All Answers 356722 Answers

This is the formula you would use to find the FV of your savings plan.

FV=P{[1 + R]^N - 1/ R}

FV =$100 x {[1 + 0.02/12]^(4*12) - 1 / (0.02/12)}

FV=$4,992.90 - This should be the balance in the savings plan after 4 years.

P.S. Do the math in the above formula and you should get the same answer that I did.

1 with 1000000000000 zeroes after it. Remember: \(10^n\) = 1 with \(n\) zeroes after it. 

Not sure, but... for the 120 case, I guess it's 239? {120, 1, 1..., 1, 1}? Anyway, ask CPhill.

This is the formula you would use to find the FV of the IRA at 65.

FV=P{[1 + R]^N - 1/ R}

FV =$75 x {[1 + 0.07/12]^(40*12) - 1 / (0.07/12)}

FV =$196,861.00 - This is what the balance in the IRA should be after 40 years.

Total deposits should be =$75 x 40 years x 12 months =$36,000

$196,861 - $36,000 =$160,861 was interest earned over 40-year period.

P.S. Do the math in the above formula and you should get the same answer that I got!!.

I'll do as many of the second question as I can....some are hard to tell

y = -(2/3)x^4   appears to be  "i"

y =  (1/2)x^-5  the half-graph appears to be "a"

y = 2x^1/4    don't see one that appears to match this one

y =  - x^5/3    don't see one that appears to match this one

y = -2x^2    "j"  is the one that seems to match this one

y = 1.7x^2/3     "d"  is the one that seems to match this one

An actor invested some money at 9 % simple  interest, and $41,000

more than three times the amount of 11%. The total annual interest earned from the investment was $47,350.

How much did he invest at each amount?

Let the amount that he invested @ 11% =A

Then the amount he invested @ 9% =3A + $41,000

11%A + 9%(3A + $41,000) =$47,350

0.11A + 0.27A + $3,690 = $47,350

0.38A +$3,690 = $47,350         Subtract $3,690 from both sides

0.38A = $47,350 - $3,690

0.38A = $43,660                            Divide both sides by 0.38

A = $43,660 / 0.38

A = $114,894.74 money invested @ 11%

$114,894.74 x 3  +  $41,000 =$385,684.22 money Invsted @ 9%

I was expecting it to come as even dollars, but it didn't unless I fouled something!!.

P  =  1.14F + 18.31     and     10 ≤ F ≤ 75

The question is.....what value of  F  causes  P  to be  85  ?

Plug in  85  for  P  and solve for  F .

85  =  1.14F + 18.31         Subtract  18.31  from both sides.

66.69  =  1.14F         Divide both sides by  1.14 .

58.5  =  F                  This is between  10  and  75 , so it is a possible value for  F .

The hood must have a flow rate of about  59  liters per second.

Thanks, Melody.

2nd question:

If you plug the equations into this calculator:

If you plug the equations into this calculator:

oh, ok :)

Malis verbis meis...

There was the first one that was multiple choice, but then there is a picture under that question which contains a graph and a list of functions. That picture is a question of its own.

I assume you mean this question:

This is the formula you would use to find the FV of your deposits:

FV=P{[1 + R]^N - 1/ R}

FV=250 x {[1 + 0.04/12]^18 - 1 / (0.04/12)}

FV=250 x {[1.0033333]^18 - 1 /  (0.0033333)}

FV=250 x {[1.0617306] - 1  /(0.0033333)}

FV=250 x {[0.0617306]  /  (0.0033333)}

FV=250 x                       18.5191810...........

FV=$4,629.80 - Savings balance after 18 months @ 4% comounded monthly.

Which of the following exhibit inverse variation?

A) The distance traveled as a function of speed.

speed  =  distance / time

A bigger number for the distance causes a bigger number for the speed.     not inverse

B) The total cost as a function of the number of items purchased.

As the number of items purchased goes up, the total cost goes up.     not inverse

C) The area of a circular swimming pool as a function of its radius.

A bigger radius causes a bigger area.     not inverse

D) The number of posts in a 20ft fence as a function of distance between posts.

As the distance between posts gets larger, the number of posts gets smaller.

As the distance between posts gets smaller, the number of posts gets larger.

This is an inverse relationship.

\(\frac{-2(5x^3y^2)^2}{10xy}\)

Fisrt, distribute the square.

\(\frac{-2(25x^6y^4)}{10xy}\)

Distirbute the -2.

\(\frac{-50x^6y^4}{10xy}\)

Consider that a variable without a power is the same as that variable to the power of 1: x = x¹

If a variable  with a power is divide by the same variable with a lower power, the powers subtract: x⁶/x³=x^6-3=x³

Simplify.

-50/10=-5

\(\frac{-5x^6y^4}{x^1y^1}\)

Subtract powers.

\(-5x^5y^3\)

Как дела?

When I thought a and b were ordinary pronumerals I believed this question to be nonsense.

If a and b were pronumerals then I would have been correct BUT a and b are directional vectors so it is my answer that is nonsense. So at this point in time I will delete it. 

Thanks Tiggsy and Heureka and CPhill for the correction.  

 [ (3.8) * 10^2] *  [ 5.9 * 10^12 ]  =  

(3.8)(5.9) * (10^2)(10^12)  =

22.42  *  10^14  = 

2.242 x  10^15   miles

Как дела?

Thanks, GA....didn't think of a permutation.....!!!

(5x^2-7x+5) - (9x^2-10x+1) =

5x^2 - 9x^2  - 7x + 10x  + 5 - 1  =

-4x^2 + 3x + 4

I think you want to find an angle that has the cosine value of 4/10

We can use the cosine inverse for this

arccos (4/10)  ≈  66.42°

Converting this to  D-M-S  we have

.42°  =  (.42*60) minutes =  25.2 minutes

.2 minutes  = ( .2* 60 ) seconds  = 12 seconds

So 

66.42°  =  66° 25' 12"