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We are talking about a VERY large number here....there are thousands of possibilities....without knowing the starting a1  and the  r of the series and where in the series you are, it could be almost anything.....were you given any more information...or multiple choices?

I will assume that is a 95 %   (and not something like 95 out of 150 !)     ~Well done !

(but in math you should always include UNITS  )

Thank you very much for your answer this has made it alot clearer. All it takes is someone to just explain it.

Thank you x

The domain is all the possible x values

and

The range is all the range is all the posible y vlues.

You can often get it just by looking at or thinking about the curve.

Sometimes you must look at the eqation and look at what values x or y can, or cannot take.

-----------------

for instance

y-2 =1/x

You cannot divide by 0 so x is not zero

so the domain is all real x where x is not equal to 0      

\(Domain:\:x\in R\;\;where\;\; \:x\ne0\;\;\)

1 divided by anything is not equal to 0 so y-2 is not equal to 0 so    y is not equal to 2

\(Range:\:y\in R\;\;where\;\; \:y\ne2\;\;\)

So x=0 and y=2 are the asymptotes of this hyperbola.

\(\frac{3x - 7}{x + 1}\)

The domain  will include all real numbers except x  =  -1

So.....

(-inf, -1)   U  (-1, inf )

I understood it much better now! Thanks so much, CPhill! 

First one

0 is not in the domain

-1 is not in the domain

-1/2 is not in the domain

The sum of these   is   -3/2

Since AB  = AC, then

Angle ABC  = angle ACB

And since BD = BC

Then Angle BDC  = Angle DCB

But DCB  = ACB

So....triangles   ABC  and  BDC  are similar

Call angle ABC  = 2theta

But since ABC is bisected, then  DBC  is also  = theta

And angle DBC  = angle BAC  = theta

Then...in triangle ABC

Angle ABC + Angle ACB  + Angle BAC  = 180

2theta + 2theta + theta  = 180

5theta  = 180

theta  = 36°=  BAC   = "Angle A "

Fair enough all though for the record if you look at the time between my question before this one and the last, you'll see that it is not over night. I you made you self a member I can send you the same message I sent to others about what the group is about...remember they do have an off topic post for a reason. I have plans and none of them are bad. I want to engage people make them laugh, I mean come on, even the greatest nerds can say they'd prefer math to *fill in the blank*. Okay not true there are some people out there but for instance, how cool would a joke thread be to have. Or have topics of the day to discuss. Things like that. How does that sound bad.

Maybe you do, but you are a big target. You have many posts on here defining what you are. People do not change overnight. Start posting something useful then we will all see that you are not all hot farts. 

Fine you can do whatever you want but you honestly don't make yourself look anybetter by attacking me. If you were the guest on my last post then you have now twice come after me when I genuinely want to help.

So you act like a big di ck for over a year, and now you are saying you just want to be a little di ck.  Well, until I see you shrink up a little, I’m reserving judgment for your di ck size. 

What are you going to "isolate" g from, since every term has a "g'' in it?? All you can do is simplify the expression:

Simplify the following:

(3 g)/(g^3 - 9 g)

Factor g out of g^3 - 9 g:

(3 g)/(g (g^2 - 9))

(3 g)/(g (g^2 - 9)) = g/g×3/(g^2 - 9) = 3/(g^2 - 9):

3/(g^2 - 9)

g^2 - 9 = g^2 - 3^2:

3/(g^2 - 3^2)

Factor the difference of two squares. g^2 - 3^2 = (g - 3) (g + 3):

3 / ((g - 3) (g + 3))

But I'm saying this because I think it's funny how even though I really do try to do something good it's the one time someone ever bashes me. But when I do other things, no one says anything I mean come on is that not even a little funny.

Maybe someone is dunking the donut. Giving yourself a point for every donut crumb you drop isn’t what this forum is about. 

That's a nice way to see this, guest.....!!!!

Um, 2 users above posted the solution. No need to say that.