I don't know that i can draw the picture. maybe I could but it would take me a while
The radii of the 2 circles join to form a kite. The equal angles are 90 degrees.
The long sides are 20cm and the two short sides are 15cm. Using pythagoras it is clear that the axis of symmentry is 25cm.
Consider the angle between the axis of symmetry and the 20 cm side. Let this angle be theta.
theta = atan(15/20)
So this arc is subtended from an angle 2*atan(15/20)
so the area of this sector (in the larger circle) is [2*atan(15/20)/360]*pi*20^2
The area of the triangle is 0.5*20*20*sin[2*atan(15/20)]
So the area of the small segment of the large circle is
{[2*atan(15/20)/360]*pi*20^2}-{0.5*20*20*sin[2*atan(15/20)]}
Then you go through the same process for the smaller circle and add the 2 bits together.
See - I am not so stupid afterall!
