1 * 1012 = n( 4 * 104)
We want to solve this for n . That is the number of times 1 * 1012 is greater than 4 * 104
Divide both sides of the equation by 4 * 104 .
\(\frac{1*10^{12}}{4*10^4}\) = n
Reduce the fraction by 104 .
\(\frac{1*10^{8}}{4}\) = n
\(\frac{10^{8}}{4}\) = n
\(\frac{1}{4}\) * 108 = n
0.25 * 108 = n
n = 25 000 000