
important=nPr=68P5=1,250,895,360
Combination: A set of objects in which position (or order) is NOT 
important.=nCr=68C5=10,424,128

The answer is "D"

how you do this is you plug the number x equals into the equation.

When x=4, the inequality looks like this: 4 + 4 < 2(4) - 3

Simplify: 8<5

So when x=4, the statement is false.

When x=-2, the inequality looks like this: -2 + 4 < 2(-2) - 3

Simplify: 2 < -7

So when x=-2, the statement is false

Do those steps over for x=7 and x=9.

Look up each individual word in the online Dictionary here:

http://www.dictionary.com/

Take the integral:
 integral(2000 x^2014 + 14)/(x^2015 - x) dx
For the integral (2000 x^2014 + 14)/(x^2015 - x), write (2000 x^2014 + 14)/(x^2015 - x) as (2000 x^1999 + 14/x^15)/(x^2000 - 1/x^14):
 = integral(2000 x^1999 + 14/x^15)/(x^2000 - 1/x^14) dx
For the integrand (2000 x^1999 + 14/x^15)/(x^2000 - 1/x^14), substitute u = x^2000 - 1/x^14 and du = (2000 x^1999 + 14/x^15) dx:
 = integral1/u du
The integral of 1/u is log(u):
 = log(u) + constant
Substitute back for u = x^2000 - 1/x^14:
 = log((x^2014 - 1)/x^14) + constant
Which is equivalent for restricted x values to:
Answer: | = log(1 - x^2014) - 14 log(x) + constant

5.63 is the answer

9022624

yes i do

(126/100)/2 + 5

= 63/100 + 5

= 5.63

Want to see my baby BOI

I tried that but I quit after a while, so I switched to pc and I'm more confused

\(\frac{m}{m-n}-12 \\ m = -4 \quad n = -5 \\ \frac{-4}{-4-5}-12 = \frac{-4}{-9}-12 = \frac{-104}{9}\)

It is -1898 you n00b

Use a

Why is 2x, 3x and 4x  not on the arcs ?

You cannot work out actual distances when you are not given any actural distance.

I don't think so anyway.  

Do you want the distance answers in terms of the radius?

1999

\(\frac{3}{4}\times x=28\\ \frac{3}{4}\times x\times \frac{4}{3}=28\times \frac{4}{3}\\ x=28\times \frac{4}{3}\\\)

You can finish it :)